Chapter 9, Problem 9.108EP

3

Н.W A smaller power plant produces steam at 3 MPa, 600•C, in the boiler. It keeps the condenser at 45 C by the transfer of 10MW out as heat transfer. The first turbine section expands to 500 kPa, and then flow is reheated followed by the expansion in the low-pressure turbine. Find the reheat temperature so that the turbine output is saturated vapor. For this reheat, find the total turbine power output and the boiler heat transfer. [Answer. (Reheat temperature= 529°C , total turbine power output= 6487 kW, the boiler heat transfer= 16 475 kW)]

When a steam boiler generates saturated steam at 2.5 mpa and the condenser pressure is 20 kpa, what is the Rankine cycle efficiency?Show complete step-by-step process and solution.

A smaller power plant produces 25 kg/s steam at 3 MPa, 600°C in the boiler. It cools the condenser with ocean water so the condenser exit is at 45°C. There is a reheat done at 500 kPa up to 400°C and then expansion in the low pressure turbine. For the engine, find W and e?

C. the steam fiow rate is plant. Kg/hr, find the net power output of the 3. Steam is supplied to a two-stage turbine at 170 bar and 600°C. It expands isentropic ally until it is zero percent moisture. Then it is reheated to 500°C at constant pressure and expanded in the second-stage turbine to the condenser pressure of 0.2 bar. If the isentropic efficiency of the second stage is 80%, calculate the specific steam consumption and thermal efficiency.

In a Rankine cycle, steam leaves the boiler and enters the turbine at 4 MPa, 400C. The condenser pressure is 10 kPa. What is the pump work in kJ/kg?

Steam is delivered to turbine at 5.4 Mpa and 600C. Before condensation at 31C, steam is extracted for feedwater heating at 0.6 Mpa. For an ideal regenerative cycle, find the thermal efficiency. (Attach your T-S and schematic diagram of this problem)

Saturation: Pressures Specifie Volume Sa Internal Energy Sal Ligule Entropy Set. Ligurd Enthalpy Pr Tegp Ligld 10, Sat. Vaper Sal. Liquid Sat Veper Sat. Vapor Erap Er 10 DO06113 .0007 COC3 .co09 01 1.0002 206 136 1.89 1.0001 181 255 3.77 1.0001 159 675 5.45- 1.0001 142 789 00 2.75.3 23753 7.90 23700 2377.9 15.81 2364.7 23806 22.88 23600 2382.9 · O1 25013 2501.4 7.91 24969 2504 8 15.81 2492.5 2508.3 22.89 2488 5 2511.4 0000 9.1562 9.1562 0288 9.0775 9,1064 0575 8.9999 9.0573 ON29 8.9312 9,0:42 .0010 0011 0012 0013 .0014 6.98 1.0002 129 208 8.37 1.0002 118 042 9.66 LO003 108 696 10.86 11.98 29.30 2355.7 2385.0 35.17 23518 2386.9 40.58 2348.1 2388.7 45.60 2344.7 23903 50.31 23416 2391.9 29.30 24849 2514.2 35.17 2481.6 2516.8 40.58 2478.6 2519.1 45.60 2475.7 25213 503I 2473.1 2523.4 1059.R8697 8.9756 1268 8.8140 8.9408 1460 8.7631 8.9091 1637 8.7162 8.8799 1802 8.6727 8.8529 1.0004 100 755 1.0005 93 922 54.71 2338.6 2393.3 58.87 2335.8 2394.7 62.80 2333.2 2396.0 66.53 2330.7 23972 70.09…

In an ideal regenerative cycle, steam enters the turbine at 6 Mpa. 500 °C. Steam is extracted at 0.2 Mpa and 0.275 Mpa. Then leaves the condenser at 0.1 Mpa. Find the efficiency in % IF the mass recirculating inside the cycle is 3.63 kg/s.