Chapter A.1, Problem 117AYU

To determine

To find: The value of the expression $2x^3-3x^2+5x-4$ if $x=2$ and if $x=1$.

Answer to Problem 117AYU

10, 0

Explanation of Solution

If $x=2$,

$2x^3-3x^2+5x-4=2{\left(2\right)}^3-3{\left(2\right)}^2+5\left(2\right)-4=16-12+10-4=10$

If $x=1$,

$2x^3-3x^2+5x-4=2{\left(1\right)}^3-3{\left(1\right)}^2+5\left(1\right)-4=2-3+5-4=0$