Explanation Given Information: The given pair of equations are 4 x − 5 y = 14 and 2 x + 3 y = − 4 . Calculation: Consider the equations 4 x − 5 y = 14 and 2 x + 3 y = − 4 Multiply the equation 2 x + 3 y = − 4 by − 2 on both the sides, we get, − 2 ( 2 x + 3 y ) = − 2 ( − 4 ) − 4 x − 6 y = 8 Now, add the equation as, 4 x − 5 y = 14 − 4 x − 6 y = 8 _ 0 − 11 y = 22 − 11 y = 22 Divide both sides by 11, − 11 y = 22 y = − 22 11 y = − 2 Put y = − 2 in equation 4 x − 5 y = 14 to get, 4 x − 5 y = 14 4 x − 5 ( − 2 ) = 14 4 x = 4 Divide both sides by 4, x = 4 4 x = 1 Thus, the ordered pair of solution for the pair of equation 4 x − 5 y = 14 and 2 x + 3 y = − 4 is ( 1 , − 2 )

Student Solutions Manual For Ewen/nelson's Elementary Technical Mathematics, 11th

11th Edition

ISBN: 9781285199276

Author: Dale Ewen

Publisher: Cengage Learning

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Chapter 9.2, Problem 13E

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To calculate: The solution set for the pair of equations $4x−5y=142x+3y=−4$ , If there is no solution then

determine whether the pair of lines is parallel or coincide.

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Chapter 9.2, Problem 12E

Chapter 9.2, Problem 14E

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(a) Test the hypothesis. Consider the hypothesis test Ho = : against H₁o < 02. Suppose that the sample sizes aren₁ = 7 and n₂ = 13 and that $² = 22.4 and $22 = 28.2. Use α = 0.05. Ho is not ✓ rejected. 9-9 IV (b) Find a 95% confidence interval on of 102. Round your answer to two decimal places (e.g. 98.76).

Let us suppose we have some article reported on a study of potential sources of injury to equine veterinarians conducted at a university veterinary hospital. Forces on the hand were measured for several common activities that veterinarians engage in when examining or treating horses. We will consider the forces on the hands for two tasks, lifting and using ultrasound. Assume that both sample sizes are 6, the sample mean force for lifting was 6.2 pounds with standard deviation 1.5 pounds, and the sample mean force for using ultrasound was 6.4 pounds with standard deviation 0.3 pounds. Assume that the standard deviations are known. Suppose that you wanted to detect a true difference in mean force of 0.25 pounds on the hands for these two activities. Under the null hypothesis, 40 = 0. What level of type II error would you recommend here? Round your answer to four decimal places (e.g. 98.7654). Use a = 0.05. β = i What sample size would be required? Assume the sample sizes are to be equal.…

= Consider the hypothesis test Ho: μ₁ = μ₂ against H₁ μ₁ μ2. Suppose that sample sizes are n₁ = 15 and n₂ = 15, that x1 = 4.7 and X2 = 7.8 and that s² = 4 and s² = 6.26. Assume that o and that the data are drawn from normal distributions. Use απ 0.05. (a) Test the hypothesis and find the P-value. (b) What is the power of the test in part (a) for a true difference in means of 3? (c) Assuming equal sample sizes, what sample size should be used to obtain ẞ = 0.05 if the true difference in means is - 2? Assume that α = 0.05. (a) The null hypothesis is 98.7654). rejected. The P-value is 0.0008 (b) The power is 0.94 . Round your answer to four decimal places (e.g. Round your answer to two decimal places (e.g. 98.76). (c) n₁ = n2 = 1 . Round your answer to the nearest integer.

Chapter 9 Solutions

Student Solutions Manual For Ewen/nelson's Elementary Technical Mathematics, 11th

Ch. 9.1 - Draw the graphs of each pair of linear equations....Ch. 9.1 - Prob. 2E Ch. 9.1 - Draw the graphs of each pair of linear equations....Ch. 9.1 - Prob. 4E Ch. 9.1 - Prob. 5E Ch. 9.1 - Prob. 6E Ch. 9.1 - Prob. 7E Ch. 9.1 - Prob. 8E Ch. 9.1 - Draw the graphs of each pair of linear equations....Ch. 9.1 - Draw the graphs of each pair of linear equations....

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The solution set for the pair of equations 4 x − 5 y = 14 2 x + 3 y = − 4 , If there is no solution then determine whether the pair of lines is parallel or coincide.

Solution Summary: The author calculates the solution set for the pair of equations c4x-5y=14 and 2x+3y =-4. If there is no solution, determine

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To calculate: The solution set for the pair of equations $4x−5y=142x+3y=−4$ , If there is no solution then

determine whether the pair of lines is parallel or coincide.

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Chapter 9 Solutions