Explanation Given: The equation of the ellipse: ( x + 5 ) 2 16 + ( y + 2 ) 2 36 = 1 Graph: Consider the equation of the ellipse, ( x + 5 ) 2 16 + ( y + 2 ) 2 36 = 1 Compare the above equation with the standard form of the equation of the ellipse with ( h , k ) as its center and the length of its axis are 2 a and 2 b that is, ( x − h ) 2 a 2 + ( y − k ) 2 b 2 = 1 Form this, h = − 5 , k = − 2 , a = 4 and b = 6 Therefore, the ellipse ( x + 5 ) 2 16 + ( y + 2 ) 2 36 = 1 is centered at ( − 5 , − 2 ) . Now, to plot the vertices of the ellipse on the axis parallel to x -axis, begin at ( − 5 , − 2 ) and plot 4 units to its left and 4 units to its right

Intermediate Algebra Books a la Carte Edition PLUS MyLab Math (8th Edition)

8th Edition

ISBN: 9780134578507

Author: John Tobey Jr., Jeffrey Slater, Jenny Crawford, Jamie Blair

Publisher: PEARSON

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Vertices Of An Ellipse

In the study of the conic section of the geometry, An ellipse is a plane curve surrounding two focal points, or foci where the set of all locus of points in the plane has their sum of the distances to the two foci is constant. On the ellipse curve, it is…

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Chapter 9.3, Problem 27E

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To graph: The ellipse (x+5)216+(y+2)236=1 and label the center.

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Chapter 9.3, Problem 26E

Chapter 9.3, Problem 28E

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Chapter 9 Solutions

Intermediate Algebra Books a la Carte Edition PLUS MyLab Math (8th Edition)

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To graph: The ellipse ( x + 5 ) 2 16 + ( y + 2 ) 2 36 = 1 and label the center.

Solution Summary: The author compares the equation of the ellipse with the standard form of its equation with (h,k) as its center.

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To graph: The ellipse (x+5)216+(y+2)236=1 and label the center.

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Chapter 9 Solutions