Explanation Given Information: The provided equations of line are, y = − 6.4 x − 7 and 64 y − 5 x = 32 Explanation: Consider the provided equations of lines, y = − 6.4 x − 7 …… (1) 64 y − 5 x = 32 …… (2) Now, the slope-intercept form of line is, y = m x + b Where m is slope and b is y intercept. Now, for the equation (1), y = − 6.4 x − 7 Thus, the slope is − 6.4 and the y intercept is ( 0 , − 7 ) . Now, convert the equation (2) into slope intercept form by adding 5 x to both sides as, 64 y − 5 x + 5 x = 32 + 5 x 64 y = 5 x + 32 Divide both sides by 64 to get, y = 5 64 x + 1 2 Thus, the slope is 5 64 and y intercept is ( 0 , 1 2 ) . Now, obtain the product of slopes of both the lines as, m 1 m 2 = 5 64 ⋅ − 6.4 = − 5 10 = − 1 2 Since, the product of slopes is not − 1 , so the lines are not perpendicular. The following table represents the coordinates of the equation y = − 6.4 x − 7 . Coordinates of x Coordinates of y y = − 6.4 x − 7 Coordinates of ( x , y ) − 1.3 − 6.4 ⋅ ( − 1

16th Edition

ISBN: 9781323235911

Author: BITTINGER

Publisher: Pearson Custom Publishing

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Chapter 9.6, Problem 20ES

To determine

Whether the graphs of the equations y=−6.4x−7 and 64y−5x=32 are perpendicular lines.

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Chapter 9.6, Problem 19ES

Chapter 9.6, Problem 21ES

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Chapter 9 Solutions

DEVELOP.MATH(3 VOLS) CUSTOM-W/MML <IC<

Ch. 9.1 - Objective 8.1a: Determine whether a given number...Ch. 9.1 - Prob. 2SR Ch. 9.1 - Prob. 1DE Ch. 9.1 - Prob. 2DE Ch. 9.1 - Prob. 3DE Ch. 9.1 - Prob. 4DE Ch. 9.1 - Prob. 5DE Ch. 9.1 - Prob. 6DE Ch. 9.1 - Prob. 7DE Ch. 9.1 - Prob. 8DE

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Prob. 32UTDW Ch. 9.4 - Prob. 33UTDW Ch. 9.5 - 1. 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Whether the graphs of the equations y = − 6.4 x − 7 and 64 y − 5 x = 32 are perpendicular lines.

Solution Summary: The author explains that the lines of the equations y=-6.4x-7 and 64y-5x=32 are not perpendicular.

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Whether the graphs of the equations y=−6.4x−7 and 64y−5x=32 are perpendicular lines.

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Chapter 9 Solutions