That the given relation is true ∫ 0 π 2 sin m θ cos n θ d θ = Γ ( m + 1 2 ) Γ ( n + 1 2 ) 2 Γ ( m + n + 2 2 ) , m > − 1 , n > − 1

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Answer 1

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Chapter A, Problem 38E

To determine

To show: That the given relation is true

∫0π2sinmθcosnθdθ=Γ(m+12)Γ(n+12)2Γ(m+n+22),m>−1,n>−1

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Answer 2

Question

Chapter A, Problem 38E

To determine

To show: That the given relation is true

∫0π2sinmθcosnθdθ=Γ(m+12)Γ(n+12)2Γ(m+n+22),m>−1,n>−1

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Answer 3

Question

Chapter A, Problem 38E

To determine

To show: That the given relation is true

∫0π2sinmθcosnθdθ=Γ(m+12)Γ(n+12)2Γ(m+n+22),m>−1,n>−1

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Answer 4

Question

Chapter A, Problem 38E

To determine

To show: That the given relation is true

∫0π2sinmθcosnθdθ=Γ(m+12)Γ(n+12)2Γ(m+n+22),m>−1,n>−1

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Answer 5

Chapter A, Problem 38E

To determine

To show: That the given relation is true

∫0π2sinmθcosnθdθ=Γ(m+12)Γ(n+12)2Γ(m+n+22),m>−1,n>−1

Answer 6

Chapter A, Problem 38E

To determine

To show: That the given relation is true

∫0π2sinmθcosnθdθ=Γ(m+12)Γ(n+12)2Γ(m+n+22),m>−1,n>−1

Answer 7

Chapter A, Problem 38E

To determine

To show: That the given relation is true

∫0π2sinmθcosnθdθ=Γ(m+12)Γ(n+12)2Γ(m+n+22),m>−1,n>−1

Answer 8

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Answer 9

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Answer 11

Ch. A - In Problems 1 and 2 evaluate the given quantity....Ch. A - Prob. 2E Ch. A - Prob. 3E Ch. A - Prob. 4E Ch. A - Prob. 5E Ch. A - Prob. 6E Ch. A - Prob. 7E Ch. A - Prob. 8E Ch. A - Prob. 9E Ch. A - Prob. 10E

That the given relation is true ∫ 0 π 2 sin m θ cos n θ d θ = Γ ( m + 1 2 ) Γ ( n + 1 2 ) 2 Γ ( m + n + 2 2 ) , m > − 1 , n > − 1

Solution Summary: The author explains that the given relation is true, and the gamma function is defined as, cB(x,y)=Gamm

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To show: That the given relation is true

∫0π2sinmθcosnθdθ=Γ(m+12)Γ(n+12)2Γ(m+n+22),m>−1,n>−1

Want to see the full answer?

Chapter A Solutions

That the given relation is true ∫ 0 π 2 sin m θ cos n θ d θ = Γ ( m + 1 2 ) Γ ( n + 1 2 ) 2 Γ ( m + n + 2 2 ) , m &gt; − 1 , n &gt; − 1

Solution Summary: The author explains that the given relation is true, and the gamma function is defined as, cB(x,y)=Gamm

Concept explainers

Videos

To show: That the given relation is true ∫0π2sinmθcosnθdθ=Γ(m+12)Γ(n+12)2Γ(m+n+22),m>−1,n>−1

Want to see the full answer?

Chapter A Solutions

That the given relation is true ∫ 0 π 2 sin m θ cos n θ d θ = Γ ( m + 1 2 ) Γ ( n + 1 2 ) 2 Γ ( m + n + 2 2 ) , m > − 1 , n > − 1

To show: That the given relation is true

∫0π2sinmθcosnθdθ=Γ(m+12)Γ(n+12)2Γ(m+n+22),m>−1,n>−1