Chapter 9, Problem 9.104QP

Interpretation Introduction

Interpretation:

The required volume of $\text{HCl}$ solution to neutralize the given $\text{NaOH}$ and ${\text{Ba(OH)}}_{\text{2}}$ solutions should be calculated.

Concept introduction:

Molarity:

The concentration of the solutions is given by the term of molarity and it is given by ratio between numbers of moles of solute present in litter of solution.

$\text{Molarity}\text{=}\frac{\text{No}\text{.mole}}{\text{volume}\text{(L)}}$

Mole:

The mole of the solute is calculated by multiplication of concentration of solution and volume of the solution and it is,

$\text{Mole}\text{=}\text{Concentration}\text{(M)×}\text{volume}\text{(L)}$