To determine To solve: The triangle if a = 4530 , b = 924 and C = 98 ° . Explanation Formula used: Law of cosines: Consider the following triangle as shown below: Let a, b and c be the sides of the triangle, then the law of cosines is given by: a 2 = b 2 + c 2 − 2 b c cos A This can be also written as follows. b 2 = a 2 + c 2 − 2 a c cos B c 2 = a 2 + b 2 − 2 a b cos C Law of sines: a sin A = b sin B = c sin C Calculation: Given that, the magnitude of a = 4530 , b = 924 and C = 98 ° . Sketch the graph of the triangle with known measures as shown below in Figure 1. From Figure 1, it is observed that the two sides and the included angle of the triangle is known. So, directly solve the side opposite to the given angle, which is c here, using law of cosines. Substitute 4530for a , 924 for b and 98 ° for C in c 2 = a 2 + b 2 − 2 a b cos C . c 2 = a 2 + b 2 − 2 a b cos C c 2 = 4530 2 + 924 2 − 2 ( 4530 ) ( 924 ) cos 98 ° c = 4530 2 +

Pearson eText for Basic Technical Mathematics with Calculus -- Instant Access (Pearson+)

11th Edition

ISBN: 9780137554843

Author: Allyn Washington, Richard Evans

Publisher: PEARSON+

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Chapter 9.6, Problem 5E

To determine

To solve: The triangle if a=4530,b=924 and C=98°.

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Chapter 9.6, Problem 4E

Chapter 9.6, Problem 6E

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Chapter 9 Solutions

Pearson eText for Basic Technical Mathematics with Calculus -- Instant Access (Pearson+)

Ch. 9.1 - For the vectors in Example 2, show that R = B + C...Ch. 9.1 - Prob. 2PE Ch. 9.1 - Prob. 1E Ch. 9.1 - Prob. 2E Ch. 9.1 - Prob. 3E Ch. 9.1 - Prob. 4E Ch. 9.1 - Prob. 5E Ch. 9.1 - Prob. 6E Ch. 9.1 - Prob. 7E Ch. 9.1 - Prob. 8E

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