Chapter 9.4, Problem 18E

To determine

To identify: The amplitude and period of the function then graph the function and describe the function of $g$ as a transformation of the graph of its parent function.

Answer to Problem 18E

The amplitude is 3 and period is $\pi$ and graph is shown in figure (1).

Explanation of Solution

Given:

The given function is $g\left(x\right)=3\sin 2x$ .

Calculation:

Compare the function $g\left(x\right)=3\sin 2x$ with $y=a\sin b\left(x-h\right)+k$ to find amplitude and period of the function.

  $\begin{array}{c}a=3\\ \text{Period}=\frac{2\pi }{b}\\ =\frac{2\pi }{2}\\ =\pi \end{array}$

The horizontal shift is $h=0$ and vertical shifts is $k=0$ .

Draw the midline of the graph, $y=0$ .

Find the intercepts at $x=0,\frac{\pi }{4},\frac{\pi }{2},\frac{3\pi }{4},\pi$ to draw the graph.

  $\begin{array}{c}\left(0,3\sin 0\right)=\left(0,0\right)\\ \left(\frac{\pi }{4},3\sin \frac{\pi }{2}\right)=\left(\frac{\pi }{4},3\right)\\ \left(\frac{\pi }{2},3\sin \pi \right)=\left(\frac{\pi }{2},0\right)\\ \left(\frac{3\pi }{4},3\sin \frac{3\pi }{2}\right)=\left(\frac{3\pi }{4},-3\right)\end{array}$

And,

  $\left(\pi ,3\sin 2\pi \right)=\left(\pi ,0\right)$

Maximum point is $\left(\frac{\pi }{4},1\right)$ and minimum point is $\left(\frac{3\pi }{4},-1\right)$ .

Draw the graph of the function $g\left(x\right)=3\sin 2x$ as follows.

  

Figure (1)

The graph of $g$ is a vertical stretch by a factor of 3 and a horizontal shrink by a factor of $\frac{1}{2}$ for the graph of $f$ .

Therefore, the amplitude is 3 and period is $\pi$ and graph is shown in figure (1).