For Exercises 13–18, solve the equation and related inequalities. (See Examples 2–3.)
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- In Exercises 105–107, solve each equation using a graphing utility. Graph each side separately in the same viewing rectangle. The solutions are the x-coordinates of the intersection points. 105. |x + 1|| 106. 13(x + 4)| = 12 107. 12x – 3| = 19 – 4x|arrow_forwardIn Exercises 23–25, solve each equation. If the solution set is Ø or (-0, ), classify the equation as an inconsistent equation or an identity. 23. 3(2x – 4) = 9 – 3(x + 1) 2x 24. x - 4 x + 1 4 2 4 25. 3(x – 4) + x = 2(6 + 2x)arrow_forwardSolve the variation problems in Exercises 68–73. 68. A company's profit varies directly as the number of products it sells. The company makes a profit of $1175 on the sale of 25 products. What is the company's profit when it sells 105 products? 69. The distance that a body falls from rest varies directly as the square of the time of the fall. If skydivers fall 144 feet in 3 seconds, how far will they fall in 10 seconds? 70. The pitch of a musical tone varies inversely as its wavelength. A tone has a pitch of 660 vibrations per second and a wavelength of 1.6 feet. What is the pitch of a tone that has a wavelength of 2.4 feet? 71. The loudness of a stereo speaker, measured in decibels, varies inversely as the square of your distance from the speaker. When you are 8 feet from the speaker, the loudness is 28 decibels. What is the loudness when you are 4 feet from the speaker? 72. The time required to assemble computers varies directly as the number of computers assembled and inversely as…arrow_forward
- Solve 5.arrow_forwardExercises 105-120: Complete the following. (a) Write the equation as ax² + bx + e = 0 with a > 0. (b) Calculate the discriminant b² – 4ac and determine the number of real solutions. (c) Solve the equation. 105. 3x² = 12 106. 8x - 2 = 14 107. x² – 2x = -1 108. 6x² = 4x 109. 4x = x? 110. 16x + 9 = 24x 111. x² + 1 = x 112. 2x² + x = 2 113. 2x² + 3x = 12 – 2x 114. 3x² + 3 = 5x 115. x(x – 4) = -4 116. + 3x = x – 4 117. x(x + 2) = -13 118. 4x = 6 + x? 119. 3x = 1- x 120. x(5x – 3) = 1arrow_forwardplease solve asaparrow_forward
- Exercises 43–52: Complete the following. (a) Solve the equation symbolically. (b) Classify the equation as a contradiction, an identity, or a conditional equation. 43. 5x - 1 = 5x + 4 44. 7- 9: = 2(3 – 42) – z 45. 3(x - 1) = 5 46. 22 = -2(2x + 1.4) 47. 0.5(x – 2) + 5 = 0.5x + 4 48. 눈x-2(x-1)3-x + 2 2x + 1 2x 49. 50. x – 1.5 2- 3r - 1.5 51. -6 52. 0.5 (3x - 1) + 0.5x = 2x – 0.5arrow_forward28. Place (click and drag) into the appropriate boxes the values of A, B, and C that will make the equation shown below true. Ax2 +Bx +C (x-3)(2x - 5) 2x +1 4x +6 X-3 2x 5 9. 8. 16 -14 6. 10 -23 -13 13 A B = 2. C = %3D B.arrow_forward15. Every year in Delaware there is a contest where people create cannons and catapults designed to launch pumpkins as far in the air as possible. The equation y = 10 + 95x- 16x- can be used to represent the height, y, of a launched pumpkin, where x is the time in seconds that the pumpkin has been in the air. What is the maximum height that the pumpkin reaches? How many seconds have passed when the pumpkin hits the ground? (Hint: If the pumpkin hits the ground, its height is 0 feet.) O The pumpkin's maximum height is 2.97 feet and it hits the ground after 6.04 seconds. O The pumpkin's maximum height is 151.02 feet and it hits the ground after 6.04 seconds. O The pumpkin's maximum height is 2.97 feet and it hits the ground after 151.02 seconds. O The pumpkin's maximum height is 151.02 feet and it hits the ground after 2.97 seconds.arrow_forward
- Big Ideas Math A Bridge To Success Algebra 1: Stu...AlgebraISBN:9781680331141Author:HOUGHTON MIFFLIN HARCOURTPublisher:Houghton Mifflin Harcourt