Explanation Given: 4 −in schedule 40 steel pipe D = 0.3355 f t , Q = 400 g a l / m i n , the value of kinematic viscosity from table A-1, where temperature is 50 ° F ν = 1.40 × 10 − 5 f t 2 / s , Concept Used: Annuity problem requires the velocity flow equation (9-3) U = v [ 1 + 1.43 f + 2.15 f log 10 ( y / r o ) ] Here, Velocity = U , average velocity= v , friction factor = f , D=diameter distance= y Annuity problem requires the Reynolds number by using the following formula: ⇒ N R = v D ρ / η ⇒ N R = v D / ν N R → Reynolds Number, ν → Kinematic viscosity of fluid Calculation: As per the given problem D = 0.3355 f t Annuity problem requires the use of this formula A = π D 2 4 Substitute these values in the formula A = π ( 0.3355 f t ) 2 4 = 0.0884 f t 2 A = 0.0884 f t 2 Annuity problem requires the use of this formula D = 0.3355 f t , A = 0.0884 f t 2 v = Q A , Average velocity= v Q =Discharge Substitute these values in the formula v = 400 g a l / m i n 0.0884 f t × 1 f t 2 449 g a l / min = 10.08 f t / s v = 10.08 f t / s Annuity problem requires the use of this formula v = 10.08 f t / s , D = 0.3355 f t , ν = 1.40 × 10 − 5 f t 2 / s N R = v D / ν Substitute these values in the formula N R = ( 10.08 ) ( 0.3355 ) / 1.40 × 10 − 5 = 2.42 × 10 5 N R = 2.42 × 10 5 The value of ε from table where Reynolds number is ε = 1.5 × 10 − 4 Annuity problem requires the use of this formula ε = 1.5 × 10 − 4 , D = 0.3355 f t ⇒ D ε Substitute these values in the formula ⇒ 0.3355 1.5 × 10 − 4 = 2237 at f = 0.0182 f = 0.0182 Annuity problem requires the use of this formula r o = 0.3355 f t = 0.3355 / 0.083 = 4.026 i n = 4.026 / 2 = 2.013 i n f = 0.0182 , v = 10.08 f t / s , r o = 2.013 i n U = v [ 1 + 1.43 f + 2.15 f log 10 ( y / r o ) ] Substitute these values in the formula U = 10.08 [ 1 + 1.43 0.0182 + 2.15 0.0182 log 10 ( y / r o ) ] U = 10.08 [ 1.193 + 0.290 log 10 ( y / r o ) ] Velocity profile for circular section and flow in noncircular section Annuity problem requires the use of this formula Let, y = 0 U = 10.08 [ 1.193 + 0.290 log 10 ( y / r o ) ] Substitute these values in the formula U = 10.08 [ 1.193 + 0.290 log 10 ( 0 / 0 ) ] = 0 U = 0 Annuity problem requires the use of this formula Let, y = 0

7th Edition

ISBN: 9780132558921

Author: Robert L. Mott, Joseph A. Untener

Publisher: PEARSON

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Chapter 9, Problem 9.16PP

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To compute: several points on the velocity profile.

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Chapter 9, Problem 9.15PP

Chapter 9, Problem 9.17PP

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Chapter 9 Solutions

Applied Fluid Mechanics (7th Edition)

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Ch. 9 - Prob. 9.11PP Ch. 9 - Prob. 9.12PP Ch. 9 - Prob. 9.13PP Ch. 9 - Prob. 9.14PP Ch. 9 - Using Eq. (9-4), compute the ratio of the average...Ch. 9 - Prob. 9.16PP Ch. 9 - Repeat Problem 9.16 for the same conditions,...Ch. 9 - Prob. 9.18PP Ch. 9 - A shell-and-tube heat exchanger is made of two...Ch. 9 - Figure 9.14 shows a heat exchanger in which each...Ch. 9 - Figure 9.15 shows the cross section of a...Ch. 9 - Air with a specific weight of 12.5N/m3 and a...Ch. 9 - Carbon dioxide with a specific weight of...Ch. 9 - Water at 90F flows in the space between 6 in...Ch. 9 - Refer to the shell-and-tube heat exchanger shown...Ch. 9 - Refer to Fig. 9.14, which shows two DN 150...Ch. 9 - Refer to Fig. 9.15, which shows three pipes inside...Ch. 9 - Water at 10C is flowing in the shell shown in Fig....Ch. 9 - Figure 9.19 shows the cross section of a heat...Ch. 9 - Figure 9.20 shows a liquid-to-air heat exchanger...Ch. 9 - Glycerin ( sg=1.26 ) at 40C flows in the portion...Ch. 9 - Each of the square tubes shown in Fig. 9.21...Ch. 9 - A heat sink for an electronic circuit is made by...Ch. 9 - Figure 9.23 shows the cross section of a cooling...Ch. 9 - Prob. 9.35PP Ch. 9 - The blade of a gas turbine engine contains...Ch. 9 - For the system described in Problem 9.24. compute...Ch. 9 - For the shell-and-tube heat exchanger described in...Ch. 9 - For the system described in Problem 9.26 compute...Ch. 9 - For the system described in Problem 9.27 compute...Ch. 9 - For the shell-and-tube heat exchanger described in...Ch. 9 - For the heat exchanger described in Problem 9.29...Ch. 9 - For the glycerin described in Problem 9.31 compute...Ch. 9 - For the flow of water in the square tubes...Ch. 9 - If the heat sink described in Problem 9.33 is 105...Ch. 9 - Compute the energy loss for the flow of water in...Ch. 9 - In Fig. 9.26 ethylene glycol ( sg=1.10 ) at 77F...Ch. 9 - Figure 9.27 shows a duct in which methyl alcohol...Ch. 9 - Prob. 9.49PP Ch. 9 - Figure 9.29 shows a system in which methyl alcohol...Ch. 9 - A simple heat exchanger is made by welding...Ch. 9 - Three surfaces of an instrument package are cooled...Ch. 9 - Figure 9.32 shows a heat exchanger with internal...

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several points on the velocity profile.

Solution Summary: The author explains that the Annuity problem requires the Reynolds number by using the following formula: D=0.3355ft

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To compute: several points on the velocity profile.

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Chapter 9 Solutions