For the given equation, if 4 moles of A is reacted with 2 moles of B, then the correct statement is to be predicted. The reason behind the incorrect statements is to be stated. Concept Introduction: Limiting reagent is the reactant in the chemical reaction which is completely consumed. The amount of product and the excess reactant left in a reaction is determined on the basis of limiting reagent only.

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Answer 1

Question

Chapter 9, Problem 8ALQ

Interpretation Introduction

Interpretation:

For the given equation, if 4 moles of A is reacted with 2 moles of B, then the correct statement is to be predicted. The reason behind the incorrect statements is to be stated.

Concept Introduction:

Limiting reagent is the reactant in the chemical reaction which is completely consumed. The amount of product and the excess reactant left in a reaction is determined on the basis of limiting reagent only.

Expert Solution & Answer

Answer to Problem 8ALQ

The true statement is “A is the limiting reactant because you need 6 moles of A and have 4 moles”.

Explanation of Solution

Reason for true statements: Possibility 1 is correct as in possibility 2 there are negative numbers of moles of A which is not possible.

The mole ratio for A to C or D is 3:1, that is for three moles of A one mole of both C and D are formed. The mole ratio for B to C or D is 1:1, that is for one mole of B one mole of both C and D are formed.

There are two possibilities for the limiting reagent in the given reaction.

Possibility 1

3A + B → C + DBefore 4 2 0 0Change −4 −1.34 +1.34 +1.34After 0 0.66 1.34 1.34

In this case, A is considered as limiting reagent.

Possibility 2

3A + B → C + DBefore 4 2 0 0Change −6 −2 +2 +2After −2 0 2 2

In this case, B is considered as limiting reagent.

Possibility 1 is correct as in possibility 2 there are negative numbers of moles of A which is not possible.

Conclusion

Reason for false statements:

(a) The given statement is not true as the molar mass is not required for determining the limiting reactant.

(c) The given statement is not true because possibility 1 is correct. In possibility 2, there are negative numbers of moles of A which is not possible.

(d) The given statement is not true because possibility 1 is correct. In possibility 2, there are negative numbers of moles of A which is not possible.

(e) The given statement is not true because A acts as limiting reagent.

Explanation:

(a) It is not necessarily true that the limiting reactant is the one with higher molar mass. The limiting reactant is calculated on the basis of stoichiometry of reactants in a chemical reaction.

(c) The mole ratio for A to C or D is 3:1, that is for three moles of A one mole of both C and D are formed. The mole ratio for B to C or D is 1:1, that is for one mole of B one mole of both C and D are formed.

There are two possibilities for the limiting reagent in the given reaction.

Possibility 1

3A + B → C + DBefore 4 2 0 0Change −4 −1.34 +1.34 +1.34After 0 0.66 1.34 1.34

In this case, A is considered as limiting reagent.

Possibility 2

3A + B → C + DBefore 4 2 0 0Change −6 −2 +2 +2After −2 0 2 2

In this case, B is considered as limiting reagent.

Possibility 1 is correct as in possibility 2 there are negative numbers of moles of A which is not possible.

(d) The mole ratio for A to C or D is 3:1, that is for three moles of A one mole of both C and D are formed. The mole ratio for B to C or D is 1:1, that is for one mole of B one mole of both C and D are formed.

There are two possibilities for the limiting reagent in the given reaction.

Possibility 1

3A + B → C + DBefore 4 2 0 0Change −4 −1.34 +1.34 +1.34After 0 0.66 1.34 1.34

In this case, A is considered as limiting reagent.

Possibility 2

3A + B → C + DBefore 4 2 0 0Change −6 −2 +2 +2After −2 0 2 2

In this case, B is considered as limiting reagent.

Possibility 1 is correct as in possibility 2 there are negative numbers of moles of A which is not possible.

(e) The mole ratio for A to C or D is 3:1, that is for three moles of A one mole of both C and D are formed. The mole ratio for B to C or D is 1:1, that is for one mole of B one mole of both C and D are formed.

There are two possibilities for the limiting reagent in the given reaction.

Possibility 1

3A + B → C + DBefore 4 2 0 0Change −4 −1.34 +1.34 +1.34After 0 0.66 1.34 1.34

In this case, A is considered as limiting reagent.

Possibility 2

3A + B → C + DBefore 4 2 0 0Change −6 −2 +2 +2After −2 0 2 2

In this case, B is considered as limiting reagent.

Possibility 1 is correct as in possibility 2 there are negative numbers of moles of A which is not possible.

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how to get limiting reactant and % yield based off this data Compound Mass 6) Volume(mL Ben zaphone-5008 ne Acetic Acid 1. Sam L 2-propanot 8.00 Benzopin- a col 030445 Benzopin a Colone 0.06743 Results Compound Melting Point (°c) Benzopin acol 172°c - 175.8 °c Benzoping to lone 1797-180.9

Assign ALL signals for the proton and carbon NMR spectra on the following pages.

7.5 1.93 2.05 C B A 4 3 5 The Joh. 9 7 8 1 2 7.5 7.0 6.5 6.0 5.5 5.0 4.5 4.0 3.5 3.0 2.5 2.0 1.5 1.0 ppm 9 7 8 0.86 OH 10 4 3 5 1 2 7.5 7.0 6.5 6.0 5.5 5.0 4.5 4.0 3.5 3.0 2.5 2.0 1.5 1.0 ppm 9 7 8 CI 4 3 5 1 2 7.0 6.5 6.0 5.5 5.0 4.5 4.0 3.5 3.0 2.5 2.0 2.21 4.00 1.5 2.00 2.07 1.0 ppm 2.76

Answer 2

Question

Chapter 9, Problem 8ALQ

Interpretation Introduction

Interpretation:

For the given equation, if 4 moles of A is reacted with 2 moles of B, then the correct statement is to be predicted. The reason behind the incorrect statements is to be stated.

Concept Introduction:

Limiting reagent is the reactant in the chemical reaction which is completely consumed. The amount of product and the excess reactant left in a reaction is determined on the basis of limiting reagent only.

Expert Solution & Answer

Answer to Problem 8ALQ

The true statement is “A is the limiting reactant because you need 6 moles of A and have 4 moles”.

Explanation of Solution

Reason for true statements: Possibility 1 is correct as in possibility 2 there are negative numbers of moles of A which is not possible.

The mole ratio for A to C or D is 3:1, that is for three moles of A one mole of both C and D are formed. The mole ratio for B to C or D is 1:1, that is for one mole of B one mole of both C and D are formed.

There are two possibilities for the limiting reagent in the given reaction.

Possibility 1

3A + B → C + DBefore 4 2 0 0Change −4 −1.34 +1.34 +1.34After 0 0.66 1.34 1.34

In this case, A is considered as limiting reagent.

Possibility 2

3A + B → C + DBefore 4 2 0 0Change −6 −2 +2 +2After −2 0 2 2

In this case, B is considered as limiting reagent.

Possibility 1 is correct as in possibility 2 there are negative numbers of moles of A which is not possible.

Conclusion

Reason for false statements:

(a) The given statement is not true as the molar mass is not required for determining the limiting reactant.

(c) The given statement is not true because possibility 1 is correct. In possibility 2, there are negative numbers of moles of A which is not possible.

(d) The given statement is not true because possibility 1 is correct. In possibility 2, there are negative numbers of moles of A which is not possible.

(e) The given statement is not true because A acts as limiting reagent.

Explanation:

(a) It is not necessarily true that the limiting reactant is the one with higher molar mass. The limiting reactant is calculated on the basis of stoichiometry of reactants in a chemical reaction.

(c) The mole ratio for A to C or D is 3:1, that is for three moles of A one mole of both C and D are formed. The mole ratio for B to C or D is 1:1, that is for one mole of B one mole of both C and D are formed.

There are two possibilities for the limiting reagent in the given reaction.

Possibility 1

3A + B → C + DBefore 4 2 0 0Change −4 −1.34 +1.34 +1.34After 0 0.66 1.34 1.34

In this case, A is considered as limiting reagent.

Possibility 2

3A + B → C + DBefore 4 2 0 0Change −6 −2 +2 +2After −2 0 2 2

In this case, B is considered as limiting reagent.

Possibility 1 is correct as in possibility 2 there are negative numbers of moles of A which is not possible.

(d) The mole ratio for A to C or D is 3:1, that is for three moles of A one mole of both C and D are formed. The mole ratio for B to C or D is 1:1, that is for one mole of B one mole of both C and D are formed.

There are two possibilities for the limiting reagent in the given reaction.

Possibility 1

3A + B → C + DBefore 4 2 0 0Change −4 −1.34 +1.34 +1.34After 0 0.66 1.34 1.34

In this case, A is considered as limiting reagent.

Possibility 2

3A + B → C + DBefore 4 2 0 0Change −6 −2 +2 +2After −2 0 2 2

In this case, B is considered as limiting reagent.

Possibility 1 is correct as in possibility 2 there are negative numbers of moles of A which is not possible.

(e) The mole ratio for A to C or D is 3:1, that is for three moles of A one mole of both C and D are formed. The mole ratio for B to C or D is 1:1, that is for one mole of B one mole of both C and D are formed.

There are two possibilities for the limiting reagent in the given reaction.

Possibility 1

3A + B → C + DBefore 4 2 0 0Change −4 −1.34 +1.34 +1.34After 0 0.66 1.34 1.34

In this case, A is considered as limiting reagent.

Possibility 2

3A + B → C + DBefore 4 2 0 0Change −6 −2 +2 +2After −2 0 2 2

In this case, B is considered as limiting reagent.

Possibility 1 is correct as in possibility 2 there are negative numbers of moles of A which is not possible.

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Answer 3

Question

Chapter 9, Problem 8ALQ

Interpretation Introduction

Interpretation:

For the given equation, if 4 moles of A is reacted with 2 moles of B, then the correct statement is to be predicted. The reason behind the incorrect statements is to be stated.

Concept Introduction:

Limiting reagent is the reactant in the chemical reaction which is completely consumed. The amount of product and the excess reactant left in a reaction is determined on the basis of limiting reagent only.

Expert Solution & Answer

Answer to Problem 8ALQ

The true statement is “A is the limiting reactant because you need 6 moles of A and have 4 moles”.

Explanation of Solution

Reason for true statements: Possibility 1 is correct as in possibility 2 there are negative numbers of moles of A which is not possible.

The mole ratio for A to C or D is 3:1, that is for three moles of A one mole of both C and D are formed. The mole ratio for B to C or D is 1:1, that is for one mole of B one mole of both C and D are formed.

There are two possibilities for the limiting reagent in the given reaction.

Possibility 1

3A + B → C + DBefore 4 2 0 0Change −4 −1.34 +1.34 +1.34After 0 0.66 1.34 1.34

In this case, A is considered as limiting reagent.

Possibility 2

3A + B → C + DBefore 4 2 0 0Change −6 −2 +2 +2After −2 0 2 2

In this case, B is considered as limiting reagent.

Possibility 1 is correct as in possibility 2 there are negative numbers of moles of A which is not possible.

Conclusion

Reason for false statements:

(a) The given statement is not true as the molar mass is not required for determining the limiting reactant.

(c) The given statement is not true because possibility 1 is correct. In possibility 2, there are negative numbers of moles of A which is not possible.

(d) The given statement is not true because possibility 1 is correct. In possibility 2, there are negative numbers of moles of A which is not possible.

(e) The given statement is not true because A acts as limiting reagent.

Explanation:

(a) It is not necessarily true that the limiting reactant is the one with higher molar mass. The limiting reactant is calculated on the basis of stoichiometry of reactants in a chemical reaction.

(c) The mole ratio for A to C or D is 3:1, that is for three moles of A one mole of both C and D are formed. The mole ratio for B to C or D is 1:1, that is for one mole of B one mole of both C and D are formed.

There are two possibilities for the limiting reagent in the given reaction.

Possibility 1

3A + B → C + DBefore 4 2 0 0Change −4 −1.34 +1.34 +1.34After 0 0.66 1.34 1.34

In this case, A is considered as limiting reagent.

Possibility 2

3A + B → C + DBefore 4 2 0 0Change −6 −2 +2 +2After −2 0 2 2

In this case, B is considered as limiting reagent.

Possibility 1 is correct as in possibility 2 there are negative numbers of moles of A which is not possible.

(d) The mole ratio for A to C or D is 3:1, that is for three moles of A one mole of both C and D are formed. The mole ratio for B to C or D is 1:1, that is for one mole of B one mole of both C and D are formed.

There are two possibilities for the limiting reagent in the given reaction.

Possibility 1

3A + B → C + DBefore 4 2 0 0Change −4 −1.34 +1.34 +1.34After 0 0.66 1.34 1.34

In this case, A is considered as limiting reagent.

Possibility 2

3A + B → C + DBefore 4 2 0 0Change −6 −2 +2 +2After −2 0 2 2

In this case, B is considered as limiting reagent.

Possibility 1 is correct as in possibility 2 there are negative numbers of moles of A which is not possible.

(e) The mole ratio for A to C or D is 3:1, that is for three moles of A one mole of both C and D are formed. The mole ratio for B to C or D is 1:1, that is for one mole of B one mole of both C and D are formed.

There are two possibilities for the limiting reagent in the given reaction.

Possibility 1

3A + B → C + DBefore 4 2 0 0Change −4 −1.34 +1.34 +1.34After 0 0.66 1.34 1.34

In this case, A is considered as limiting reagent.

Possibility 2

3A + B → C + DBefore 4 2 0 0Change −6 −2 +2 +2After −2 0 2 2

In this case, B is considered as limiting reagent.

Possibility 1 is correct as in possibility 2 there are negative numbers of moles of A which is not possible.

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Answer 4

Question

Chapter 9, Problem 8ALQ

Interpretation Introduction

Interpretation:

For the given equation, if 4 moles of A is reacted with 2 moles of B, then the correct statement is to be predicted. The reason behind the incorrect statements is to be stated.

Concept Introduction:

Limiting reagent is the reactant in the chemical reaction which is completely consumed. The amount of product and the excess reactant left in a reaction is determined on the basis of limiting reagent only.

Expert Solution & Answer

Answer to Problem 8ALQ

The true statement is “A is the limiting reactant because you need 6 moles of A and have 4 moles”.

Explanation of Solution

Reason for true statements: Possibility 1 is correct as in possibility 2 there are negative numbers of moles of A which is not possible.

The mole ratio for A to C or D is 3:1, that is for three moles of A one mole of both C and D are formed. The mole ratio for B to C or D is 1:1, that is for one mole of B one mole of both C and D are formed.

There are two possibilities for the limiting reagent in the given reaction.

Possibility 1

3A + B → C + DBefore 4 2 0 0Change −4 −1.34 +1.34 +1.34After 0 0.66 1.34 1.34

In this case, A is considered as limiting reagent.

Possibility 2

3A + B → C + DBefore 4 2 0 0Change −6 −2 +2 +2After −2 0 2 2

In this case, B is considered as limiting reagent.

Possibility 1 is correct as in possibility 2 there are negative numbers of moles of A which is not possible.

Conclusion

Reason for false statements:

(a) The given statement is not true as the molar mass is not required for determining the limiting reactant.

(c) The given statement is not true because possibility 1 is correct. In possibility 2, there are negative numbers of moles of A which is not possible.

(d) The given statement is not true because possibility 1 is correct. In possibility 2, there are negative numbers of moles of A which is not possible.

(e) The given statement is not true because A acts as limiting reagent.

Explanation:

(a) It is not necessarily true that the limiting reactant is the one with higher molar mass. The limiting reactant is calculated on the basis of stoichiometry of reactants in a chemical reaction.

(c) The mole ratio for A to C or D is 3:1, that is for three moles of A one mole of both C and D are formed. The mole ratio for B to C or D is 1:1, that is for one mole of B one mole of both C and D are formed.

There are two possibilities for the limiting reagent in the given reaction.

Possibility 1

3A + B → C + DBefore 4 2 0 0Change −4 −1.34 +1.34 +1.34After 0 0.66 1.34 1.34

In this case, A is considered as limiting reagent.

Possibility 2

3A + B → C + DBefore 4 2 0 0Change −6 −2 +2 +2After −2 0 2 2

In this case, B is considered as limiting reagent.

Possibility 1 is correct as in possibility 2 there are negative numbers of moles of A which is not possible.

(d) The mole ratio for A to C or D is 3:1, that is for three moles of A one mole of both C and D are formed. The mole ratio for B to C or D is 1:1, that is for one mole of B one mole of both C and D are formed.

There are two possibilities for the limiting reagent in the given reaction.

Possibility 1

3A + B → C + DBefore 4 2 0 0Change −4 −1.34 +1.34 +1.34After 0 0.66 1.34 1.34

In this case, A is considered as limiting reagent.

Possibility 2

3A + B → C + DBefore 4 2 0 0Change −6 −2 +2 +2After −2 0 2 2

In this case, B is considered as limiting reagent.

Possibility 1 is correct as in possibility 2 there are negative numbers of moles of A which is not possible.

(e) The mole ratio for A to C or D is 3:1, that is for three moles of A one mole of both C and D are formed. The mole ratio for B to C or D is 1:1, that is for one mole of B one mole of both C and D are formed.

There are two possibilities for the limiting reagent in the given reaction.

Possibility 1

3A + B → C + DBefore 4 2 0 0Change −4 −1.34 +1.34 +1.34After 0 0.66 1.34 1.34

In this case, A is considered as limiting reagent.

Possibility 2

3A + B → C + DBefore 4 2 0 0Change −6 −2 +2 +2After −2 0 2 2

In this case, B is considered as limiting reagent.

Possibility 1 is correct as in possibility 2 there are negative numbers of moles of A which is not possible.

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Answer 5

Chapter 9, Problem 8ALQ

Interpretation Introduction

Interpretation:

For the given equation, if 4 moles of A is reacted with 2 moles of B, then the correct statement is to be predicted. The reason behind the incorrect statements is to be stated.

Concept Introduction:

Limiting reagent is the reactant in the chemical reaction which is completely consumed. The amount of product and the excess reactant left in a reaction is determined on the basis of limiting reagent only.

Expert Solution & Answer

Answer to Problem 8ALQ

The true statement is “A is the limiting reactant because you need 6 moles of A and have 4 moles”.

Explanation of Solution

Reason for true statements: Possibility 1 is correct as in possibility 2 there are negative numbers of moles of A which is not possible.

The mole ratio for A to C or D is 3:1, that is for three moles of A one mole of both C and D are formed. The mole ratio for B to C or D is 1:1, that is for one mole of B one mole of both C and D are formed.

There are two possibilities for the limiting reagent in the given reaction.

Possibility 1

3A + B → C + DBefore 4 2 0 0Change −4 −1.34 +1.34 +1.34After 0 0.66 1.34 1.34

In this case, A is considered as limiting reagent.

Possibility 2

3A + B → C + DBefore 4 2 0 0Change −6 −2 +2 +2After −2 0 2 2

In this case, B is considered as limiting reagent.

Possibility 1 is correct as in possibility 2 there are negative numbers of moles of A which is not possible.

Conclusion

Reason for false statements:

(a) The given statement is not true as the molar mass is not required for determining the limiting reactant.

(c) The given statement is not true because possibility 1 is correct. In possibility 2, there are negative numbers of moles of A which is not possible.

(d) The given statement is not true because possibility 1 is correct. In possibility 2, there are negative numbers of moles of A which is not possible.

(e) The given statement is not true because A acts as limiting reagent.

Explanation:

(a) It is not necessarily true that the limiting reactant is the one with higher molar mass. The limiting reactant is calculated on the basis of stoichiometry of reactants in a chemical reaction.

(c) The mole ratio for A to C or D is 3:1, that is for three moles of A one mole of both C and D are formed. The mole ratio for B to C or D is 1:1, that is for one mole of B one mole of both C and D are formed.

There are two possibilities for the limiting reagent in the given reaction.

Possibility 1

3A + B → C + DBefore 4 2 0 0Change −4 −1.34 +1.34 +1.34After 0 0.66 1.34 1.34

In this case, A is considered as limiting reagent.

Possibility 2

3A + B → C + DBefore 4 2 0 0Change −6 −2 +2 +2After −2 0 2 2

In this case, B is considered as limiting reagent.

Possibility 1 is correct as in possibility 2 there are negative numbers of moles of A which is not possible.

(d) The mole ratio for A to C or D is 3:1, that is for three moles of A one mole of both C and D are formed. The mole ratio for B to C or D is 1:1, that is for one mole of B one mole of both C and D are formed.

There are two possibilities for the limiting reagent in the given reaction.

Possibility 1

3A + B → C + DBefore 4 2 0 0Change −4 −1.34 +1.34 +1.34After 0 0.66 1.34 1.34

In this case, A is considered as limiting reagent.

Possibility 2

3A + B → C + DBefore 4 2 0 0Change −6 −2 +2 +2After −2 0 2 2

In this case, B is considered as limiting reagent.

Possibility 1 is correct as in possibility 2 there are negative numbers of moles of A which is not possible.

(e) The mole ratio for A to C or D is 3:1, that is for three moles of A one mole of both C and D are formed. The mole ratio for B to C or D is 1:1, that is for one mole of B one mole of both C and D are formed.

There are two possibilities for the limiting reagent in the given reaction.

Possibility 1

3A + B → C + DBefore 4 2 0 0Change −4 −1.34 +1.34 +1.34After 0 0.66 1.34 1.34

In this case, A is considered as limiting reagent.

Possibility 2

3A + B → C + DBefore 4 2 0 0Change −6 −2 +2 +2After −2 0 2 2

In this case, B is considered as limiting reagent.

Possibility 1 is correct as in possibility 2 there are negative numbers of moles of A which is not possible.

Answer 6

Chapter 9, Problem 8ALQ

Interpretation Introduction

Interpretation:

For the given equation, if 4 moles of A is reacted with 2 moles of B, then the correct statement is to be predicted. The reason behind the incorrect statements is to be stated.

Concept Introduction:

Limiting reagent is the reactant in the chemical reaction which is completely consumed. The amount of product and the excess reactant left in a reaction is determined on the basis of limiting reagent only.

Expert Solution & Answer

Answer to Problem 8ALQ

The true statement is “A is the limiting reactant because you need 6 moles of A and have 4 moles”.

Explanation of Solution

Reason for true statements: Possibility 1 is correct as in possibility 2 there are negative numbers of moles of A which is not possible.

The mole ratio for A to C or D is 3:1, that is for three moles of A one mole of both C and D are formed. The mole ratio for B to C or D is 1:1, that is for one mole of B one mole of both C and D are formed.

There are two possibilities for the limiting reagent in the given reaction.

Possibility 1

3A + B → C + DBefore 4 2 0 0Change −4 −1.34 +1.34 +1.34After 0 0.66 1.34 1.34

In this case, A is considered as limiting reagent.

Possibility 2

3A + B → C + DBefore 4 2 0 0Change −6 −2 +2 +2After −2 0 2 2

In this case, B is considered as limiting reagent.

Possibility 1 is correct as in possibility 2 there are negative numbers of moles of A which is not possible.

Conclusion

Reason for false statements:

(a) The given statement is not true as the molar mass is not required for determining the limiting reactant.

(c) The given statement is not true because possibility 1 is correct. In possibility 2, there are negative numbers of moles of A which is not possible.

(d) The given statement is not true because possibility 1 is correct. In possibility 2, there are negative numbers of moles of A which is not possible.

(e) The given statement is not true because A acts as limiting reagent.

Explanation:

(a) It is not necessarily true that the limiting reactant is the one with higher molar mass. The limiting reactant is calculated on the basis of stoichiometry of reactants in a chemical reaction.

(c) The mole ratio for A to C or D is 3:1, that is for three moles of A one mole of both C and D are formed. The mole ratio for B to C or D is 1:1, that is for one mole of B one mole of both C and D are formed.

There are two possibilities for the limiting reagent in the given reaction.

Possibility 1

3A + B → C + DBefore 4 2 0 0Change −4 −1.34 +1.34 +1.34After 0 0.66 1.34 1.34

In this case, A is considered as limiting reagent.

Possibility 2

3A + B → C + DBefore 4 2 0 0Change −6 −2 +2 +2After −2 0 2 2

In this case, B is considered as limiting reagent.

Possibility 1 is correct as in possibility 2 there are negative numbers of moles of A which is not possible.

(d) The mole ratio for A to C or D is 3:1, that is for three moles of A one mole of both C and D are formed. The mole ratio for B to C or D is 1:1, that is for one mole of B one mole of both C and D are formed.

There are two possibilities for the limiting reagent in the given reaction.

Possibility 1

3A + B → C + DBefore 4 2 0 0Change −4 −1.34 +1.34 +1.34After 0 0.66 1.34 1.34

In this case, A is considered as limiting reagent.

Possibility 2

3A + B → C + DBefore 4 2 0 0Change −6 −2 +2 +2After −2 0 2 2

In this case, B is considered as limiting reagent.

Possibility 1 is correct as in possibility 2 there are negative numbers of moles of A which is not possible.

(e) The mole ratio for A to C or D is 3:1, that is for three moles of A one mole of both C and D are formed. The mole ratio for B to C or D is 1:1, that is for one mole of B one mole of both C and D are formed.

There are two possibilities for the limiting reagent in the given reaction.

Possibility 1

3A + B → C + DBefore 4 2 0 0Change −4 −1.34 +1.34 +1.34After 0 0.66 1.34 1.34

In this case, A is considered as limiting reagent.

Possibility 2

3A + B → C + DBefore 4 2 0 0Change −6 −2 +2 +2After −2 0 2 2

In this case, B is considered as limiting reagent.

Possibility 1 is correct as in possibility 2 there are negative numbers of moles of A which is not possible.

Answer 7

Chapter 9, Problem 8ALQ

Interpretation Introduction

Interpretation:

For the given equation, if 4 moles of A is reacted with 2 moles of B, then the correct statement is to be predicted. The reason behind the incorrect statements is to be stated.

Concept Introduction:

Limiting reagent is the reactant in the chemical reaction which is completely consumed. The amount of product and the excess reactant left in a reaction is determined on the basis of limiting reagent only.

Answer 8

Expert Solution & Answer

Answer to Problem 8ALQ

The true statement is “A is the limiting reactant because you need 6 moles of A and have 4 moles”.

Answer 9

Expert Solution & Answer

Answer 10

Expert Solution & Answer

Answer 11

Explanation of Solution

Reason for true statements: Possibility 1 is correct as in possibility 2 there are negative numbers of moles of A which is not possible.

The mole ratio for A to C or D is 3:1, that is for three moles of A one mole of both C and D are formed. The mole ratio for B to C or D is 1:1, that is for one mole of B one mole of both C and D are formed.

There are two possibilities for the limiting reagent in the given reaction.

Possibility 1

3A + B → C + DBefore 4 2 0 0Change −4 −1.34 +1.34 +1.34After 0 0.66 1.34 1.34

In this case, A is considered as limiting reagent.

Possibility 2

3A + B → C + DBefore 4 2 0 0Change −6 −2 +2 +2After −2 0 2 2

In this case, B is considered as limiting reagent.

Possibility 1 is correct as in possibility 2 there are negative numbers of moles of A which is not possible.

Answer 12

Conclusion

Reason for false statements:

(a) The given statement is not true as the molar mass is not required for determining the limiting reactant.

(c) The given statement is not true because possibility 1 is correct. In possibility 2, there are negative numbers of moles of A which is not possible.

(d) The given statement is not true because possibility 1 is correct. In possibility 2, there are negative numbers of moles of A which is not possible.

(e) The given statement is not true because A acts as limiting reagent.

Explanation:

(a) It is not necessarily true that the limiting reactant is the one with higher molar mass. The limiting reactant is calculated on the basis of stoichiometry of reactants in a chemical reaction.

(c) The mole ratio for A to C or D is 3:1, that is for three moles of A one mole of both C and D are formed. The mole ratio for B to C or D is 1:1, that is for one mole of B one mole of both C and D are formed.

There are two possibilities for the limiting reagent in the given reaction.

Possibility 1

3A + B → C + DBefore 4 2 0 0Change −4 −1.34 +1.34 +1.34After 0 0.66 1.34 1.34

In this case, A is considered as limiting reagent.

Possibility 2

3A + B → C + DBefore 4 2 0 0Change −6 −2 +2 +2After −2 0 2 2

In this case, B is considered as limiting reagent.

Possibility 1 is correct as in possibility 2 there are negative numbers of moles of A which is not possible.

(d) The mole ratio for A to C or D is 3:1, that is for three moles of A one mole of both C and D are formed. The mole ratio for B to C or D is 1:1, that is for one mole of B one mole of both C and D are formed.

There are two possibilities for the limiting reagent in the given reaction.

Possibility 1

3A + B → C + DBefore 4 2 0 0Change −4 −1.34 +1.34 +1.34After 0 0.66 1.34 1.34

In this case, A is considered as limiting reagent.

Possibility 2

3A + B → C + DBefore 4 2 0 0Change −6 −2 +2 +2After −2 0 2 2

In this case, B is considered as limiting reagent.

Possibility 1 is correct as in possibility 2 there are negative numbers of moles of A which is not possible.

(e) The mole ratio for A to C or D is 3:1, that is for three moles of A one mole of both C and D are formed. The mole ratio for B to C or D is 1:1, that is for one mole of B one mole of both C and D are formed.

There are two possibilities for the limiting reagent in the given reaction.

Possibility 1

3A + B → C + DBefore 4 2 0 0Change −4 −1.34 +1.34 +1.34After 0 0.66 1.34 1.34