EBK APPLIED FLUID MECHANICS
7th Edition
ISBN: 8220100668340
Author: UNTENER
Publisher: PEARSON
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Chapter 9, Problem 9.13PP
To determine
To compute: the velocity for turbulent flow will be found at distance
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Procedure:1- Cartesian system, 2D3D,type of support2- Free body diagram3 - Find the support reactions4- If you find a negativenumber then flip the force5- Find the internal force3D∑Fx=0∑Fy=0∑Fz=0∑Mx=0∑My=0\Sigma Mz=02D\Sigma Fx=0\Sigma Fy=0\Sigma Mz=05- Use method of sectionand cut the elementwhere you want to find
Procedure:1- Cartesian system, 2D3D,type of support2- Free body diagram3 - Find the support reactions4- If you find a negativenumber then flip the force5- Find the internal force3D∑Fx=0∑Fy=0∑Fz=0∑Mx=0∑My=0\Sigma Mz=02D\Sigma Fx=0\Sigma Fy=0\Sigma Mz=05- Use method of sectionand cut the elementwhere you want to findthe internal force andkeep either side of the
Procedure:
1- Cartesian system, 2D3D,
type of support
2- Free body diagram
3 - Find the support reactions
4- If you find a negative
number then flip the force
5- Find the internal force
3D
∑Fx=0
∑Fy=0
∑Fz=0
∑Mx=0
∑My=0
ΣMz=0
2D
ΣFx=0
ΣFy=0
ΣMz=0
5- Use method of section
and cut the element
where you want to find
the internal force and
keep either side of the
Chapter 9 Solutions
EBK APPLIED FLUID MECHANICS
Ch. 9 - Compute points on the velocity profile from the...Ch. 9 - s9.2 Compute points on the velocity profile from...Ch. 9 - Compute points on the velocity profile from the...Ch. 9 - Compute points on the velocity profile from the...Ch. 9 - A small velocity probe is to be inserted through a...Ch. 9 - If the accuracy of positioning the probe described...Ch. 9 - An alternative scheme for using the velocity probe...Ch. 9 - Prob. 9.8PPCh. 9 - For the flow of 12.9L/min of water at 75C in a...Ch. 9 - A large pipeline with a 1,200m inside diameter...
Ch. 9 - Prob. 9.11PPCh. 9 - Prob. 9.12PPCh. 9 - Prob. 9.13PPCh. 9 - Prob. 9.14PPCh. 9 - Using Eq. (9-4), compute the ratio of the average...Ch. 9 - Prob. 9.16PPCh. 9 - Repeat Problem 9.16 for the same conditions,...Ch. 9 - Prob. 9.18PPCh. 9 - A shell-and-tube heat exchanger is made of two...Ch. 9 - Figure 9.14 shows a heat exchanger in which each...Ch. 9 - Figure 9.15 shows the cross section of a...Ch. 9 - Air with a specific weight of 12.5N/m3 and a...Ch. 9 - Carbon dioxide with a specific weight of...Ch. 9 - Water at 90F flows in the space between 6 in...Ch. 9 - Refer to the shell-and-tube heat exchanger shown...Ch. 9 - Refer to Fig. 9.14, which shows two DN 150...Ch. 9 - Refer to Fig. 9.15, which shows three pipes inside...Ch. 9 - Water at 10C is flowing in the shell shown in Fig....Ch. 9 - Figure 9.19 shows the cross section of a heat...Ch. 9 - Figure 9.20 shows a liquid-to-air heat exchanger...Ch. 9 - Glycerin ( sg=1.26 ) at 40C flows in the portion...Ch. 9 - Each of the square tubes shown in Fig. 9.21...Ch. 9 - A heat sink for an electronic circuit is made by...Ch. 9 - Figure 9.23 shows the cross section of a cooling...Ch. 9 - Prob. 9.35PPCh. 9 - The blade of a gas turbine engine contains...Ch. 9 - For the system described in Problem 9.24. compute...Ch. 9 - For the shell-and-tube heat exchanger described in...Ch. 9 - For the system described in Problem 9.26 compute...Ch. 9 - For the system described in Problem 9.27 compute...Ch. 9 - For the shell-and-tube heat exchanger described in...Ch. 9 - For the heat exchanger described in Problem 9.29...Ch. 9 - For the glycerin described in Problem 9.31 compute...Ch. 9 - For the flow of water in the square tubes...Ch. 9 - If the heat sink described in Problem 9.33 is 105...Ch. 9 - Compute the energy loss for the flow of water in...Ch. 9 - In Fig. 9.26 ethylene glycol ( sg=1.10 ) at 77F...Ch. 9 - Figure 9.27 shows a duct in which methyl alcohol...Ch. 9 - Prob. 9.49PPCh. 9 - Figure 9.29 shows a system in which methyl alcohol...Ch. 9 - A simple heat exchanger is made by welding...Ch. 9 - Three surfaces of an instrument package are cooled...Ch. 9 - Figure 9.32 shows a heat exchanger with internal...
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- Procedure:1- Cartesian system, 2D3D,type of support2- Free body diagram3 - Find the support reactions4- If you find a negativenumber then flip the force5- Find the internal force3D∑Fx=0∑Fy=0∑Fz=0∑Mx=0∑My=0\Sigma Mz=02D\Sigma Fx=0\Sigma Fy=0\Sigma Mz=05- Use method of sectionand cut the elementwhere you want to findthe internal force andkeep either side of thearrow_forwardProcedure: 1- Cartesian system, 2(D)/(3)D, type of support 2- Free body diagram 3 - Find the support reactions 4- If you find a negative number then flip the force 5- Find the internal force 3D \sum Fx=0 \sum Fy=0 \sum Fz=0 \sum Mx=0 \sum My=0 \Sigma Mz=0 2D \Sigma Fx=0 \Sigma Fy=0 \Sigma Mz=0 5- Use method of section and cut the element where you want to find the internal force and keep either side of the sectionarrow_forwardProcedure: 1- Cartesian system, 2(D)/(3)D, type of support 2- Free body diagram 3 - Find the support reactions 4- If you find a negative number then flip the force 5- Find the internal force 3D \sum Fx=0 \sum Fy=0 \sum Fz=0 \sum Mx=0 \sum My=0 \Sigma Mz=0 2D \Sigma Fx=0 \Sigma Fy=0 \Sigma Mz=0 5- Use method of section and cut the element where you want to find the internal force and keep either side of the sectionarrow_forward
- For each system below with transfer function G(s), plot the pole(s) on the s-plane. and indicate whether the system is: (a) "stable" (i.e., a bounded input will always result in a bounded output), (b) "marginally stable," or (c) "unstable" Sketch a rough graph of the time response to a step input. 8 a) G(s) = 5-5 8 b) G(s) = c) G(s) = = s+5 3s + 8 s² - 2s +2 3s +8 d) G(s): = s²+2s+2 3s+8 e) G(s): = s² +9 f) G(s): 8 00 == Sarrow_forwardPlease answer the following question. Include all work and plase explain. Graphs are provided below. "Consider the Mg (Magnesium) - Ni (Nickel) phase diagram shown below. This phase diagram contains two eutectic reactions and two intermediate phases (Mg2Ni and MgNi2). At a temperature of 505oC, determine what the composition of an alloy would need to be to contain a mass fraction of 0.20 Mg and 0.80 Mg2Ni."arrow_forwardThe triangular plate, having a 90∘∘ angle at AA, supports the load PP = 370 lblb as shown in (Figure 1).arrow_forward
- Design a 4-bar linkage to carry the body in Figure 1 through the two positions P1 and P2 at the angles shown in the figure. Use analytical synthesis with the free choice values z = 1.075, q= 210°, ß2 = −27° for left side and s = 1.24, y= 74°, ½ = − 40° for right side. φ 1.236 P2 147.5° 210° 2.138 P1 Figure 1 Xarrow_forwardDesign a 4-bar linkage to carry the body in Figure 1 through the two positions P1 and P2 at the angles shown in the figure. Use analytical synthesis with the free choice values z = 1.075, q= 210°, B₂ = −27° for left side and s = 1.24, y= 74°, ½ = − 40° for right side. 1.236 P2 147.5° 210° P1 Figure 1 2.138 Xarrow_forwardcan you explain how in a coordinate frame transformation: v = {v_n}^T {n-hat} and then it was found that {n-hat} = [C]^T {b-hat} so v_n = {v_n}^T [C]^T {b-hat}, how does that equation go from that to this --> v_n = [C]^T v_barrow_forward
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