Concept explainers
(a)
Interpretation:
The main group of
Concept introduction:
An ionic bond is formed by the interaction of a metal with a non-metal. When a metal element interacts with a non-metal, the metal loses electron/electrons. The electrons lost are gained by the nonmetal. The metal turns into a cation whereas the non-metal turns into an anion. The electrostatic force of attraction between the cation and the anion leads to the formation of an ionic bond between the two. The constituents in an ionic compound are ions.
In an ionic compound, the ions are bonded to each other by ionic bonds and get separates in the water to form cations and anions.
The group number of the cation is the charge present on the cation in that compound and the group number in case of the anion is calculated as,
(b)
Interpretation:
The main group of
Concept introduction:
An ionic bond is formed by the interaction of a metal with a non-metal. When a metal element interacts with a non-metal, the metal loses electron/electrons. The electrons lost are gained by the nonmetal. The metal turns into a cation whereas the non-metal turns into an anion. The electrostatic force of attraction between the cation and the anion leads to the formation of an ionic bond between the two. The constituents in an ionic compound are ions.
In an ionic compound, the ions are bonded to each other by ionic bonds and get separates in the water to form cations and anions.
The group number of the cation is the charge present on the cation in that compound and the group number in case of the anion is calculated as follows:
(c)
Interpretation:
The main group of
Concept introduction:
An ionic bond is formed by the interaction of a metal with a non-metal. When a metal element interacts with a non-metal, the metal loses electron/electrons. The electrons lost are gained by the nonmetal. The metal turns into a cation whereas the non-metal turns into an anion. The electrostatic force of attraction between the cation and the anion leads to the formation of an ionic bond between the two. The constituents in an ionic compound are ions.
In an ionic compound, the ions are bonded to each other by ionic bonds and get separates in the water to form cations and anions.
The group number of the cation is the charge present on the cation in that compound and the group number in case of the anion is calculated as follows:

Want to see the full answer?
Check out a sample textbook solution
Chapter 9 Solutions
CHEMISTRY: MOLECULAR NATURE ALEKS ACCESS
- 9. Write Me product as well as the reaction Mechanism For each of the Following Vanctions +H₂504 4.50+ T C. +212 Fellz 237 b. Praw the potential energy Diagrams For each OF Mese Rauctions and account For any differences that appear in the two potential Puergy Diagrams which of here two reactions 19 Found to be Reversable, Rationalice your answer based upon the venation mechanisms and the potential energy diagrams.arrow_forward9. Write Me product as well as the reaction Mechanism For each of the Following Veritious +H2504 4.50+ + 1/₂ Felly ◎+ 7 b. Praw he potential energy Diagrams For each OF Mese Ronctions and account for any differences that appeak in the two potential Puergy Diagramsarrow_forwardDraw the major product of this reaction. Ignore inorganic byproducts. Incorrect, 3 attempts remaining 1. excess Br2, NaOH 2. neutralizing workup Qarrow_forward
- Given the electrode Pt | Ag | Ag+ (aq), describe it.arrow_forwardAt 25°C, the reaction Zn2+ + 2e ⇄ Zn has a normal equilibrium potential versus the saturated calomel electrode of -1.0048 V. Determine the normal equilibrium potential of Zn versus the hydrogen electrode.Data: The calomel electrode potential is E° = 0.2420 V versus the normal hydrogen electrode.arrow_forwardElectrochemistry. State the difference between E and E0.arrow_forward
- In an electrolytic cell, the positive pole is always assumed to be on the right side of the battery notation. Is that correct?arrow_forwardIn an electrolytic cell, the positive pole is always assumed to be on the right side of the battery. Is that correct?arrow_forwardCalculate the free energy of formation of 1 mol of Cu in cells where the electrolyte is 1 mol dm-3 Cu2+ in sulfate solution, pH 0. E° for the Cu2+/Cu pair in this medium is +142 mV versus ENH.Assume the anodic reaction is oxygen evolution.Data: EH2 = -0.059 pH (V) and EO2 = 1.230 - 0.059 pH (V); 2.3RT/F = 0.059 Varrow_forward
- If the normal potential for the Fe(III)/Fe(II) pair in acid at zero pH is 524 mV Hg/Hg2Cl2 . The potential of the saturated calomel reference electrode is +246 mV versus the NHE. Calculate E0 vs NHE.arrow_forwardGiven the galvanic cell whose scheme is: (-) Zn/Zn2+ ⋮⋮ Ag+/Ag (+). If we know the normal potentials E°(Zn2+/Zn) = -0.76V and E°(Ag+/Ag) = 0.799 V. Indicate the electrodes that are the anode and the cathode and calculate the E0battery.arrow_forwardIndicate the functions that salt bridges have in batteries.arrow_forward
- ChemistryChemistryISBN:9781305957404Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCostePublisher:Cengage LearningChemistryChemistryISBN:9781259911156Author:Raymond Chang Dr., Jason Overby ProfessorPublisher:McGraw-Hill EducationPrinciples of Instrumental AnalysisChemistryISBN:9781305577213Author:Douglas A. Skoog, F. James Holler, Stanley R. CrouchPublisher:Cengage Learning
- Organic ChemistryChemistryISBN:9780078021558Author:Janice Gorzynski Smith Dr.Publisher:McGraw-Hill EducationChemistry: Principles and ReactionsChemistryISBN:9781305079373Author:William L. Masterton, Cecile N. HurleyPublisher:Cengage LearningElementary Principles of Chemical Processes, Bind...ChemistryISBN:9781118431221Author:Richard M. Felder, Ronald W. Rousseau, Lisa G. BullardPublisher:WILEY





