In Exercises 19-20, a few steps in the process of simplifying the given matrix to row-echelon form, with Is down the diagonal from tipper left to lower right, and 0s below the Is, are shown. Fill in the missing numbers in the steps that are shown. [ 1 − 1 1 2 3 − 1 3 − 2 − 9 | 8 − 2 9 ] → [ 1 − 1 1 0 5 0 1 | 8 ] → [ 1 − 1 1 2 3 3 − 2 | 8 ]
In Exercises 19-20, a few steps in the process of simplifying the given matrix to row-echelon form, with Is down the diagonal from tipper left to lower right, and 0s below the Is, are shown. Fill in the missing numbers in the steps that are shown. [ 1 − 1 1 2 3 − 1 3 − 2 − 9 | 8 − 2 9 ] → [ 1 − 1 1 0 5 0 1 | 8 ] → [ 1 − 1 1 2 3 3 − 2 | 8 ]
Solution Summary: The author explains how to determine the missing numbers in the provided matrices.
In Exercises 19-20, a few steps in the process of simplifying the given matrix to row-echelon form, with Is down the diagonal from tipper left to lower right, and 0s below the Is, are shown. Fill in the missing numbers in the steps that are shown.
Solve the equation. Write the smaller
answer first.
2
(x-6)²
= 36
x =
Α
x =
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Write a quadratic equation in
factored form that has solutions of x
=
2 and x = = -3/5
○ a) (x-2)(5x + 3) = 0
○ b) (x + 2)(3x-5) = 0
O
c) (x + 2)(5x -3) = 0
○ d) (x-2)(3x + 5) = 0
Chapter 9 Solutions
Algebra & Trigonometry With Additional Material From College Algebra Essentials (custom Edition For Tidewater Community College)
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