Explanation Ca(s) → Ca(g) ΔH s =+178 kJ Ca(g) → Ca + (g) IE =+590 kJ Ca + (g) → Ca 2+ (g) IE =+1145 kJ 1 2 O 2 (g) → O(g) ΔH b =+71 kJ O(g) → O − (g) EA = −141 KJ O − (g) → O 2− (g) EA = 744 kJ Ca(s)+ 1 2 O 2 (g) − CaO(s) ΔH

Pearson eText for Chemistry: structures and Properties -- Instant Access (Pearson+)

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ISBN: 9780136951537

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Chapter 9, Problem 96E

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Lattice energy of CaO using born-Haber cycle

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Chapter 9, Problem 95E

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Lattice energy of CaO using born-Haber cycle

Solution Summary: The author explains that the lattice energy of CaO is 3222 kJ/mol.

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To determine:

Lattice energy of CaO using born-Haber cycle