The value of 2 A + B and 4 A − B .

Question

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Answer 1

Question

Chapter A, Problem A.1P

To determine

The value of 2A+B and 4A−B.

Expert Solution & Answer

Answer to Problem A.1P

The value of (2A+B) is [41805].

The value of (4A−B) is [812−613].

Explanation of Solution

Given:

A=[25−13].

B=[082−1].

Calculation:

Calculate the value of (2A+B).

Substitute [25−13] for A and [082−1] for B.

2A+B=2[25−13]+[082−1]=[410−26]+[082−1]=[4+010+8−2+26+−1]=[41805]

Calculate the value of (4A−B).

Substitute [25−13] for A and [082−1] for B.

(4A−B)=4[25−13]−[082−1]=[820−412]−[082−1]=[8−020−8−4−212−(−1)]=[812−613]

Conclusion:

The value of (2A+B) is [41805].

The value of (4A−B) is [812−613].

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Answer 2

Question

Chapter A, Problem A.1P

To determine

The value of 2A+B and 4A−B.

Expert Solution & Answer

Answer to Problem A.1P

The value of (2A+B) is [41805].

The value of (4A−B) is [812−613].

Explanation of Solution

Given:

A=[25−13].

B=[082−1].

Calculation:

Calculate the value of (2A+B).

Substitute [25−13] for A and [082−1] for B.

2A+B=2[25−13]+[082−1]=[410−26]+[082−1]=[4+010+8−2+26+−1]=[41805]

Calculate the value of (4A−B).

Substitute [25−13] for A and [082−1] for B.

(4A−B)=4[25−13]−[082−1]=[820−412]−[082−1]=[8−020−8−4−212−(−1)]=[812−613]

Conclusion:

The value of (2A+B) is [41805].

The value of (4A−B) is [812−613].

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Answer 3

Question

Chapter A, Problem A.1P

To determine

The value of 2A+B and 4A−B.

Expert Solution & Answer

Answer to Problem A.1P

The value of (2A+B) is [41805].

The value of (4A−B) is [812−613].

Explanation of Solution

Given:

A=[25−13].

B=[082−1].

Calculation:

Calculate the value of (2A+B).

Substitute [25−13] for A and [082−1] for B.

2A+B=2[25−13]+[082−1]=[410−26]+[082−1]=[4+010+8−2+26+−1]=[41805]

Calculate the value of (4A−B).

Substitute [25−13] for A and [082−1] for B.

(4A−B)=4[25−13]−[082−1]=[820−412]−[082−1]=[8−020−8−4−212−(−1)]=[812−613]

Conclusion:

The value of (2A+B) is [41805].

The value of (4A−B) is [812−613].

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Answer 4

Question

Chapter A, Problem A.1P

To determine

The value of 2A+B and 4A−B.

Expert Solution & Answer

Answer to Problem A.1P

The value of (2A+B) is [41805].

The value of (4A−B) is [812−613].

Explanation of Solution

Given:

A=[25−13].

B=[082−1].

Calculation:

Calculate the value of (2A+B).

Substitute [25−13] for A and [082−1] for B.

2A+B=2[25−13]+[082−1]=[410−26]+[082−1]=[4+010+8−2+26+−1]=[41805]

Calculate the value of (4A−B).

Substitute [25−13] for A and [082−1] for B.

(4A−B)=4[25−13]−[082−1]=[820−412]−[082−1]=[8−020−8−4−212−(−1)]=[812−613]

Conclusion:

The value of (2A+B) is [41805].

The value of (4A−B) is [812−613].

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Answer 5

Chapter A, Problem A.1P

To determine

The value of 2A+B and 4A−B.

Expert Solution & Answer

Answer to Problem A.1P

The value of (2A+B) is [41805].

The value of (4A−B) is [812−613].

Explanation of Solution

Given:

A=[25−13].

B=[082−1].

Calculation:

Calculate the value of (2A+B).

Substitute [25−13] for A and [082−1] for B.

2A+B=2[25−13]+[082−1]=[410−26]+[082−1]=[4+010+8−2+26+−1]=[41805]

Calculate the value of (4A−B).

Substitute [25−13] for A and [082−1] for B.

(4A−B)=4[25−13]−[082−1]=[820−412]−[082−1]=[8−020−8−4−212−(−1)]=[812−613]

Conclusion:

The value of (2A+B) is [41805].

The value of (4A−B) is [812−613].

Answer 6

Chapter A, Problem A.1P

To determine

The value of 2A+B and 4A−B.

Expert Solution & Answer

Answer to Problem A.1P

The value of (2A+B) is [41805].

The value of (4A−B) is [812−613].

Explanation of Solution

Given:

A=[25−13].

B=[082−1].

Calculation:

Calculate the value of (2A+B).

Substitute [25−13] for A and [082−1] for B.

2A+B=2[25−13]+[082−1]=[410−26]+[082−1]=[4+010+8−2+26+−1]=[41805]

Calculate the value of (4A−B).

Substitute [25−13] for A and [082−1] for B.

(4A−B)=4[25−13]−[082−1]=[820−412]−[082−1]=[8−020−8−4−212−(−1)]=[812−613]

Conclusion:

The value of (2A+B) is [41805].

The value of (4A−B) is [812−613].

Answer 7

Chapter A, Problem A.1P

To determine

The value of 2A+B and 4A−B.

Answer 8

Expert Solution & Answer

Answer to Problem A.1P

The value of (2A+B) is [41805].

The value of (4A−B) is [812−613].

Answer 9

Expert Solution & Answer

Answer 10

Expert Solution & Answer

Answer 11

Explanation of Solution

Given:

A=[25−13].

B=[082−1].

Calculation:

Calculate the value of (2A+B).

Substitute [25−13] for A and [082−1] for B.

2A+B=2[25−13]+[082−1]=[410−26]+[082−1]=[4+010+8−2+26+−1]=[41805]

Calculate the value of (4A−B).

Substitute [25−13] for A and [082−1] for B.

(4A−B)=4[25−13]−[082−1]=[820−412]−[082−1]=[8−020−8−4−212−(−1)]=[812−613]

Conclusion:

The value of (2A+B) is [41805].

The value of (4A−B) is [812−613].

Answer 12

Ch. A - Prob. A.1P Ch. A - Prob. A.2P Ch. A - Prob. A.3P Ch. A - Prob. A.4P Ch. A - Prob. A.5P Ch. A - Prob. A.6P Ch. A - Prob. A.7P Ch. A - Prob. A.8P Ch. A - Prob. A.9P Ch. A - Prob. A.10P

The value of 2 A + B and 4 A − B .

The value of 2A+B and 4A−B.

Answer to Problem A.1P

Explanation of Solution

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Chapter A Solutions