Explanation Formula used: The standard equation of hyperbola with center ( h , k ) and vertices ( h , k + b ) and ( h , k − b ) , ( y − k ) 2 b 2 − ( x − h ) 2 a 2 = 1 Calculation: The vertices of hyperbola are ( 4 , − 14 ) and ( 4 , 0 ) , which has the form ( h , k + b ) and ( h , k − b ) . Therefore, the hyperbola is a vertical hyperbola. On comparison, h = 4 and k can be found out as below: k = − 14 + 0 2 = − 7 So, the center of the hyperbola is ( h , k ) = ( 4 , − 7 ) . Now, the standard equation of one of the asymptotes is y = − b a x . Compare the given equation of asymptote y = − 7 4 x

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ISBN: 9780135909942

Author: TOBEY/SLATER

Publisher: PEARSON

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Chapter 9.4, Problem 27E

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To calculate: The equation of hyperbola if the hyperbola’s center is not at the origin and its vertices are (4,−14) and (4,0) and one asymptote is y=−74x.

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Chapter 9.4, Problem 26E

Chapter 9.4, Problem 28E

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Chapter 9 Solutions

INTERMEDIATE ALGEBRA - 18 WEEK MML CODE

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The equation of hyperbola if the hyperbola’s center is not at the origin and its vertices are ( 4 , − 14 ) and ( 4 , 0 ) and one asymptote is y = − 7 4 x .

Solution Summary: The author calculates the equation of hyperbola if its center is not at the origin and its vertices are (h,k+b)and

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To calculate: The equation of hyperbola if the hyperbola’s center is not at the origin and its vertices are (4,−14) and (4,0) and one asymptote is y=−74x.

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Chapter 9 Solutions