Explanation Given information: ∫ 2 5 x e x d x with n = 5 . Where, n is number of equal subintervals. Formula used: 1) Midpoint Rule: M = ∫ a b f ( x ) d x ≈ [ f ( x 1 ) + f ( x 2 ) + ⋯ + f ( x n ) ] Δ x Where, x 1 , x 2 , ... , x n are mid-points of the subintervals of the intervals a ≤ x ≤ b and Δ x = b − a n . 2) Trapezoidal Rule: T = ∫ a b f ( x ) d x ≈ [ f ( a 0 ) + 2 f ( a 1 ) + ... + 2 f ( a n − 1 ) + f ( a n ) ] Δ x 2 Where, a 0 , a 1 , ... , a n are end points of subintervals a ≤ x ≤ b and Δ x = b − a n . 3) Simpson’s Rule: ∫ a b f ( x ) ≈ S = 2 M + T 3 . Where, M the approximate value of integral is calculated by midpoint rule and T is the approximate value of integral calculated by Trapezoidal rule. 4) Integration by parts ∫ f ( x ) g ( x ) d x = f ( x ) G ( x ) − ∫ f ′ ( x ) G ( x ) d x Where, f ' ( x ) is derivative of f ( x ) and G ( x ) is an antiderivative of g ( x ) . Calculation: For n = 5 Compare ∫ a b f ( x ) d x with ∫ 2 5 x e x d x it becomes a = 2 and b = 5 Therefore, Δ x = b − a n = 5 − 2 5 = 0.6 Now, a 0 = a ⇒ a 0 = 2 x 1 = a 0 + Δ x 2 = 2 + 0.6 2 = 2.3 x 2 = x 1 + Δ x = 2.3 + 0.6 = 2.9 x 3 = x 2 + Δ x = 2.9 + 0.6 = 3.5 x 4 = x 3 + Δ x = 3.5 + 0.6 = 4.1 x 5 = x 4 + Δ x = 4.1 + 0.6 = 4.7 By using mid-point rule, M = ∫ 2 5 x e x d x ≈ [ f ( 2.3 ) + f ( 2.9 ) + f ( 3.5 ) + f ( 4.1 ) + f ( 4.7 ) ] × 0.6 = [ 2.3 e 2.3 + 2.9 e 2.9 + 3.5 e 3.5 + 4

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ISBN: 9780137590469

Author: Larry Goldstein / David Lay

Publisher: Pearson Education (US)

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Numerical Integration

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Chapter 9.4, Problem 19E

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To calculate: The approximate value of integral ∫25xexdx by midpoint rule, trapezoidal rule,

Simson’s rule with n=5 and find the exact value of integration. Express answers to five decimal places.

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Chapter 9.4, Problem 18E

Chapter 9.4, Problem 20E

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The approximate value of integral ∫ 2 5 x e x d x by midpoint rule, trapezoidal rule, Simson’s rule with n = 5 and find the exact value of integration . Express answers to five decimal places.

Solution Summary: The author calculates the approximate value of integral by midpoint rule, trapezoidal rule and Simson's rule with n=5.

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To calculate: The approximate value of integral ∫25xexdx by midpoint rule, trapezoidal rule,

Simson’s rule with n=5 and find the exact value of integration. Express answers to five decimal places.

Want to see the full answer?

Chapter 9 Solutions

The approximate value of integral ∫ 2 5 x e x d x by midpoint rule, trapezoidal rule, Simson’s rule with n = 5 and find the exact value of integration . Express answers to five decimal places.

Solution Summary: The author calculates the approximate value of integral by midpoint rule, trapezoidal rule and Simson's rule with n=5.

Concept explainers

Videos

To calculate: The approximate value of integral ∫25xexdx by midpoint rule, trapezoidal rule, Simson’s rule with n=5 and find the exact value of integration. Express answers to five decimal places.

Want to see the full answer?

Chapter 9 Solutions

To calculate: The approximate value of integral ∫25xexdx by midpoint rule, trapezoidal rule,

Simson’s rule with n=5 and find the exact value of integration. Express answers to five decimal places.