Chapter 9, Problem 9P

A series RLC circuit with an AC voltage source is shown. The amplitude of the current, I, in this circuit is given by:

$I=\frac{v_m}{\sqrt{R^2+{\omega }_{d}L-1/(}{\omega }_{d}C){]}^2}$

where ${\omega }_d=2\pi f_d$ , in which f_dis the driving frequency: R and C are the resistance of the resistor and capacitance of the capacitor, respectively; and v_m, is the amplitude of V For the circuit in the figure R = 80O, C = 18×10-⁶F, L = 260× 10-3, and v_m= 10 V.

Determine f_dfor which I =0.1 A. (There are two solutions.)