The derivative of the error function erf ( x ) and complementary error function erfc ( x ) .

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Answer 1

Question

Chapter A, Problem 52E

(a)

To determine

The derivative of the error function erf(x) and complementary error function erfc(x).

(b)

To determine

To show: The equation y=e−x2−2x∫x∞e−t2dt is a solution of the differential equation y″+2xy′−2y=0.

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Answer 2

Question

Chapter A, Problem 52E

(a)

To determine

The derivative of the error function erf(x) and complementary error function erfc(x).

(b)

To determine

To show: The equation y=e−x2−2x∫x∞e−t2dt is a solution of the differential equation y″+2xy′−2y=0.

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Answer 3

Question

Chapter A, Problem 52E

(a)

To determine

The derivative of the error function erf(x) and complementary error function erfc(x).

(b)

To determine

To show: The equation y=e−x2−2x∫x∞e−t2dt is a solution of the differential equation y″+2xy′−2y=0.

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Answer 4

Question

Chapter A, Problem 52E

(a)

To determine

The derivative of the error function erf(x) and complementary error function erfc(x).

(b)

To determine

To show: The equation y=e−x2−2x∫x∞e−t2dt is a solution of the differential equation y″+2xy′−2y=0.

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Answer 5

Chapter A, Problem 52E

(a)

To determine

The derivative of the error function erf(x) and complementary error function erfc(x).

(b)

To determine

To show: The equation y=e−x2−2x∫x∞e−t2dt is a solution of the differential equation y″+2xy′−2y=0.

Answer 6

Chapter A, Problem 52E

(a)

To determine

The derivative of the error function erf(x) and complementary error function erfc(x).

Answer 7

Chapter A, Problem 52E

(a)

To determine

The derivative of the error function erf(x) and complementary error function erfc(x).

Answer 8

(b)

To determine

To show: The equation y=e−x2−2x∫x∞e−t2dt is a solution of the differential equation y″+2xy′−2y=0.

Answer 9

(b)

To determine

To show: The equation y=e−x2−2x∫x∞e−t2dt is a solution of the differential equation y″+2xy′−2y=0.

Answer 10

Expert Solution & Answer

Answer 11

Expert Solution & Answer

Answer 12

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Answer 13

Ch. A - In Problems 1 and 2 evaluate the given quantity....Ch. A - Prob. 2E Ch. A - Prob. 3E Ch. A - Prob. 4E Ch. A - Prob. 5E Ch. A - Prob. 6E Ch. A - Prob. 7E Ch. A - Prob. 8E Ch. A - Prob. 9E Ch. A - Prob. 10E

The derivative of the error function erf ( x ) and complementary error function erfc ( x ) .

Solution Summary: The author explains the derivatives of the error function erf(x) and complementary error functions.

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The derivative of the error function erf(x) and complementary error function erfc(x).

To show: The equation y=e−x2−2x∫x∞e−t2dt is a solution of the differential equation y″+2xy′−2y=0.

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Chapter A Solutions