Bond enthalpy of C − C , C − N a n d O − O bonds in C 2 H 6 , N 2 H 4 and H 2 O 2 respectively has to be calculated. The effect caused by the lone pairs on adjacent atoms on strength of bonds has to be outlined. Concept Introduction: Δ H ° refers to change in enthalpy. Change in enthalpy in a reaction and bond energy (BE) are related as, ΔH° = ΣBE(reactants)-ΣBE(products) Hess’s law is applied to calculate the enthalpy changes in a reaction. According to Hess’s law – “The overall enthalpy change of a reaction is equal to the sum of the enthalpy changes involving in each and every individual steps in the reaction.” Thus if a reaction involves ‘n’ steps then enthalpy change Δ H ° of the reaction is, Δ H ° = Δ H 1 ° + Δ H 2 ° + Δ H 3 ° .... + Δ H n °
Bond enthalpy of C − C , C − N a n d O − O bonds in C 2 H 6 , N 2 H 4 and H 2 O 2 respectively has to be calculated. The effect caused by the lone pairs on adjacent atoms on strength of bonds has to be outlined. Concept Introduction: Δ H ° refers to change in enthalpy. Change in enthalpy in a reaction and bond energy (BE) are related as, ΔH° = ΣBE(reactants)-ΣBE(products) Hess’s law is applied to calculate the enthalpy changes in a reaction. According to Hess’s law – “The overall enthalpy change of a reaction is equal to the sum of the enthalpy changes involving in each and every individual steps in the reaction.” Thus if a reaction involves ‘n’ steps then enthalpy change Δ H ° of the reaction is, Δ H ° = Δ H 1 ° + Δ H 2 ° + Δ H 3 ° .... + Δ H n °
Solution Summary: The author explains that Hess's law is applied to calculate the enthalpy changes in a reaction.
Bond enthalpy of C−C,C−NandO−O bonds in C2H6,N2H4 and H2O2 respectively has to be calculated. The effect caused by the lone pairs on adjacent atoms on strength of bonds has to be outlined.
Concept Introduction:
ΔH° refers to change in enthalpy. Change in enthalpy in a reaction and bond energy (BE) are related as,
ΔH°=ΣBE(reactants)-ΣBE(products)
Hess’s law is applied to calculate the enthalpy changes in a reaction. According to Hess’s law – “The overall enthalpy change of a reaction is equal to the sum of the enthalpy changes involving in each and every individual steps in the reaction.” Thus if a reaction involves ‘n’ steps then enthalpy change ΔH° of the reaction is,
Comparison of experimental data to “known” value. Monna and co-workers used radioactive isotopes to date sediments from lakes and estuaries.21 To verify this method they analyzed a 208Po standard known to have an activity of 77.5 decays/min, obtaining the following results.
77.09, 75.37, 72.42, 76.84, 77.84, 76.69, 78.03, 74.96, 77.54, 76.09, 81.12, 75.75
Do the results differ from the expected results at the 95% confidence interval?
Explain the difference between the propagated uncertainty and the standard deviation. Which number would you use to describe the uncertainty in the measurement? if the standard deviation is 0.01 and the propagated uncertainty is 0.03
Propagation of uncertainty. Find the absolute and percent relative uncertainty assuming the ±-values are random error.
7.65±0.04 + 5.28±0.02 – 1.12±0.01
85.6±0.9 × 50.2±0.7 ÷ 13.8±0.5
[4.88±0.07 + 3.22±0.05] / 1.53±0.02
Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell
Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell