Explanation Procedure used: Synthetic Division: To divide the polynomial by x − c : 1. Arrange the polynomial in descending powers, with a 0 coefficient for any missing term. 2. Write c for the divisor x − c . To the right, write the coefficients of the dividend. 3. Write the leading coefficient of the dividend on the bottom row. 4. Multiply c times the value just written on the bottom row. Write the product in the next column in the second row. 5. Add the values in this new column, writing the sum in the bottom row. 6. Repeat the series of multiplication and additions until all columns are filled in. 7 Use the numbers in the last row to write the quotient, plus the remainder above the divisor. The degree of the first term of the quotient is one less than the degree of the first term of the dividend. The final value in this row is the remainder. Calculation: The given expression is 3 x 4 − 5 x 3 − 21 x 2 + 17 x + 25 x − 3 . Use synthetic division to find the quotient and remainder when 3 x 4 − 5 x 3 − 21 x 2 + 17 x + 25 is divided by x − 3 . Here x − 3 is the divisor which is of the form x − c and hence c = 3 . Use synthetic division for the expression 3 x 4 − 5 x 3 − 21 x 2 + 17 x + 25 x − 3 as follows

Elementary & Intermediate Algebra with Access Code

3rd Edition

ISBN: 9780321915139

Author: Michael III Sullivan

Publisher: PEARSON

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Chapter A, Problem 17E

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To solve: The expression 3x4−5x3−21x2+17x+25x−3 using synthetic division.

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Chapter A, Problem 16E

Chapter A, Problem 18E

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Chapter A Solutions

Elementary & Intermediate Algebra with Access Code

Ch. A - True or False We can divide 4x3 + 5x2 + 10x 3 by...Ch. A - Prob. 2E Ch. A - Prob. 3E Ch. A - Prob. 4E Ch. A - Prob. 5E Ch. A - Prob. 6E Ch. A - Prob. 7E Ch. A - Prob. 8E Ch. A - Prob. 9E Ch. A - In Problems 9-22, divide using synthetic division....

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The expression 3 x 4 − 5 x 3 − 21 x 2 + 17 x + 25 x − 3 using synthetic division.

Solution Summary: The author explains how to divide the polynomial by x-c using synthetic division.

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To solve: The expression 3x4−5x3−21x2+17x+25x−3 using synthetic division.

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Chapter A Solutions