ch of these relations on the set of all functions from Z to Z are equivalence relations? Determine the properties of an equivalence relation that the others lack. a) { ( f , g ) | f ( 1 ) = g ( 1 ) } b) { ( f , g ) | f ( 0 ) = g ( 0 ) or f ( 1 ) = g ( 1 ) } c) { ( f , g ) | f ( x ) − g ( x ) =1 for all x ∈ Z } d) { ( f , g ) | for some C ∈ Z , for all x ∈ Z , f ( x ) − g ( x ) =C } e) { ( f , g ) | f ( 0 ) = g ( 1 ) and f ( 1 ) = g ( 0 ) }
ch of these relations on the set of all functions from Z to Z are equivalence relations? Determine the properties of an equivalence relation that the others lack. a) { ( f , g ) | f ( 1 ) = g ( 1 ) } b) { ( f , g ) | f ( 0 ) = g ( 0 ) or f ( 1 ) = g ( 1 ) } c) { ( f , g ) | f ( x ) − g ( x ) =1 for all x ∈ Z } d) { ( f , g ) | for some C ∈ Z , for all x ∈ Z , f ( x ) − g ( x ) =C } e) { ( f , g ) | f ( 0 ) = g ( 1 ) and f ( 1 ) = g ( 0 ) }
Solution Summary: The author explains that equivalence relations determine the properties of an equivalent relation that the others lack.
ch of these relations on the set of all functions fromZtoZare equivalence relations? Determine the properties of an equivalence relation that the others lack.
a)
{
(
f
,
g
)
|
f
(
1
)
=
g
(
1
)
}
b)
{
(
f
,
g
)
|
f
(
0
)
=
g
(
0
)
or
f
(
1
)
=
g
(
1
)
}
c)
{
(
f
,
g
)
|
f
(
x
)
−
g
(
x
)
=1 for all
x
∈
Z
}
d)
{
(
f
,
g
)
|
for some C
∈
Z
,
for all
x
∈
Z
,
f
(
x
)
−
g
(
x
)
=C
}
e)
{
(
f
,
g
)
|
f
(
0
)
=
g
(
1
)
and
f
(
1
)
=
g
(
0
)
}
1.
Prove the following arguments using the rules of inference. Do not make use of
conditional proof.
(а) а → (ЪЛс)
¬C
..¬a
(b) (pVq) →
→r
יור
(c) (c^h) → j
¬j
h
(d) s→ d
t
d
-d
..8A-t
(e) (pVg) (rv¬s)
Лѕ
קר .'
The graph of f(x) is given below. Select each true statement about the continuity of f(x) at x = 1.
Select all that apply:
☐ f(x) is not continuous at x = 1 because it is not defined at x = 1.
☐ f(x) is not continuous at x = 1 because lim f(x) does not exist.
x+1
☐ f(x) is not continuous at x = 1 because lim f(x) ‡ f(1).
x+→1
☐ f(x) is continuous at x = 1.
2. Consider the following argument:
(a)
Seabiscuit is a thoroughbred.
Seabiscuit is very fast.
Every very fast racehorse can win the race.
.. Therefore, some thoroughbred racehorse can win the race.
Let us define the following predicates, whose domain is racehorses:
T(x) x is a thoroughbred
F(x) x is very fast
R(x) x can win the race
:
Write the above argument in logical symbols using these predicates.
(b)
Prove the argument using the rules of inference. Do not make use of conditional
proof.
(c)
Rewrite the proof using full sentences, avoiding logical symbols. It does not
need to mention the names of rules of inference, but a fellow CSE 16 student should be
able to understand the logical reasoning.
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, subject and related others by exploring similar questions and additional content below.
RELATIONS-DOMAIN, RANGE AND CO-DOMAIN (RELATIONS AND FUNCTIONS CBSE/ ISC MATHS); Author: Neha Agrawal Mathematically Inclined;https://www.youtube.com/watch?v=u4IQh46VoU4;License: Standard YouTube License, CC-BY