DEVELOP.MATH(3 VOLS) CUSTOM-W/MML <IC<
16th Edition
ISBN: 9781323235911
Author: BITTINGER
Publisher: Pearson Custom Publishing
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Chapter A, Problem 112ES
To determine
To fill: The blank space in theprovided table,
Object |
Yards (yd) |
Centimeters (cm) |
Inches (in.) |
Meters (m) |
Millimeters (mm) |
Thickness of a piece of cardboard |
0.23 |
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1. Matrix Operations
Given:
A = [ 33 ]A-[3-321]
-3
B = [342]B-[3-41-2]
(a) A² A2
Multiply A× A:
-3
=
(3 x 32x-3) (3 x 22 x 1)
| = |[19–63
|-9-3 -6+21] =
A² = 33 33 1-3×3+1x-3) (-3×2+1x1)
[12]A2=[3-321][3-321]=[(3×3+2x-3)(-3×3+1x-3)(3×2+2×1)(-3×2+1×1)]=[9-6-9-36+2-6+1
]=[3-128-5]
(b) | A ||A| Determinant of A
| A | (3 × 1) (2 x-3)=3+ 6 = 9|A|=(3×1)-(2x-3)=3+6=9
(c) Adjoint of A
Swap diagonal elements and change sign of off-diagonals:
A = [33], so adj (A) = |¯²]A=[3-321], so adj(A)=[13–23]
-3
(d) B-¹B-1
First find | B ||B|:
|B | (3x-2)- (1 × -4) = -6 + 4 = −2|B|=(3x-2)-(1x-4)=-6+4=-2
Then the adjoint of B:
adj (B) = [²
3
adj(B)=[-24-13]
Now,
B-1
1
=
|B|
· adj (B) = 1 [²¯¯³¹³] = [2₂ B
0.5
|B-1=|B|1-adj(B)=-21[-24-13]=[1-20.5-1.5]
2.
(a) Matrix Method: Solve
(2x + 3y = 6
(2x-3y=14
{2x+3y=62x-3y=14
Matrix form:
22 33-22
=
[223-3][xy]=[614]
Find inverse of coefficient matrix: Determinant:
| M | (2x-3) - (3 x 2) = -6 -6 = -12|M|=(2x-3)-(3×2)=-6-6=-12
Adjoint:
adj(M) = [3]adj(M)-[-3-2-32]
So…
Let the region R be the area enclosed by the function f(x)= = 3x² and g(x) = 4x. If the region R is the
base of a solid such that each cross section perpendicular to the x-axis is an isosceles right triangle with a
leg in the region R, find the volume of the solid. You may use a calculator and round to the nearest
thousandth.
y
11
10
9
00
8
7
9
5
4
3
2
1
-1
-1
x
1
2
Using the accompanying Accounting Professionals data to answer the following questions.
a. Find and interpret a 90% confidence interval for the mean years of service.
b. Find and interpret a 90% confidence interval for the proportion of employees who have a graduate degree.
view the Accounting Professionals data.
Employee Years of Service Graduate Degree?1 26 Y2 8 N3 10 N4 6 N5 23 N6 5 N7 8 Y8 5 N9 26 N10 14 Y11 10 N12 8 Y13 7 Y14 27 N15 16 Y16 17 N17 21 N18 9 Y19 9 N20 9 N
Question content area bottom
Part 1
a. A 90% confidence interval for the mean years of service is
(Use ascending order. Round to two decimal places as needed.)
Chapter A Solutions
DEVELOP.MATH(3 VOLS) CUSTOM-W/MML <IC<
Ch. A - Use the unit below to measure the length of each...Ch. A - Prob. 2DECh. A - Prob. 3DECh. A - Prob. 4DECh. A - Prob. 5DECh. A - Prob. 6DECh. A - Prob. 7DECh. A - Prob. 8DECh. A - Prob. 9DECh. A - Prob. 10DE
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