Chapter 9.5, Problem 9CYU

To determine

The numbers in the increasing order

Answer to Problem 9CYU

  $6.1\times {10}^{-2}<6.5\times {10}^3<6.01\times {10}^4<6.12\times {10}^5$

Explanation of Solution

Given:

The given terms are

  $6.5\times {10}^3,6.12\times {10}^5,6.01\times {10}^4,6.1\times {10}^{-2}$

Calculation:

The given terms can be simplified as

  $\begin{array}{l}\Rightarrow 6.5\times {10}^3\\ =\frac{65}{10}\times 1000\\ =6500\\ \\ \Rightarrow 6.12\times {10}^5\\ =\frac{612}{100}\times 100000\\ =612000\\ \\ \Rightarrow 6.01\times {10}^4\\ =\frac{601}{100}\times 10000\\ =60100\\ \\ \Rightarrow 6.1\times {10}^{-2}\\ =\frac{61}{10}\times \frac{1}{100}\\ =\frac{61}{1000}\\ =0.061\\ \\ \text{As,}\\ 0.061<6500<60100<612000\\ 6.1\times {10}^{-2}<6.5\times {10}^3<6.01\times {10}^4<6.12\times {10}^5\end{array}$