Integrate Planck’s law (equation 9.23) from the wavelength limits λ = 0 to λ = ∞ to get equation 9.24. You will have to rewrite the expression by redefining the variable (and its infinitesimal) and use the following integral: ∫ 0 ∞ ( x 3 e x − 1 ) d x = π 4 15 (9.43)
Integrate Planck’s law (equation 9.23) from the wavelength limits λ = 0 to λ = ∞ to get equation 9.24. You will have to rewrite the expression by redefining the variable (and its infinitesimal) and use the following integral: ∫ 0 ∞ ( x 3 e x − 1 ) d x = π 4 15 (9.43)
Solution Summary: The author explains that the Planck's law (equation 9.23) is to be integrated to obtain equation 9.24.
Integrate Planck’s law (equation 9.23) from the wavelength limits
λ
=
0
to
λ
=
∞
to get equation 9.24. You will have to rewrite the expression by redefining the variable (and its infinitesimal) and use the following integral:
I have a excitation/emission spectra of a quinine standard solution here, and I'm having trouble interpreting it. the red line is emission the blue line is excitation. i'm having trouble interpreting properly. just want to know if there is any evidence of raman or rayleigh peaks in the spectra.
Give the major product of the following reaction.
excess
1. OH, H₂O
1.OH
H
CH3CH2CH21
H
2. A.-H₂O
Draw the molecule on the canvas by choosing buttons from the Tools (for bonds), Atoms, and
Advanced Template toolbars. The single bond is active by default.
2. Use Hess's law to calculate the AH
(in kJ) for:
rxn
CIF(g) + F2(g) →
CIF 3 (1)
using the following information:
2CIF(g) + O2(g) →
Cl₂O(g) + OF 2(g)
AH = 167.5 kJ
ΔΗ
2F2 (g) + O2(g) → 2 OF 2(g)
2C1F3 (1) + 202(g) → Cl₂O(g) + 3 OF 2(g)
о
=
= -43.5 kJ
AH = 394.1kJ
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The Bohr Model of the atom and Atomic Emission Spectra: Atomic Structure tutorial | Crash Chemistry; Author: Crash Chemistry Academy;https://www.youtube.com/watch?v=apuWi_Fbtys;License: Standard YouTube License, CC-BY