Concept explainers
Interpretation:
For the given equation, if
Concept Introduction:
Limiting reagent is the reactant in the

Answer to Problem 8ALQ
The true statement is “A is the limiting reactant because you need
Explanation of Solution
Reason for true statements: Possibility 1 is correct as in possibility 2 there are negative numbers of moles of A which is not possible.
The mole ratio for A to C or D is
There are two possibilities for the limiting reagent in the given reaction.
Possibility 1
In this case, A is considered as limiting reagent.
Possibility 2
In this case, B is considered as limiting reagent.
Possibility 1 is correct as in possibility 2 there are negative numbers of moles of A which is not possible.
Reason for false statements:
(a) The given statement is not true as the molar mass is not required for determining the limiting reactant.
(c) The given statement is not true because possibility 1 is correct. In possibility 2, there are negative numbers of moles of A which is not possible.
(d) The given statement is not true because possibility 1 is correct. In possibility 2, there are negative numbers of moles of A which is not possible.
(e) The given statement is not true because A acts as limiting reagent.
Explanation:
(a) It is not necessarily true that the limiting reactant is the one with higher molar mass. The limiting reactant is calculated on the basis of stoichiometry of reactants in a chemical reaction.
(c) The mole ratio for A to C or D is
There are two possibilities for the limiting reagent in the given reaction.
Possibility 1
In this case, A is considered as limiting reagent.
Possibility 2
In this case, B is considered as limiting reagent.
Possibility 1 is correct as in possibility 2 there are negative numbers of moles of A which is not possible.
(d) The mole ratio for A to C or D is
There are two possibilities for the limiting reagent in the given reaction.
Possibility 1
In this case, A is considered as limiting reagent.
Possibility 2
In this case, B is considered as limiting reagent.
Possibility 1 is correct as in possibility 2 there are negative numbers of moles of A which is not possible.
(e) The mole ratio for A to C or D is
There are two possibilities for the limiting reagent in the given reaction.
Possibility 1
In this case, A is considered as limiting reagent.
Possibility 2
In this case, B is considered as limiting reagent.
Possibility 1 is correct as in possibility 2 there are negative numbers of moles of A which is not possible.
Possibility 1 is correct as in possibility 2 there are negative numbers of moles of A which is not possible.
Want to see more full solutions like this?
Chapter 9 Solutions
EBK INTRODUCTORY CHEMISTRY
- The following 'H NMR spectrum was taken with a 750 MHz spectrometer: 1.0 0.5 0.0 10.0 9.0 8.0 7.0 6.0 5.0 4.0 3.0 ' 2.0 1.0 0.0 (ppm) What is the difference Av in the frequency of RF ac Δν ac radiation absorbed by the a and c protons? (Note: it's not equal to the difference in chemical shifts.) Round your answer to 2 significant digits, and be sure it has an appropriate unit symbol. = O O a will shift left, c will shift right. O a will shift right, c will shift left. a and c will both shift left, with more space between them. Suppose a new spectrum is taken with a 500 MHz spectrometer. What will be true about this new spectrum? O a and c will both shift left, with less space between them. O a and c will both shift right, with more space between them. O a and c will both shift right, with less space between them. Which protons have the largest energy gap between spin up and spin down states? O None of the above. ○ a Ob Explanation Check C Ar B 2025 McGraw Hill LLC. All Rights Reserved.…arrow_forwardWhat mass of Na2CO3 must you add to 125g of water to prepare 0.200 m Na2CO3? Calculate mole fraction of Na2CO3, mass percent, and molarity of the resulting solution. MM (g/mol): Na2CO3 105.99; water 18.02. Final solution density is 1.04 g/mL.arrow_forward(ME EX2) Prblms Can you please explain problems to me in detail, step by step? Thank you so much! If needed color code them for me.arrow_forward
- Experiment #8 Electrical conductivity & Electrolytes. Conductivity of solutions FLINN Scientific Scale RED LED Green LED LED Conductivity 0 OFF OFF 1 Dim OFF 2 medium OFF 3 Bright Dim Low or Nowe Low Medium High 4 Very Bright Medium nd very high AA Δ Δ Δ Δ Δ Δ Δ Δ Δ Δ Δ SE=Strong Electrolyte, FE = Fair Electrolyte CWE = Weak Electrolyte, NE= Noni Electrolyte, #Solutions 1 0.1 M NaCl 2/1x 102 M NaCl, 3/1X103 M Nall Can Prediction M Observed Conductivity Very bright red Bright red Dim red you help me understand how I'm supposed to find the predictions of the following solutions? I know this is an Ionic compound and that the more ions in a solution means it is able to carry a charge, right? AAAA Darrow_forward(SE EX 2) Prblsm 4-7: Can you please explain problems 4-7 and color code if needed for me. (step by step) detail explanationsarrow_forward(SE EX 2) Problems 8-11, can you please explain them to me in detail and color-code anything if necessary?arrow_forward
- Chemistry & Chemical ReactivityChemistryISBN:9781337399074Author:John C. Kotz, Paul M. Treichel, John Townsend, David TreichelPublisher:Cengage LearningChemistry for Engineering StudentsChemistryISBN:9781285199023Author:Lawrence S. Brown, Tom HolmePublisher:Cengage LearningChemistry for Engineering StudentsChemistryISBN:9781337398909Author:Lawrence S. Brown, Tom HolmePublisher:Cengage Learning
- Introductory Chemistry: A FoundationChemistryISBN:9781337399425Author:Steven S. Zumdahl, Donald J. DeCostePublisher:Cengage LearningChemistryChemistryISBN:9781305957404Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCostePublisher:Cengage LearningChemistry: An Atoms First ApproachChemistryISBN:9781305079243Author:Steven S. Zumdahl, Susan A. ZumdahlPublisher:Cengage Learning





