Bond enthalpy of C − C , C − N a n d O − O bonds in C 2 H 6 , N 2 H 4 and H 2 O 2 respectively has to be calculated. The effect caused by the lone pairs on adjacent atoms on strength of bonds has to be outlined. Concept Introduction: Δ H ° refers to change in enthalpy. Change in enthalpy in a reaction and bond energy (BE) are related as, ΔH° = ΣBE(reactants)-ΣBE(products) Hess’s law is applied to calculate the enthalpy changes in a reaction. According to Hess’s law – “The overall enthalpy change of a reaction is equal to the sum of the enthalpy changes involving in each and every individual steps in the reaction.” Thus if a reaction involves ‘n’ steps then enthalpy change Δ H ° of the reaction is, Δ H ° = Δ H 1 ° + Δ H 2 ° + Δ H 3 ° .... + Δ H n °
Bond enthalpy of C − C , C − N a n d O − O bonds in C 2 H 6 , N 2 H 4 and H 2 O 2 respectively has to be calculated. The effect caused by the lone pairs on adjacent atoms on strength of bonds has to be outlined. Concept Introduction: Δ H ° refers to change in enthalpy. Change in enthalpy in a reaction and bond energy (BE) are related as, ΔH° = ΣBE(reactants)-ΣBE(products) Hess’s law is applied to calculate the enthalpy changes in a reaction. According to Hess’s law – “The overall enthalpy change of a reaction is equal to the sum of the enthalpy changes involving in each and every individual steps in the reaction.” Thus if a reaction involves ‘n’ steps then enthalpy change Δ H ° of the reaction is, Δ H ° = Δ H 1 ° + Δ H 2 ° + Δ H 3 ° .... + Δ H n °
Solution Summary: The author explains that Hess's law is applied to calculate the enthalpy changes in a reaction.
Bond enthalpy of C−C,C−NandO−O bonds in C2H6,N2H4 and H2O2 respectively has to be calculated. The effect caused by the lone pairs on adjacent atoms on strength of bonds has to be outlined.
Concept Introduction:
ΔH° refers to change in enthalpy. Change in enthalpy in a reaction and bond energy (BE) are related as,
ΔH°=ΣBE(reactants)-ΣBE(products)
Hess’s law is applied to calculate the enthalpy changes in a reaction. According to Hess’s law – “The overall enthalpy change of a reaction is equal to the sum of the enthalpy changes involving in each and every individual steps in the reaction.” Thus if a reaction involves ‘n’ steps then enthalpy change ΔH° of the reaction is,
At 0oC and 1 atm, the viscosity of hydrogen (gas) is 8.55x10-5 P. Calculate the viscosity of a gas, if possible, consisting of deuterium. Assume that the molecular sizes are equal.
Indicate the correct option for the velocity distribution function of gas molecules:a) its velocity cannot be measured in any other way due to the small size of the gas moleculesb) it is only used to describe the velocity of particles if their density is very high.c) it describes the probability that a gas particle has a velocity in a given interval of velocitiesd) it describes other magnitudes, such as pressure, energy, etc., but not the velocity of the molecules
Indicate the correct option for the velocity distribution function of gas molecules:a) its velocity cannot be measured in any other way due to the small size of the gas moleculesb) it is only used to describe the velocity of particles if their density is very high.c) it describes the probability that a gas particle has a velocity in a given interval of velocitiesd) it describes other magnitudes, such as pressure, energy, etc., but not the velocity of the molecules
Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell
Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell