
Concept explainers
(a)
To graph: The sketch of housing starts versus time from the beginning of
(b)
The maximum and minimum number of housing started if the number of housing started is given as
(c)
To calculate: The maximum and minimum number of housing starts directly from the equation

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Chapter 9 Solutions
Student Solutions Manual for Waner/Costenoble's Applied Calculus, 7th
- Q2. You deposit $22,000 in an account that pays 4.8% interest compounded monthly. a. Find the future value after six years. & b b. Determine the effective annual yield of this account.arrow_forward18. Using the method of variation of parameter, a particular solution to y′′ + 16y = 4 sec(4t) isyp(t) = u1(t) cos(4t) + u2(t) sin(4t). Then u2(t) is equal toA. 1 B. t C. ln | sin 4t| D. ln | cos 4t| E. sec(4t)arrow_forwardQuestion 4. Suppose you need to know an equation of the tangent plane to a surface S at the point P(2, 1, 3). You don't have an equation for S but you know that the curves r1(t) = (2 + 3t, 1 — t², 3 − 4t + t²) r2(u) = (1 + u², 2u³ − 1, 2u + 1) both lie on S. (a) Check that both r₁ and r2 pass through the point P. 1 (b) Give the expression of the 074 in two ways Ət ⚫ in terms of 32 and 33 using the chain rule მყ ⚫ in terms of t using the expression of z(t) in the curve r1 (c) Similarly, give the expression of the 22 in two ways Əz ди ⚫ in terms of oz and oz using the chain rule Əz მყ • in terms of u using the expression of z(u) in the curve r2 (d) Deduce the partial derivative 32 and 33 at the point P and the equation of მე მყ the tangent planearrow_forward
- Coast Guard Patrol Search Mission The pilot of a Coast Guard patrol aircraft on a search mission had just spotted a disabled fishing trawler and decided to go in for a closer look. Flying in a straight line at a constant altitude of 1000 ft and at a steady speed of 256 ft/s, the aircraft passed directly over the trawler. How fast (in ft/s) was the aircraft receding from the trawler when it was 1400 ft from the trawler? (Round your answer to one decimal places.) 1000 ft 180 × ft/s Need Help? Read It SUBMIT ANSWERarrow_forward6. The largest interval in which the solution of (cos t)y′′ +t^2y′ − (5/t)y = e^t/(t−3) , y(1) = 2, y′(1) = 0is guaranteed to exist by the Existence and Uniqueness Theorem is:A. (0, ∞) B. (π/2, 3) C. (0,π/2) D. (0, π) E. (0, 3)arrow_forward12. For the differential equation in the previous question, what is the correct form for a particularsolution?A. yp = Ae^t + Bt^2 B. yp = Ae^t + Bt^2 + Ct + DC. yp = Ate^t + Bt^2 D. yp = Ate^t + Bt^2 + Ct + D Previous differential equation y′′ − 4y′ + 3y = e^t + t^2arrow_forward
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- Find the first and second derivatives of the function. f(u) = √7 3u − 3 f'(u) 2 (7-34) (½) f"(u) = 9 4(7-3u) 32 X Need Help? Read It Watch It SUBMIT ANSWERarrow_forward11. Consider the 2nd-order non-homogeneous differential equation y′′ − 4y′ + 3y = et + t2What is the complementary (or homogeneous) solution?A. yc = c1e^t + c2t^2 B. yc = c1e^−t + c2e^−3t C. yc = c1e^t + c2e^3t D. yc = c1e^t + c2e^−3tarrow_forward5. A trial solution for the non-homogeneous equation y′′ + y′ − 2y = e^x isA. Ae^x B. Ae^x+ Be^−2x C. Ae^x + Be^−x D. Axe^x E. None of these.arrow_forward
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