In Exercises 1–4, (a) display the data in a
1. The numbers of pass attempts and passing yards for seven professional quarterbacks for a recent regular season (Sourer: National Football League)
a.
To construct: The scatterplot for the variables the numbers of pass attempts and passing yards.
Answer to Problem 9.1.1RE
Output using the MINITAB software is given below:
Explanation of Solution
Given info:
The data shows the numbers of pass attempts (x) and passing yards (y) values.
Calculation:
Software procedure:
Step by step procedure to obtain scatterplot using the MINITAB software:
- Choose Graph > Scatterplot.
- Choose Simple and then click OK.
- Under Y variables, enter a column of Passing yards.
- Under X variables, enter a column of Pass attempts.
- Click OK.
From the scatterplot, it is observed that as pass attempts increases, the passing yards also increases.
b.
To find: The value of the linear correlation coefficient r.
Answer to Problem 9.1.1RE
The linear correlation coefficient r is 0.917.
Explanation of Solution
Calculation:
Correlation coefficient r:
Software procedure:
Step-by-step procedure to obtain the ‘correlation coefficient’ using the MINITAB software:
- Select Stat > Basic Statistics > Correlation.
- In Variables, select Pass attempts and Passing yards from the box on the left.
- Click OK.
Output using the MINITAB software is given below:
Thus, the Pearson correlation of the numbers of pass attempts and passing yards is 0.917 and P-value is 0.004.
c.
To describe: The type of linear association between the numbers of pass attempts and passing yards.
To interpret: The linear association between the numbers of pass attempts and passing yards.
Answer to Problem 9.1.1RE
There is a strong positive linear correlation between the numbers of pass attempts and passing yards.
As the numbers of pass attempts increase then the passing yards also increase.
Explanation of Solution
From, the scatterplot in part (a), it is observed that the horizontal axis represents the numbers of pass attempts and vertical axis represents the numbers of the passing yards. Also, it is observed that the numbers of pass attempts increase then the passing yards also increase. Also, the data points are scattered closely.
From part (b), it is observed that the linear correlation between the numbers of pass attempts and passing yards is 0.917.
Thus, there is a strong positive linear correlation between the numbers of pass attempts and passing yards
Want to see more full solutions like this?
Chapter 9 Solutions
MYLAB STATISTICS: ELEMENTARY STATISTICS
- For context, the images attached below are a question from a June, 2024 past paper in statistical modelingarrow_forwardFor context, the images attached below (question and related graph) are from a February 2024 past paper in statistical modelingarrow_forwardFor context, the images attached below are from a February 2024 past paper in statistical modelingarrow_forward
- For context, the image provided below is a question from a September, 2024 past paper in statistical modelingarrow_forwardFor context, the image below is from a January 2024 past paper in statistical modelingarrow_forwardFor context, the image provided below is a question from a September, 2024 past paper in statistical modelingarrow_forward
- Section 2.2 Subsets 71 Exercise Set 2.2 Practice Exercises In Exercises 1-18, write or in each blank so that the resulting statement is true. 1. {1, 2, 5} {1, 2, 3, 4, 5, 6, 7} 2. {2, 3, 7} {1, 2, 3, 4, 5, 6, 7} 3. {-3, 0, 3} {-4,-3,-1, 1, 3, 4} 4. {-4, 0, 4} 5. {Monday, Friday} {-3, -1, 1, 3} {Saturday, Sunday, Monday, Tuesday, Wednesday} 6. {Mercury, Venus, Earth} {Venus, Earth, Mars, Jupiter} 7. {x/x is a cat} {xx is a black cat} {x|x is a pure-bred dog} ibrary mbers, ause the entire sual 8. {xx is a dog} 9. (c, o, n, v, e, r, s, a, t, i, o, n} {v, o, i, c, e, s, r, a, n, t, o, n} 10. [r, e, v, o, l, u, t, i, o, n} {t, o, l, o, v, e, r, u, i, n} 33. A = {x|x E N and 5 < x < 12} B = {x|x E N and 2 ≤ x ≤ 11} A_ B 34. A = {x|x = N and 3 < x < 10} B = A. {x|x = N and 2 ≤ x ≤ 8} B 35. Ø {7, 8, 9,..., 100} 36. Ø _{101, 102, 103, . . ., 200} 37. [7, 8, 9,...} 38. [101, 102, 103, ...} 39. Ø 40. { } { } e In Exercises 41-54, determine whether each statement is true or false. If…arrow_forwardA = 5.8271 ± 0.1497 = B 1.77872 ± 0.01133 C=0.57729 ± 0.00908 1. Find the relative uncertainty of A, B, and C 2. Find A-3 3. Find 7B 4. Find A + B 5. Find A B-B - 6. Find A * B 7. Find C/B 8. Find 3/A 9. Find A 0.3B - 10. Find C/T 11. Find 1/√A 12. Find AB²arrow_forwardWhy charts,graphs,table??? difference between regression and correlation analysis.arrow_forward
- You’re scrolling through Instagram and you notice that a lot of people are posting selfies. This piques yourcuriosity and you want to estimate the percentage of photos on Instagram that are selfies.(a) (5 points) Is there a “ground truth” for the percentage of selfies on Instagram? Why or why not?(b) (5 points) Is it possible to estimate the ground truth percentage of selfies on Instagram?Irrespective of your answer to the previous question, you decide to pull up n = 250 randomly chosenphotos from your friends’ Instagram accounts and find that 32% of these photos are selfies.(c) (15 points) Determine which of the following is an observation, a variable, a sample statistic (valuecalculated based on the observed sample), or a population parameter.• A photo on Instagram.• Whether or not a photo is a selfie.• Percentage of all photos on Instagram that are selfies.• 32%.(d) (5 points) Based on the sample you collected, do you think 32% is a reliable ballpark estimate for theground truth…arrow_forwardCan you explain this statement below in layman's terms? Secondary Analysis with Generalized Linear Mixed Model with clustering for Hospital Center and ICUvs Ward EnrolmentIn a secondary adjusted analysis we used generalized linear mixed models with random effects forcenter (a stratification variable in the primary analyses). In this analysis, the relative risk for the primaryoutcome of 90-day mortality for 7 versus 14 days of antibiotics was 0.90 (95% Confidence Interval [CI]0.78, 1.05).arrow_forwardIn a crossover trial comparing a new drug to a standard, π denotes the probabilitythat the new one is judged better. It is desired to estimate π and test H0 : π = 0.5against H1 : π = 0.5. In 20 independent observations, the new drug is better eachtime.(a) Find and plot the likelihood function. Give the ML estimate of π (Hint: youmay use the plot function in R)arrow_forward
- Glencoe Algebra 1, Student Edition, 9780079039897...AlgebraISBN:9780079039897Author:CarterPublisher:McGraw HillHolt Mcdougal Larson Pre-algebra: Student Edition...AlgebraISBN:9780547587776Author:HOLT MCDOUGALPublisher:HOLT MCDOUGALBig Ideas Math A Bridge To Success Algebra 1: Stu...AlgebraISBN:9781680331141Author:HOUGHTON MIFFLIN HARCOURTPublisher:Houghton Mifflin Harcourt