Chapter 9, Problem 9.85CP

Interpretation Introduction

Interpretation:

Express the given concentration in terms of $\text{(m/v)\%}$, $ppm$ and molarity

Concept Introduction:

In order to express the concentration, many units have been used. One among them is molarity, defined as number of moles of solute divided by number of liters of solution.

Given by,

$Molarity(M)=\frac{Numberofmoles}{Litersofsolution}$

$\text{Mass/volume}\text{percent}\text{concentration(m/v)\%}$, defined as number of grams of solute dissolved in $\text{100mL}$ of solution.

$\text{(m/v)\% =}\frac{\text{Mass of solute(g)}}{Volume\text{of}\text{solution(mL)}}\text{×100}$

Parts per million $(ppm)$ defines as one milligram of solute per liter of solution or one milligram of solute per kilogram of solution.

Expressed as,

$\text{1}\text{ppm}\text{=}\frac{\text{1}\text{mg}\text{solute}}{\text{1}\text{L}\text{solution}}\text{=}\frac{\text{1}\text{mg}\text{solute}}{\text{1}\text{kg}\text{solution}}$