Introduction to Probability and Statistics
14th Edition
ISBN: 9781133103752
Author: Mendenhall, William
Publisher: Cengage Learning
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Chapter 9.3, Problem 9.2E
To determine
Appropriate conclusion at value of
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32. Consider a normally distributed population with mean μ = 80
and standard deviation σ = 14.
a.
Construct the centerline and the upper and lower control
limits for the chart if samples of size 5 are used.
b. Repeat the analysis with samples of size 10.
2080 101
c. Discuss the effect of the sample size on the control limits.
Consider the following hypothesis test.
The following results are for two independent samples taken from the two populations.
Sample 1
Sample 2
n 1 = 80
n 2 = 70
x 1 = 104
x 2 = 106
σ 1 = 8.4
σ 2 = 7.6
What is the value of the test statistic? If required enter negative values as negative numbers (to 2 decimals).
What is the p-value (to 4 decimals)? Use z-table.
With = .05, what is your hypothesis testing conclusion?
Periodically, Merrill Lynch customers are asked to evaluate Merrill Lynch financial consultants and services (2000 Merrill Lynch Client Satisfaction Survey). Higher ratings on the client satisfaction survey indicate better service with 7 the maximum service rating. Independent samples of service ratings for two financial consultants are summarized here. Consultant A has 10 years of experience, whereas consultant B has 1 year of experience. Use = .05 and test to see whether the consultant with more experience has the higher population mean service rating.
Consultant A
Consultant B
= 16
= 10
= 6.82
= 6.25
= .64
= .75
State the null and alternative hypotheses.H0: 1 - 2 Ha: 1 - 2
Compute the value of the test statistic (to 2 decimals).
What is the p-value?The p-value is
What is your conclusion?
Chapter 9 Solutions
Introduction to Probability and Statistics
Ch. 9.3 - Find the appropriate rejection regions for the...Ch. 9.3 - Prob. 9.2ECh. 9.3 - Find the appropriate rejection regions for the...Ch. 9.3 - Prob. 9.4ECh. 9.3 - For the three tests given in Exercise 9.4, use the...Ch. 9.3 - A random sample of n=35 observations from a...Ch. 9.3 - Prob. 9.7ECh. 9.3 - Prob. 9.8ECh. 9.3 - A random sample of 100 observations from a...Ch. 9.3 - Prob. 9.10E
Ch. 9.3 - Prob. 9.11ECh. 9.3 - Prob. 9.12ECh. 9.3 - Prob. 9.14ECh. 9.3 - Prob. 9.15ECh. 9.3 - What’s Normal? What is normal, when it comes to...Ch. 9.4 - Prob. 9.18ECh. 9.4 - Independent random samples of 36 and 45...Ch. 9.4 - Prob. 9.20ECh. 9.4 - Cure for the Common Cold? An experiment was...Ch. 9.4 - Healthy Eating As Americans become more conscious...Ch. 9.4 - Prob. 9.24ECh. 9.4 - Prob. 9.25ECh. 9.4 - Prob. 9.26ECh. 9.4 - Prob. 9.27ECh. 9.4 - Prob. 9.28ECh. 9.4 - What’s Normal II Of the 130 people in Exercise...Ch. 9.5 - A random sample of n=1000 observations from a...Ch. 9.5 - A random sample of n=1400 observations from a...Ch. 9.5 - Prob. 9.32ECh. 9.5 - Prob. 9.33ECh. 9.5 - Prob. 9.38ECh. 9.5 - Prob. 9.40ECh. 9.5 - Prob. 9.41ECh. 9.6 - Independent random samples of n1=140 and n2=140...Ch. 9.6 - Prob. 9.43ECh. 9.6 - Prob. 9.46ECh. 9.6 - Prob. 9.47ECh. 9.6 - Prob. 9.48ECh. 9.6 - Prob. 9.49ECh. 9.6 - Prob. 9.50ECh. 9 - Prob. 9.52SECh. 9 - Prob. 9.53SECh. 9 - Prob. 9.54SECh. 9 - Prob. 9.55SECh. 9 - Prob. 9.56SECh. 9 - Prob. 9.57SECh. 9 - Prob. 9.58SECh. 9 - Prob. 9.59SECh. 9 - Prob. 9.60SECh. 9 - White-Tailed Deer In an article entitled “A...Ch. 9 - Prob. 9.62SECh. 9 - Prob. 9.63SECh. 9 - Prob. 9.64SECh. 9 - Prob. 9.65SECh. 9 - Prob. 9.66SECh. 9 - Prob. 9.67SECh. 9 - Prob. 9.68SECh. 9 - Prob. 9.69SECh. 9 - Prob. 9.70SECh. 9 - Prob. 9.71SECh. 9 - Actinomycin D A biologist hypothesizes that high...Ch. 9 - Prob. 9.73SECh. 9 - Prob. 9.74SECh. 9 - Heights and Gender It is a well-accepted fact that...Ch. 9 - Prob. 9.79SECh. 9 - Prob. 9.81SE
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