Explanation Given: The equation of the ellipse: ( x + 5 ) 2 16 + ( y + 2 ) 2 36 = 1 Graph: Consider the equation of the ellipse, ( x + 5 ) 2 16 + ( y + 2 ) 2 36 = 1 Compare the above equation with the standard form of the equation of the ellipse with ( h , k ) as its center and the length of its axis are 2 a and 2 b that is, ( x − h ) 2 a 2 + ( y − k ) 2 b 2 = 1 Form this, h = − 5 , k = − 2 , a = 4 and b = 6 Therefore, the ellipse ( x + 5 ) 2 16 + ( y + 2 ) 2 36 = 1 is centered at ( − 5 , − 2 ) . Now, to plot the vertices of the ellipse on the axis parallel to x -axis, begin at ( − 5 , − 2 ) and plot 4 units to its left and 4 units to its right

Pearson eText for Intermediate Algebra -- Instant Access (Pearson+)

8th Edition

ISBN: 9780137553464

Author: John Tobey, Jeffrey Slater

Publisher: PEARSON+

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Vertices Of An Ellipse

In the study of the conic section of the geometry, An ellipse is a plane curve surrounding two focal points, or foci where the set of all locus of points in the plane has their sum of the distances to the two foci is constant. On the ellipse curve, it is…

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Chapter 9.3, Problem 27E

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To graph: The ellipse (x+5)216+(y+2)236=1 and label the center.

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Chapter 9.3, Problem 26E

Chapter 9.3, Problem 28E

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1) Express these large and small numbers from the Read and Study section in scientific notation: (a) 239,000 miles (b) 3,800,000,000,000 sheets of paper (c) 0.0000000000000000000000167 grams 2) Find all values for the variable x that make these equations true. (a) 5x = 1 (b) 3x = 1/1 9 (c) 4* = 11/ 4 (e) 4* = 64 (g) 10x = 1,000,000 (d) 3x=-3 (f) 2x = = 8 (h) 10x = 0.001

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Chapter 9 Solutions

Pearson eText for Intermediate Algebra -- Instant Access (Pearson+)

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To graph: The ellipse ( x + 5 ) 2 16 + ( y + 2 ) 2 36 = 1 and label the center.

Solution Summary: The author compares the equation of the ellipse with the standard form of its equation with (h,k) as its center.

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To graph: The ellipse (x+5)216+(y+2)236=1 and label the center.

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Chapter 9 Solutions