Table 11.5 asserts, without proof, that in several cases, the Taylor series for f converges to f at the endpoints of the interval of convergence. Proving convergence at the endpoints generally requires advanced techniques. It may also be done using the following theorem: Suppose the Taylor series for f entered at 0 converges to f on the interval (-R, R). If the series converges at x = R, then it converges to lim f(x). Table 11.5 = 1 + x + x? + + x* Σxt. for 지 < 1 k=0 1- x + x? - ... + (-1)*r* + - E(-1)*r*, for |x| < 1 k=0 x2 et = 1 +x + 2! Σ for x| < 0 k! k!' k=0 (-1)*x*+1 Eo (2k + 1)! х3 sin x = x - 3! (-1)*x*+1 for |x| < 0 If the series converges at x = -R, then it 5! (2k + 1)! converges to lim f(x). x--R (-1)*x* Σ (2k)! Forexample, this theorem would x² cos x = 1 (-1)*x* for x| < 0 allow us to conclude that the series for (2k)! In (1 + x) converges to In 2 at x = 1. (-1)*+l,* Σ x2 x3 (-1)*+1x* In (1 + x) = for -1
Table 11.5 asserts, without proof, that in several cases, the Taylor series for f converges to f at the endpoints of the interval of convergence. Proving convergence at the endpoints generally requires advanced techniques. It may also be done using the following theorem: Suppose the Taylor series for f entered at 0 converges to f on the interval (-R, R). If the series converges at x = R, then it converges to lim f(x). Table 11.5 = 1 + x + x? + + x* Σxt. for 지 < 1 k=0 1- x + x? - ... + (-1)*r* + - E(-1)*r*, for |x| < 1 k=0 x2 et = 1 +x + 2! Σ for x| < 0 k! k!' k=0 (-1)*x*+1 Eo (2k + 1)! х3 sin x = x - 3! (-1)*x*+1 for |x| < 0 If the series converges at x = -R, then it 5! (2k + 1)! converges to lim f(x). x--R (-1)*x* Σ (2k)! Forexample, this theorem would x² cos x = 1 (-1)*x* for x| < 0 allow us to conclude that the series for (2k)! In (1 + x) converges to In 2 at x = 1. (-1)*+l,* Σ x2 x3 (-1)*+1x* In (1 + x) = for -1
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Manipulating Taylor series Use the Taylor series in Table 11.5 to find the first four nonzero terms of the Taylor series for the following functions centered at 0.
![Table 11.5 asserts, without proof, that
in several cases, the Taylor series for
f converges to f at the endpoints of
the interval of convergence. Proving
convergence at the endpoints generally
requires advanced techniques. It may also
be done using the following theorem:
Suppose the Taylor series for f
entered at 0 converges to f on the
interval (-R, R). If the series converges
at x = R, then it converges to lim f(x).
Table 11.5
= 1 + x + x? +
+ x*
Σxt. for 지 < 1
k=0
1- x + x? - ... + (-1)*r* + -
E(-1)*r*, for |x| < 1
k=0
x2
et = 1 +x +
2!
Σ
for x| < 0
k!
k!'
k=0
(-1)*x*+1
Eo (2k + 1)!
х3
sin x = x -
3!
(-1)*x*+1
for |x| < 0
If the series converges at x = -R, then it
5!
(2k + 1)!
converges to lim f(x).
x--R
(-1)*x*
Σ
(2k)!
Forexample, this theorem would
x²
cos x = 1
(-1)*x*
for x| < 0
allow us to conclude that the series for
(2k)!
In (1 + x) converges to In 2 at x = 1.
(-1)*+l,*
Σ
x2
x3
(-1)*+1x*
In (1 + x) =
for -1 <xs1
k=1
x x3
x*
-In (1 - x) = x +
for -1 sx <1
... %3D
k=1
(-1)*x*+1
Σ
(-1)* x*+1
tanx = x
for |x| s 1
2k + 1
2k + 1
x*+1
x2k+1
Σ
for |x| < 0
sinh x = x +
5!
(2k + 1)!
(2k + 1)!'
x*
cosh x
for |x| < 0
+..
2!
4!
(2k)!
(2k)!"
moted in Theorem 11.6 the hinoial
erieay converge to (1 at
+1 denendine on the value of a
(3)
p(p – 1)(p – 2) - (p – k + 1)
(1 + x)P = E()x
2(3) -
r*, for x| < 1 and
k!](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fdc3129f7-2d7f-4829-a375-c36dfc03af17%2F231e77a1-1ded-49f4-9f24-5dbceb36b1d2%2Fcqdyhy8.png&w=3840&q=75)
Transcribed Image Text:Table 11.5 asserts, without proof, that
in several cases, the Taylor series for
f converges to f at the endpoints of
the interval of convergence. Proving
convergence at the endpoints generally
requires advanced techniques. It may also
be done using the following theorem:
Suppose the Taylor series for f
entered at 0 converges to f on the
interval (-R, R). If the series converges
at x = R, then it converges to lim f(x).
Table 11.5
= 1 + x + x? +
+ x*
Σxt. for 지 < 1
k=0
1- x + x? - ... + (-1)*r* + -
E(-1)*r*, for |x| < 1
k=0
x2
et = 1 +x +
2!
Σ
for x| < 0
k!
k!'
k=0
(-1)*x*+1
Eo (2k + 1)!
х3
sin x = x -
3!
(-1)*x*+1
for |x| < 0
If the series converges at x = -R, then it
5!
(2k + 1)!
converges to lim f(x).
x--R
(-1)*x*
Σ
(2k)!
Forexample, this theorem would
x²
cos x = 1
(-1)*x*
for x| < 0
allow us to conclude that the series for
(2k)!
In (1 + x) converges to In 2 at x = 1.
(-1)*+l,*
Σ
x2
x3
(-1)*+1x*
In (1 + x) =
for -1 <xs1
k=1
x x3
x*
-In (1 - x) = x +
for -1 sx <1
... %3D
k=1
(-1)*x*+1
Σ
(-1)* x*+1
tanx = x
for |x| s 1
2k + 1
2k + 1
x*+1
x2k+1
Σ
for |x| < 0
sinh x = x +
5!
(2k + 1)!
(2k + 1)!'
x*
cosh x
for |x| < 0
+..
2!
4!
(2k)!
(2k)!"
moted in Theorem 11.6 the hinoial
erieay converge to (1 at
+1 denendine on the value of a
(3)
p(p – 1)(p – 2) - (p – k + 1)
(1 + x)P = E()x
2(3) -
r*, for x| < 1 and
k!
![1
37.
1- 2x](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fdc3129f7-2d7f-4829-a375-c36dfc03af17%2F231e77a1-1ded-49f4-9f24-5dbceb36b1d2%2F61kdde.png&w=3840&q=75)
Transcribed Image Text:1
37.
1- 2x
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