The correct diagram that matches the given statements

Question

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Answer 1

Question

Chapter 9, Problem 9.77UTC

Interpretation Introduction

To Determine: The correct diagram that matches the given statements

Expert Solution & Answer

Answer to Problem 9.77UTC

Solution:

a) Diagram 1

b) Diagram 2

c) Diagram 1

Explanation of Solution

“Like dissolves like”. In other words, a polar solute will dissolve in a polar solvent. And, a non-polar solute will dissolve in a non-polar solvent.

Given: a polar solute and a polar solvent

Diagram 1 depicts this scenario. Here both solute and solvent have the same nature i.e. they are polar. In diagram 1, the pink and blue balls are uniformly dispersed indicating that they mix with each other or can be dissolved.

Given: a non-polar solute and a polar solvent

Diagram 2 depicts this scenario. Here the solute is non-polar while the solvent is polar. Since the two are different, they will not mix and tend to separate out into two layers like the orange and blue balls shown in diagram 2.

Given: a non-polar solute and a non-polar solvent

Diagram 1 depicts this scenario. Here both solute and solvent have the same nature i.e. they are non-polar. Again as shown in diagram 1, the pink and blue balls are uniformly dispersed indicating that they mix with each other or can be dissolved.

Conclusion

Diagram 1 depicts a solution containing a polar solute and polar solvent

Diagram 2 depicts a solution containing a non-polar solute and polar solvent

Diagram 1 depicts a solution containing a non-polar solute and non-polar solvent

CHEMISTRY: AN INTRODUCTION TO GENERAL, O, Chapter 9, Problem 9.77UTC

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Students have asked these similar questions

(c) The following data have been obtained for the hydrolysis of sucrose, C12H22O11, to glucose, C6H12O6, and fructose C6H12O6, in acidic solution: C12H22O11 + H2O → C6H12O6 + C6H12O6 [sucrose]/mol dm³ t/min 0 0.316 14 0.300 39 0.274 60 0.256 80 0.238 110 0.211 (i) Graphically prove the order of the reaction and determine the rate constant of the reaction. (ii) Determine the half-life, t½ for the hydrolysis of sucrose.

(III) adsorbent (b) Adsorption of the hexacyanoferrate (III) ion, [Fe(CN)6] ³, on y-Al2O3 from aqueous solution was examined. The adsorption was modelled using a modified Langmuir isotherm, yielding the following values of Kat pH = 6.5: (ii) T/K 10-10 K 280 2.505 295 1.819 310 1.364 325 1.050 Determine the enthalpy of adsorption, AadsHⓇ. If the reported value of entropy of adsorption, Aads Se = 146 J K-1 mol-1 under the above conditions, determine Aads Gº.

with full details solution please

Answer 2

Question

Chapter 9, Problem 9.77UTC

Interpretation Introduction

To Determine: The correct diagram that matches the given statements

Expert Solution & Answer

Answer to Problem 9.77UTC

Solution:

a) Diagram 1

b) Diagram 2

c) Diagram 1

Explanation of Solution

“Like dissolves like”. In other words, a polar solute will dissolve in a polar solvent. And, a non-polar solute will dissolve in a non-polar solvent.

Given: a polar solute and a polar solvent

Diagram 1 depicts this scenario. Here both solute and solvent have the same nature i.e. they are polar. In diagram 1, the pink and blue balls are uniformly dispersed indicating that they mix with each other or can be dissolved.

Given: a non-polar solute and a polar solvent

Diagram 2 depicts this scenario. Here the solute is non-polar while the solvent is polar. Since the two are different, they will not mix and tend to separate out into two layers like the orange and blue balls shown in diagram 2.

Given: a non-polar solute and a non-polar solvent

Diagram 1 depicts this scenario. Here both solute and solvent have the same nature i.e. they are non-polar. Again as shown in diagram 1, the pink and blue balls are uniformly dispersed indicating that they mix with each other or can be dissolved.

Conclusion

Diagram 1 depicts a solution containing a polar solute and polar solvent

Diagram 2 depicts a solution containing a non-polar solute and polar solvent

Diagram 1 depicts a solution containing a non-polar solute and non-polar solvent

CHEMISTRY: AN INTRODUCTION TO GENERAL, O, Chapter 9, Problem 9.77UTC

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Answer 3

Question

Chapter 9, Problem 9.77UTC

Interpretation Introduction

To Determine: The correct diagram that matches the given statements

Expert Solution & Answer

Answer to Problem 9.77UTC

Solution:

a) Diagram 1

b) Diagram 2

c) Diagram 1

Explanation of Solution

“Like dissolves like”. In other words, a polar solute will dissolve in a polar solvent. And, a non-polar solute will dissolve in a non-polar solvent.

Given: a polar solute and a polar solvent

Diagram 1 depicts this scenario. Here both solute and solvent have the same nature i.e. they are polar. In diagram 1, the pink and blue balls are uniformly dispersed indicating that they mix with each other or can be dissolved.

Given: a non-polar solute and a polar solvent

Diagram 2 depicts this scenario. Here the solute is non-polar while the solvent is polar. Since the two are different, they will not mix and tend to separate out into two layers like the orange and blue balls shown in diagram 2.

Given: a non-polar solute and a non-polar solvent

Diagram 1 depicts this scenario. Here both solute and solvent have the same nature i.e. they are non-polar. Again as shown in diagram 1, the pink and blue balls are uniformly dispersed indicating that they mix with each other or can be dissolved.

Conclusion

Diagram 1 depicts a solution containing a polar solute and polar solvent

Diagram 2 depicts a solution containing a non-polar solute and polar solvent

Diagram 1 depicts a solution containing a non-polar solute and non-polar solvent

CHEMISTRY: AN INTRODUCTION TO GENERAL, O, Chapter 9, Problem 9.77UTC

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Answer 4

Question

Chapter 9, Problem 9.77UTC

Interpretation Introduction

To Determine: The correct diagram that matches the given statements

Expert Solution & Answer

Answer to Problem 9.77UTC

Solution:

a) Diagram 1

b) Diagram 2

c) Diagram 1

Explanation of Solution

“Like dissolves like”. In other words, a polar solute will dissolve in a polar solvent. And, a non-polar solute will dissolve in a non-polar solvent.

Given: a polar solute and a polar solvent

Diagram 1 depicts this scenario. Here both solute and solvent have the same nature i.e. they are polar. In diagram 1, the pink and blue balls are uniformly dispersed indicating that they mix with each other or can be dissolved.

Given: a non-polar solute and a polar solvent

Diagram 2 depicts this scenario. Here the solute is non-polar while the solvent is polar. Since the two are different, they will not mix and tend to separate out into two layers like the orange and blue balls shown in diagram 2.

Given: a non-polar solute and a non-polar solvent

Diagram 1 depicts this scenario. Here both solute and solvent have the same nature i.e. they are non-polar. Again as shown in diagram 1, the pink and blue balls are uniformly dispersed indicating that they mix with each other or can be dissolved.

Conclusion

Diagram 1 depicts a solution containing a polar solute and polar solvent

Diagram 2 depicts a solution containing a non-polar solute and polar solvent

Diagram 1 depicts a solution containing a non-polar solute and non-polar solvent

CHEMISTRY: AN INTRODUCTION TO GENERAL, O, Chapter 9, Problem 9.77UTC

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Answer 5

Chapter 9, Problem 9.77UTC

Interpretation Introduction

To Determine: The correct diagram that matches the given statements

Expert Solution & Answer

Answer to Problem 9.77UTC

Solution:

a) Diagram 1

b) Diagram 2

c) Diagram 1

Explanation of Solution

“Like dissolves like”. In other words, a polar solute will dissolve in a polar solvent. And, a non-polar solute will dissolve in a non-polar solvent.

Given: a polar solute and a polar solvent

Diagram 1 depicts this scenario. Here both solute and solvent have the same nature i.e. they are polar. In diagram 1, the pink and blue balls are uniformly dispersed indicating that they mix with each other or can be dissolved.

Given: a non-polar solute and a polar solvent

Diagram 2 depicts this scenario. Here the solute is non-polar while the solvent is polar. Since the two are different, they will not mix and tend to separate out into two layers like the orange and blue balls shown in diagram 2.

Given: a non-polar solute and a non-polar solvent

Diagram 1 depicts this scenario. Here both solute and solvent have the same nature i.e. they are non-polar. Again as shown in diagram 1, the pink and blue balls are uniformly dispersed indicating that they mix with each other or can be dissolved.

Conclusion

Diagram 1 depicts a solution containing a polar solute and polar solvent

Diagram 2 depicts a solution containing a non-polar solute and polar solvent

Diagram 1 depicts a solution containing a non-polar solute and non-polar solvent

CHEMISTRY: AN INTRODUCTION TO GENERAL, O, Chapter 9, Problem 9.77UTC

Answer 6

Chapter 9, Problem 9.77UTC

Interpretation Introduction

To Determine: The correct diagram that matches the given statements

Expert Solution & Answer

Answer to Problem 9.77UTC

Solution:

a) Diagram 1

b) Diagram 2

c) Diagram 1

Explanation of Solution

“Like dissolves like”. In other words, a polar solute will dissolve in a polar solvent. And, a non-polar solute will dissolve in a non-polar solvent.

Given: a polar solute and a polar solvent

Diagram 1 depicts this scenario. Here both solute and solvent have the same nature i.e. they are polar. In diagram 1, the pink and blue balls are uniformly dispersed indicating that they mix with each other or can be dissolved.

Given: a non-polar solute and a polar solvent

Diagram 2 depicts this scenario. Here the solute is non-polar while the solvent is polar. Since the two are different, they will not mix and tend to separate out into two layers like the orange and blue balls shown in diagram 2.

Given: a non-polar solute and a non-polar solvent

Diagram 1 depicts this scenario. Here both solute and solvent have the same nature i.e. they are non-polar. Again as shown in diagram 1, the pink and blue balls are uniformly dispersed indicating that they mix with each other or can be dissolved.

Conclusion

Diagram 1 depicts a solution containing a polar solute and polar solvent

Diagram 2 depicts a solution containing a non-polar solute and polar solvent

Diagram 1 depicts a solution containing a non-polar solute and non-polar solvent

CHEMISTRY: AN INTRODUCTION TO GENERAL, O, Chapter 9, Problem 9.77UTC

Answer 7

Chapter 9, Problem 9.77UTC

Interpretation Introduction

To Determine: The correct diagram that matches the given statements

Answer 8

Expert Solution & Answer

Answer to Problem 9.77UTC

Solution:

a) Diagram 1

b) Diagram 2

c) Diagram 1

Answer 9

Expert Solution & Answer

Answer 10

Expert Solution & Answer

Answer 11

Explanation of Solution

“Like dissolves like”. In other words, a polar solute will dissolve in a polar solvent. And, a non-polar solute will dissolve in a non-polar solvent.

Given: a polar solute and a polar solvent

Diagram 1 depicts this scenario. Here both solute and solvent have the same nature i.e. they are polar. In diagram 1, the pink and blue balls are uniformly dispersed indicating that they mix with each other or can be dissolved.

Given: a non-polar solute and a polar solvent

Diagram 2 depicts this scenario. Here the solute is non-polar while the solvent is polar. Since the two are different, they will not mix and tend to separate out into two layers like the orange and blue balls shown in diagram 2.

Given: a non-polar solute and a non-polar solvent

Diagram 1 depicts this scenario. Here both solute and solvent have the same nature i.e. they are non-polar. Again as shown in diagram 1, the pink and blue balls are uniformly dispersed indicating that they mix with each other or can be dissolved.