
Concept explainers
(a)
Probability of observing exactly 400 counts in 1 minute.
(a)

Answer to Problem 9.1P
Probability observing exactly 400, P(n=400) = 0.02
Explanation of Solution
Given:
Mean activity,
Number of counts per minute, n = 400 cpm
Formula used:
Standard deviation
Where, n = number of counts
Probability
Where,
P(n) = probability of finding exactly n
Calculation:
Standard deviation
Probability
Conclusion:
Probability observing exactly 400, P(400) = 0.02
(b)
Probability of measuring 390 − 410 counts in 1 minute?
(b)

Answer to Problem 9.1P
Probability of measuring range (390 − 410) counts is 0.383
Explanation of Solution
Given:
Mean activity,
Count,
Formula used:
Where,
t = test
Calculation:
Test value for 390 counts
Test value for 410counts
The probability of measuring 390 − 410 counts
Conclusion:
The probability of measuring range (390 − 410)counts is 0.383.
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Chapter 9 Solutions
EBK INTRODUCTION TO HEALTH PHYSICS, FIF
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