PRECALCULUS W/LIMITS:GRAPH.APPROACH(HS)
PRECALCULUS W/LIMITS:GRAPH.APPROACH(HS)
8th Edition
ISBN: 9781337904285
Author: Larson
Publisher: CENGAGE L
Question
Book Icon
Chapter 9.7, Problem 5E

(a)

To determine

To graph: the polar equation and identify the conic

(a)

Expert Solution
Check Mark

Answer to Problem 5E

The given equation is Parabola

  PRECALCULUS W/LIMITS:GRAPH.APPROACH(HS), Chapter 9.7, Problem 5E , additional homework tip 1

Explanation of Solution

Given:

  e=1

  r=2e1+ecosθ

Calculation:

Conic sections: Eccentricity

If e=1; conic is parabola.

If e=0 , conic is circle.

If e<1, conic is an ellipse

If e>1, conic is hyperbola.

Here, the eccentricity is e=1

The given equation is parabola.

  PRECALCULUS W/LIMITS:GRAPH.APPROACH(HS), Chapter 9.7, Problem 5E , additional homework tip 2

Conclusion:

The given equation is Parabola

(b)

To determine

To graph: the polar equation and identify the conic

(b)

Expert Solution
Check Mark

Answer to Problem 5E

The given equation is ellipse

  PRECALCULUS W/LIMITS:GRAPH.APPROACH(HS), Chapter 9.7, Problem 5E , additional homework tip 3

Explanation of Solution

Given:

  e=0.5

  r=2e1+ecosθ

Calculation:

If e=1; conic is parabola.

If e=0 , conic is circle.

If e<1, conic is an ellipse

If e>1, conic is hyperbola.

Here, the eccentricity is e=0⋅5 ;

The given equation is ellipse

  PRECALCULUS W/LIMITS:GRAPH.APPROACH(HS), Chapter 9.7, Problem 5E , additional homework tip 4

Conclusion:

The given equation is ellipse

(c)

To determine

To graph: the polar equation and identify the conic the given equation is hyperbola

(c)

Expert Solution
Check Mark

Answer to Problem 5E

  PRECALCULUS W/LIMITS:GRAPH.APPROACH(HS), Chapter 9.7, Problem 5E , additional homework tip 5

Explanation of Solution

Given:

  e=1.5

  r=2e1+ecosθ

Calculation:

Here, the eccentricity is e=1.5

Therefore, the given equation is hyperbola

  PRECALCULUS W/LIMITS:GRAPH.APPROACH(HS), Chapter 9.7, Problem 5E , additional homework tip 6

Conclusion:

Therefore, the given equation is hyperbola

Previous
Chapter 9.7, Problem 4E
Next
Chapter 9.7, Problem 6E

Chapter 9 Solutions

PRECALCULUS W/LIMITS:GRAPH.APPROACH(HS)

Ch. 9.1 - Prob. 1ECh. 9.1 - Prob. 2ECh. 9.1 - Prob. 3ECh. 9.1 - Prob. 4ECh. 9.1 - Prob. 5ECh. 9.1 - Prob. 6ECh. 9.1 - Prob. 7ECh. 9.1 - Prob. 8ECh. 9.1 - Prob. 9ECh. 9.1 - Prob. 10E
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Prob. 47ECh. 9.7 - Prob. 48ECh. 9.7 - Prob. 49ECh. 9.7 - Prob. 50ECh. 9.7 - Prob. 51ECh. 9.7 - Prob. 52ECh. 9.7 - Prob. 53ECh. 9.7 - Prob. 54ECh. 9.7 - Prob. 55ECh. 9.7 - Prob. 56ECh. 9.7 - Prob. 57ECh. 9.7 - Prob. 58ECh. 9.7 - Prob. 59ECh. 9.7 - Prob. 60ECh. 9.7 - Prob. 61ECh. 9.7 - Prob. 62ECh. 9.7 - Prob. 63ECh. 9.7 - Prob. 64ECh. 9.7 - Prob. 65ECh. 9.7 - Prob. 66ECh. 9.7 - Prob. 67ECh. 9.7 - Prob. 68ECh. 9.7 - Prob. 69ECh. 9.7 - Prob. 70ECh. 9.7 - Prob. 71ECh. 9.7 - Prob. 72ECh. 9.7 - Prob. 73ECh. 9.7 - Prob. 74ECh. 9.7 - Prob. 75ECh. 9.7 - Prob. 76ECh. 9.7 - Prob. 77ECh. 9.7 - Prob. 78ECh. 9.7 - Prob. 79ECh. 9.7 - Prob. 80ECh. 9.7 - Prob. 81ECh. 9.7 - Prob. 82ECh. 9.7 - Prob. 83ECh. 9 - Prob. 1CRCh. 9 - Prob. 2CRCh. 9 - Prob. 3CRCh. 9 - Prob. 4CRCh. 9 - Prob. 5CRCh. 9 - Prob. 6CRCh. 9 - Prob. 7CRCh. 9 - Prob. 8CRCh. 9 - Prob. 9CRCh. 9 - Prob. 10CRCh. 9 - Prob. 11CRCh. 9 - Prob. 12CRCh. 9 - Prob. 13CRCh. 9 - Prob. 14CRCh. 9 - Prob. 15CRCh. 9 - Prob. 16CRCh. 9 - Prob. 17CRCh. 9 - Prob. 18CRCh. 9 - Prob. 19CRCh. 9 - Prob. 20CRCh. 9 - Prob. 21CRCh. 9 - Prob. 22CRCh. 9 - Prob. 23CRCh. 9 - Prob. 24CRCh. 9 - Prob. 25CRCh. 9 - Prob. 26CRCh. 9 - Prob. 27CRCh. 9 - Prob. 28CRCh. 9 - Prob. 29CRCh. 9 - Prob. 30CRCh. 9 - Prob. 31CRCh. 9 - Prob. 32CRCh. 9 - Prob. 33CRCh. 9 - Prob. 34CRCh. 9 - Prob. 35CRCh. 9 - Prob. 36CRCh. 9 - Prob. 37CRCh. 9 - Prob. 38CRCh. 9 - Prob. 39CRCh. 9 - Prob. 40CRCh. 9 - Prob. 41CRCh. 9 - Prob. 42CRCh. 9 - Prob. 43CRCh. 9 - Prob. 44CRCh. 9 - Prob. 45CRCh. 9 - Prob. 46CRCh. 9 - Prob. 47CRCh. 9 - Prob. 48CRCh. 9 - Prob. 49CRCh. 9 - Prob. 50CRCh. 9 - Prob. 51CRCh. 9 - Prob. 52CRCh. 9 - Prob. 53CRCh. 9 - Prob. 54CRCh. 9 - Prob. 55CRCh. 9 - Prob. 56CRCh. 9 - Prob. 57CRCh. 9 - Prob. 58CRCh. 9 - Prob. 59CRCh. 9 - Prob. 60CRCh. 9 - Prob. 61CRCh. 9 - Prob. 62CRCh. 9 - Prob. 63CRCh. 9 - Prob. 64CRCh. 9 - Prob. 65CRCh. 9 - Prob. 66CRCh. 9 - Prob. 67CRCh. 9 - Prob. 68CRCh. 9 - Prob. 69CRCh. 9 - Prob. 70CRCh. 9 - Prob. 71CRCh. 9 - Prob. 72CRCh. 9 - Prob. 73CRCh. 9 - Prob. 74CRCh. 9 - Prob. 75CRCh. 9 - Prob. 76CRCh. 9 - Prob. 77CRCh. 9 - Prob. 78CRCh. 9 - Prob. 79CRCh. 9 - Prob. 80CRCh. 9 - Prob. 81CRCh. 9 - Prob. 82CRCh. 9 - Prob. 83CRCh. 9 - Prob. 84CRCh. 9 - Prob. 85CRCh. 9 - Prob. 86CRCh. 9 - Prob. 87CRCh. 9 - Prob. 88CRCh. 9 - Prob. 89CRCh. 9 - Prob. 90CRCh. 9 - Prob. 91CRCh. 9 - Prob. 92CRCh. 9 - Prob. 93CRCh. 9 - Prob. 94CRCh. 9 - Prob. 95CRCh. 9 - Prob. 96CRCh. 9 - Prob. 97CRCh. 9 - Prob. 98CRCh. 9 - Prob. 99CRCh. 9 - Prob. 100CRCh. 9 - Prob. 101CRCh. 9 - Prob. 102CRCh. 9 - Prob. 103CRCh. 9 - Prob. 104CRCh. 9 - Prob. 105CRCh. 9 - Prob. 106CRCh. 9 - Prob. 107CRCh. 9 - Prob. 1CTCh. 9 - Prob. 2CTCh. 9 - Prob. 3CTCh. 9 - Prob. 4CTCh. 9 - Prob. 5CTCh. 9 - Prob. 6CTCh. 9 - Prob. 7CTCh. 9 - Prob. 8CTCh. 9 - Prob. 9CTCh. 9 - Prob. 10CTCh. 9 - Prob. 11CTCh. 9 - Prob. 12CTCh. 9 - Prob. 13CTCh. 9 - Prob. 14CTCh. 9 - Prob. 15CTCh. 9 - Prob. 16CTCh. 9 - Prob. 17CTCh. 9 - Prob. 18CTCh. 9 - Prob. 19CTCh. 9 - Prob. 20CTCh. 9 - Prob. 21CTCh. 9 - Prob. 22CTCh. 9 - Prob. 23CTCh. 9 - Prob. 24CTCh. 9 - Prob. 25CTCh. 9 - Prob. 1STPCh. 9 - Prob. 2STPCh. 9 - Prob. 3STPCh. 9 - Prob. 4STPCh. 9 - Prob. 5STPCh. 9 - Prob. 6STPCh. 9 - Prob. 7STPCh. 9 - Prob. 8STPCh. 9 - Prob. 9STPCh. 9 - Prob. 10STPCh. 9 - Prob. 11STPCh. 9 - Prob. 12STPCh. 9 - Prob. 13STPCh. 9 - Prob. 14STPCh. 9 - Prob. 15STPCh. 9 - Prob. 16STPCh. 9 - Prob. 17STPCh. 9 - Prob. 18STPCh. 9 - Prob. 19STPCh. 9 - Prob. 20STPCh. 9 - Prob. 21STPCh. 9 - Prob. 22STPCh. 9 - Prob. 23STPCh. 9 - Prob. 24STPCh. 9 - Prob. 25STPCh. 9 - Prob. 26STPCh. 9 - Prob. 27STP
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