Explanation Given Information: The function, f ( x ) = 5 e − 5 x over the interval [ 0 , ∞ ) Proof: Consider the function, f ( x ) = 5 e − 5 x A function f of a continuous random variables x whose set of values is the interval [ a , b ] . The function is a probability density function when it is non-negative and continuous on the interval [ a , b ] and when ∫ a b f ( x ) d x = 1 f ( x ) is non-negative and continuous over the interval [ 0 , ∞ ) Now, evaluate ∫ a b f ( x ) d x as, ∫ 0 ∞ f ( x ) d x = ∫ 0 ∞ 5 e − 5 x d x = 5 ∫ 0 ∞ e <

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Chapter 9.2, Problem 5E

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To prove: The function, f(x)=5e−5x is a probability density function over the interval [0,∞).

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Chapter 9.2, Problem 4E

Chapter 9.2, Problem 6E

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Chapter 9 Solutions

Bundle: Calculus: An Applied Approach, Loose-Leaf Version, 10th + WebAssign Printed Access Card for Larson's Calculus: An Applied Approach, 10th Edition, Single-Term

Ch. 9.1 - Checkpoint 1 Worked-out solution available at...Ch. 9.1 - Prob. 2CP Ch. 9.1 - Prob. 3CP Ch. 9.1 - Prob. 4CP Ch. 9.1 - Prob. 5CP Ch. 9.1 - Prob. 6CP Ch. 9.1 - Prob. 1SWU Ch. 9.1 - Prob. 2SWU Ch. 9.1 - Prob. 3SWU Ch. 9.1 - Prob. 4SWU

Ch. 9.1 - Prob. 5SWU Ch. 9.1 - Prob. 6SWU Ch. 9.1 - Prob. 7SWU Ch. 9.1 - Prob. 8SWU Ch. 9.1 - Prob. 9SWU Ch. 9.1 - Prob. 10SWU Ch. 9.1 - Prob. 1E Ch. 9.1 - Prob. 2E Ch. 9.1 - Prob. 3E Ch. 9.1 - Prob. 4E Ch. 9.1 - Prob. 5E Ch. 9.1 - Prob. 6E Ch. 9.1 - Prob. 7E Ch. 9.1 - Random Selection A card is chosen at random from a...Ch. 9.1 - Prob. 9E Ch. 9.1 - Prob. 10E Ch. 9.1 - Identifying Probability Distributions In Exercises...Ch. 9.1 - Prob. 12E Ch. 9.1 - Prob. 13E Ch. 9.1 - Prob. 14E Ch. 9.1 - Prob. 15E Ch. 9.1 - Using Probability Distributions In Exercises 1518,...Ch. 9.1 - Prob. 17E Ch. 9.1 - Prob. 18E Ch. 9.1 - Prob. 19E Ch. 9.1 - Children The table shows the probability...Ch. 9.1 - Prob. 21E Ch. 9.1 - Die Roll Consider the experiment of rolling a...Ch. 9.1 - Prob. 23E Ch. 9.1 - Prob. 24E Ch. 9.1 - Prob. 25E Ch. 9.1 - Prob. 26E Ch. 9.1 - Prob. 27E Ch. 9.1 - Prob. 28E Ch. 9.1 - Prob. 29E Ch. 9.1 - Personal Income The probability distribution of...Ch. 9.1 - Insurance An insurance company needs to determine...Ch. 9.1 - 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Prob. 21E Ch. 9.2 - Prob. 22E Ch. 9.2 - Prob. 23E Ch. 9.2 - Prob. 24E Ch. 9.2 - Prob. 25E Ch. 9.2 - Finding a Probability In Exercises 19-26, sketch...Ch. 9.2 - Prob. 27E Ch. 9.2 - Prob. 28E Ch. 9.2 - Prob. 29E Ch. 9.2 - Demand The daily demand for gasoline x (in...Ch. 9.2 - Prob. 31E Ch. 9.2 - Prob. 32E Ch. 9.2 - Using the Exponential Density Function In...Ch. 9.2 - Prob. 34E Ch. 9.2 - Using the Exponential Density Function In...Ch. 9.2 - Prob. 36E Ch. 9.2 - Prob. 37E Ch. 9.2 - Demand The weekly demand x (in tons) for a certain...Ch. 9.2 - Prob. 39E Ch. 9.3 - Prob. 1CP Ch. 9.3 - Find the variance and standard deviation of the...Ch. 9.3 - Use a symbolic integration utility to find the...Ch. 9.3 - Prob. 4CP Ch. 9.3 - Prob. 5CP Ch. 9.3 - Prob. 6CP Ch. 9.3 - Prob. 7CP Ch. 9.3 - Prob. 1SWU Ch. 9.3 - Prob. 2SWU Ch. 9.3 - Prob. 3SWU Ch. 9.3 - Prob. 4SWU Ch. 9.3 - Prob. 5SWU Ch. 9.3 - Prob. 6SWU Ch. 9.3 - Finding Expected Value, Variance, and Standard...Ch. 9.3 - Prob. 2E Ch. 9.3 - Prob. 3E Ch. 9.3 - 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To prove: The function, f ( x ) = 5 e − 5 x is a probability density function over the interval [ 0 , ∞ ) .

Solution Summary: The author explains that the function f(x)=5e-5x is a probability density function.

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To prove: The function, f(x)=5e−5x is a probability density function over the interval [0,∞).

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Chapter 9 Solutions