Concept explainers
a.
To find: the probability that the student will be able to answer all 10 questions on the exam.
a.

Answer to Problem 41E
Explanation of Solution
Given:
Total number of questions = 20
Total number of questions in exam = 10
Total number of questions student can solve = 15
Total number of questions student can’t solve =
Let E be the event that will be able to answer all 10 questions on the exam.
The possible number of ways to choose 10 out of the 15 known questions is:
Total possible number of ways to choose 10 out of 20 questions is:
Thus, the probability that the student will be able to answer all 10 questions on the exam is:
b.
To find: the probability that the student will be able to answer exactly eight questions on the exam.
b.

Answer to Problem 41E
Explanation of Solution
Given:
Total number of questions = 20
Total number of questions in exam = 10
Total number of questions student can solve = 15
Total number of questions student can’t solve =
Let E be the event that will be able to answer exactly eight questions on the exam.
Total possible number of ways to choose 10 out of 20 questions is:
Thus, the probability that the student will be able to answer exactly eight questions on the exam is:
c.
To find: the probability that the student will be able to answer at least nine questions on the exam.
c.

Answer to Problem 41E
Explanation of Solution
Given:
Total number of questions = 20
Total number of questions in exam = 10
Total number of questions student can solve = 15
Total number of questions student can’t solve =
Let E be the event that will be able to answer at least nine questions on the exam.
(It is sum of number to ways to be able to answer all 10 questions and to be able to solve exactly 9 questions)
Total possible number of ways to choose 10 out of 20 questions is:
Thus, the probability that the student will be able to answer at least nine questions on the exam is:
Chapter 9 Solutions
EBK PRECALCULUS W/LIMITS
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