
Construct and interpret a confidence interval for the true difference between the two population means.

Answer to Problem 12CR
Solution:
The confidence interval is
Explanation of Solution
Given Information:
A business person wants to determine how much faster the return trip from Dallas to Atlanta is than the initial trip from Atlanta to Dallas. He records the times for his next seven flights to and from Dallas and obtains the following data. Assuming that both population distributions arc approximately normal and the variances of the two populations are not the same.
Atlanta to Dallas | Dallas to Atlanta |
1 h 49 min | 1 h 32 min |
1 h 51 min | 1 h 23 min |
2 h 03 min | 1 h 38 min |
1 h 47 min | 1 h 26 min |
1 h 53 min | 1 h 30 min |
2 h 01 min | 1 h 19 min |
1 h 45 min | 1 h 28 min |
Formula used:
When the standard deviations of both the populations are unknown and assumed to be unequal, the samples taken are independent of each other and the population distribution are approximately normal, then the margin of error is calculates as,
Where
And
The number of degrees of freedom for the t-distribution is given by the smaller of the values
Then, the confidence interval for the difference between two population means for independent data sets is given by
or
Where
Calculation:
Atlanta to Dallas | Dallas to Atlanta |
109 min | 92 min |
111 min | 83 min |
123 min | 98 min |
107 min | 86 min |
113 min | 90 min |
121 min | 79 min |
105 min | 88 min |
Let the length of time the flight takes from Atlanta to Dallas be sample 1 and the length of time the flight takes from Dallas to Atlanta be sample 2.
For the population whose population variances are unequal, the t –distribution is applied for the minimum degree of freedom .i.e. the minimum of
Hence the degree of freedom is 6.
It is given that the level of confidence is 0.90 then the level of significance is,
Then,
The mean is calculated as,
Where
And n is the total number of observations.
Th mean of the sample 1 is calculated as,
The standard deviation is calculated as,
The standard deviation of sample 1 be
Substitute 112.71 for
The mean of the sample 2 is calculated as,
The standard deviation of sample 2 be
Substitute 88 for
The margin of error is calculated as,
Substitute
The confidence interval is,
Substitute 112.71 for
Conclusion:
Both the end points are coming out to be positive that is the difference of the mean is also positive that is the length timing from Atlanta to Dallas is more than the length timing from Dallas to Atlanta so the flight from Dallas to Atlanta is faster.
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Chapter 9 Solutions
Beginning Statistics, 2nd Edition
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