Static Friction A 20-pound box sits at rest on a horizontal surface, and there is friction between the box and the surface. One side of the surface is raised slowly to create a ramp. The friction force f opposes the direction of motion and is proportional to the normal force F N exerted by the surface on the box. The proportionality constant is called the coefficient of friction , μ . When the angle of the ramp, θ , reaches 20 ° , the box begins to slide. Find the value of μ to two decimal places.
Static Friction A 20-pound box sits at rest on a horizontal surface, and there is friction between the box and the surface. One side of the surface is raised slowly to create a ramp. The friction force f opposes the direction of motion and is proportional to the normal force F N exerted by the surface on the box. The proportionality constant is called the coefficient of friction , μ . When the angle of the ramp, θ , reaches 20 ° , the box begins to slide. Find the value of μ to two decimal places.
Solution Summary: The author explains how a 20-pound box sits at rest, and there is friction between the box and the surface. The proportionality constant is called the coefficient of friction,.
Static Friction A 20-pound box sits at rest on a horizontal surface, and there is friction between the box and the surface. One side of the surface is raised slowly to create a ramp. The friction force f opposes the direction of motion and is proportional to the normal force
exerted by the surface on the box. The proportionality constant is called the coefficient of friction,
. When the angle of the ramp,
, reaches
, the box begins to slide. Find the value of
to two decimal places.
Question 2
Let F be a solenoidal vector field, suppose V × F = (-8xy + 12z², −9x² + 4y² + 9z², 6y²), and let
(P,Q,R) = V²F(.725, —.283, 1.73). Then the value of sin(2P) + sin(3Q) + sin(4R) is
-2.024
1.391
0.186
-0.994
-2.053
-0.647
-0.588
-1.851
1 pts
1 pts
Let F and G be vector fields such that ▼ × F(0, 0, 0) = (0.76, -9.78, 3.29), G(0, 0, 0) = (−3.99, 6.15, 2.94), and
G is irrotational. Then sin(5V (F × G)) at (0, 0, 0) is
Question 1
-0.246
0.072
-0.934
0.478
-0.914
-0.855
0.710
0.262
.
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