For the given equation, if 4 moles of A is reacted with 2 moles of B, then the correct statement is to be predicted. The reason behind the incorrect statements is to be stated. Concept Introduction: Limiting reagent is the reactant in the chemical reaction which is completely consumed. The amount of product and the excess reactant left in a reaction is determined on the basis of limiting reagent only.

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Answer 1

Question

Chapter 9, Problem 8ALQ

Interpretation Introduction

Interpretation:

For the given equation, if 4 moles of A is reacted with 2 moles of B, then the correct statement is to be predicted. The reason behind the incorrect statements is to be stated.

Concept Introduction:

Limiting reagent is the reactant in the chemical reaction which is completely consumed. The amount of product and the excess reactant left in a reaction is determined on the basis of limiting reagent only.

Expert Solution & Answer

Answer to Problem 8ALQ

The true statement is “A is the limiting reactant because you need 6 moles of A and have 4 moles”.

Explanation of Solution

Reason for true statements: Possibility 1 is correct as in possibility 2 there are negative numbers of moles of A which is not possible.

The mole ratio for A to C or D is 3:1, that is for three moles of A one mole of both C and D are formed. The mole ratio for B to C or D is 1:1, that is for one mole of B one mole of both C and D are formed.

There are two possibilities for the limiting reagent in the given reaction.

Possibility 1

3A + B → C + DBefore 4 2 0 0Change −4 −1.34 +1.34 +1.34After 0 0.66 1.34 1.34

In this case, A is considered as limiting reagent.

Possibility 2

3A + B → C + DBefore 4 2 0 0Change −6 −2 +2 +2After −2 0 2 2

In this case, B is considered as limiting reagent.

Possibility 1 is correct as in possibility 2 there are negative numbers of moles of A which is not possible.

Conclusion

Reason for false statements:

(a) The given statement is not true as the molar mass is not required for determining the limiting reactant.

(c) The given statement is not true because possibility 1 is correct. In possibility 2, there are negative numbers of moles of A which is not possible.

(d) The given statement is not true because possibility 1 is correct. In possibility 2, there are negative numbers of moles of A which is not possible.

(e) The given statement is not true because A acts as limiting reagent.

Explanation:

(a) It is not necessarily true that the limiting reactant is the one with higher molar mass. The limiting reactant is calculated on the basis of stoichiometry of reactants in a chemical reaction.

(c) The mole ratio for A to C or D is 3:1, that is for three moles of A one mole of both C and D are formed. The mole ratio for B to C or D is 1:1, that is for one mole of B one mole of both C and D are formed.

There are two possibilities for the limiting reagent in the given reaction.

Possibility 1

3A + B → C + DBefore 4 2 0 0Change −4 −1.34 +1.34 +1.34After 0 0.66 1.34 1.34

In this case, A is considered as limiting reagent.

Possibility 2

3A + B → C + DBefore 4 2 0 0Change −6 −2 +2 +2After −2 0 2 2

In this case, B is considered as limiting reagent.

Possibility 1 is correct as in possibility 2 there are negative numbers of moles of A which is not possible.

(d) The mole ratio for A to C or D is 3:1, that is for three moles of A one mole of both C and D are formed. The mole ratio for B to C or D is 1:1, that is for one mole of B one mole of both C and D are formed.

There are two possibilities for the limiting reagent in the given reaction.

Possibility 1

3A + B → C + DBefore 4 2 0 0Change −4 −1.34 +1.34 +1.34After 0 0.66 1.34 1.34

In this case, A is considered as limiting reagent.

Possibility 2

3A + B → C + DBefore 4 2 0 0Change −6 −2 +2 +2After −2 0 2 2

In this case, B is considered as limiting reagent.

Possibility 1 is correct as in possibility 2 there are negative numbers of moles of A which is not possible.

(e) The mole ratio for A to C or D is 3:1, that is for three moles of A one mole of both C and D are formed. The mole ratio for B to C or D is 1:1, that is for one mole of B one mole of both C and D are formed.

There are two possibilities for the limiting reagent in the given reaction.

Possibility 1

3A + B → C + DBefore 4 2 0 0Change −4 −1.34 +1.34 +1.34After 0 0.66 1.34 1.34

In this case, A is considered as limiting reagent.

Possibility 2

3A + B → C + DBefore 4 2 0 0Change −6 −2 +2 +2After −2 0 2 2

In this case, B is considered as limiting reagent.

Possibility 1 is correct as in possibility 2 there are negative numbers of moles of A which is not possible.

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Consider the reactants below. Answer the following questions about the reaction mechanism and products. HO Cl

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The electrons flow from the electron-rich atoms of the nucleophile to the electrons poor atoms of the alkyl halide. Identify the electron rich in the nucleophile. Enter the element symbol only, do not include any changes.

Answer 2

Question

Chapter 9, Problem 8ALQ

Interpretation Introduction

Interpretation:

For the given equation, if 4 moles of A is reacted with 2 moles of B, then the correct statement is to be predicted. The reason behind the incorrect statements is to be stated.

Concept Introduction:

Limiting reagent is the reactant in the chemical reaction which is completely consumed. The amount of product and the excess reactant left in a reaction is determined on the basis of limiting reagent only.

Expert Solution & Answer

Answer to Problem 8ALQ

The true statement is “A is the limiting reactant because you need 6 moles of A and have 4 moles”.

Explanation of Solution

Reason for true statements: Possibility 1 is correct as in possibility 2 there are negative numbers of moles of A which is not possible.

The mole ratio for A to C or D is 3:1, that is for three moles of A one mole of both C and D are formed. The mole ratio for B to C or D is 1:1, that is for one mole of B one mole of both C and D are formed.

There are two possibilities for the limiting reagent in the given reaction.

Possibility 1

3A + B → C + DBefore 4 2 0 0Change −4 −1.34 +1.34 +1.34After 0 0.66 1.34 1.34

In this case, A is considered as limiting reagent.

Possibility 2

3A + B → C + DBefore 4 2 0 0Change −6 −2 +2 +2After −2 0 2 2

In this case, B is considered as limiting reagent.

Possibility 1 is correct as in possibility 2 there are negative numbers of moles of A which is not possible.

Conclusion

Reason for false statements:

(a) The given statement is not true as the molar mass is not required for determining the limiting reactant.

(c) The given statement is not true because possibility 1 is correct. In possibility 2, there are negative numbers of moles of A which is not possible.

(d) The given statement is not true because possibility 1 is correct. In possibility 2, there are negative numbers of moles of A which is not possible.

(e) The given statement is not true because A acts as limiting reagent.

Explanation:

(a) It is not necessarily true that the limiting reactant is the one with higher molar mass. The limiting reactant is calculated on the basis of stoichiometry of reactants in a chemical reaction.

(c) The mole ratio for A to C or D is 3:1, that is for three moles of A one mole of both C and D are formed. The mole ratio for B to C or D is 1:1, that is for one mole of B one mole of both C and D are formed.

There are two possibilities for the limiting reagent in the given reaction.

Possibility 1

3A + B → C + DBefore 4 2 0 0Change −4 −1.34 +1.34 +1.34After 0 0.66 1.34 1.34

In this case, A is considered as limiting reagent.

Possibility 2

3A + B → C + DBefore 4 2 0 0Change −6 −2 +2 +2After −2 0 2 2

In this case, B is considered as limiting reagent.

Possibility 1 is correct as in possibility 2 there are negative numbers of moles of A which is not possible.

(d) The mole ratio for A to C or D is 3:1, that is for three moles of A one mole of both C and D are formed. The mole ratio for B to C or D is 1:1, that is for one mole of B one mole of both C and D are formed.

There are two possibilities for the limiting reagent in the given reaction.

Possibility 1

3A + B → C + DBefore 4 2 0 0Change −4 −1.34 +1.34 +1.34After 0 0.66 1.34 1.34

In this case, A is considered as limiting reagent.

Possibility 2

3A + B → C + DBefore 4 2 0 0Change −6 −2 +2 +2After −2 0 2 2

In this case, B is considered as limiting reagent.

Possibility 1 is correct as in possibility 2 there are negative numbers of moles of A which is not possible.

(e) The mole ratio for A to C or D is 3:1, that is for three moles of A one mole of both C and D are formed. The mole ratio for B to C or D is 1:1, that is for one mole of B one mole of both C and D are formed.

There are two possibilities for the limiting reagent in the given reaction.

Possibility 1

3A + B → C + DBefore 4 2 0 0Change −4 −1.34 +1.34 +1.34After 0 0.66 1.34 1.34

In this case, A is considered as limiting reagent.

Possibility 2

3A + B → C + DBefore 4 2 0 0Change −6 −2 +2 +2After −2 0 2 2

In this case, B is considered as limiting reagent.

Possibility 1 is correct as in possibility 2 there are negative numbers of moles of A which is not possible.

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Answer 3

Question

Chapter 9, Problem 8ALQ

Interpretation Introduction

Interpretation:

For the given equation, if 4 moles of A is reacted with 2 moles of B, then the correct statement is to be predicted. The reason behind the incorrect statements is to be stated.

Concept Introduction:

Limiting reagent is the reactant in the chemical reaction which is completely consumed. The amount of product and the excess reactant left in a reaction is determined on the basis of limiting reagent only.

Expert Solution & Answer

Answer to Problem 8ALQ

The true statement is “A is the limiting reactant because you need 6 moles of A and have 4 moles”.

Explanation of Solution

Reason for true statements: Possibility 1 is correct as in possibility 2 there are negative numbers of moles of A which is not possible.

The mole ratio for A to C or D is 3:1, that is for three moles of A one mole of both C and D are formed. The mole ratio for B to C or D is 1:1, that is for one mole of B one mole of both C and D are formed.

There are two possibilities for the limiting reagent in the given reaction.

Possibility 1

3A + B → C + DBefore 4 2 0 0Change −4 −1.34 +1.34 +1.34After 0 0.66 1.34 1.34

In this case, A is considered as limiting reagent.

Possibility 2

3A + B → C + DBefore 4 2 0 0Change −6 −2 +2 +2After −2 0 2 2

In this case, B is considered as limiting reagent.

Possibility 1 is correct as in possibility 2 there are negative numbers of moles of A which is not possible.

Conclusion

Reason for false statements:

(a) The given statement is not true as the molar mass is not required for determining the limiting reactant.

(c) The given statement is not true because possibility 1 is correct. In possibility 2, there are negative numbers of moles of A which is not possible.

(d) The given statement is not true because possibility 1 is correct. In possibility 2, there are negative numbers of moles of A which is not possible.

(e) The given statement is not true because A acts as limiting reagent.

Explanation:

(a) It is not necessarily true that the limiting reactant is the one with higher molar mass. The limiting reactant is calculated on the basis of stoichiometry of reactants in a chemical reaction.

(c) The mole ratio for A to C or D is 3:1, that is for three moles of A one mole of both C and D are formed. The mole ratio for B to C or D is 1:1, that is for one mole of B one mole of both C and D are formed.

There are two possibilities for the limiting reagent in the given reaction.

Possibility 1

3A + B → C + DBefore 4 2 0 0Change −4 −1.34 +1.34 +1.34After 0 0.66 1.34 1.34

In this case, A is considered as limiting reagent.

Possibility 2

3A + B → C + DBefore 4 2 0 0Change −6 −2 +2 +2After −2 0 2 2

In this case, B is considered as limiting reagent.

Possibility 1 is correct as in possibility 2 there are negative numbers of moles of A which is not possible.

(d) The mole ratio for A to C or D is 3:1, that is for three moles of A one mole of both C and D are formed. The mole ratio for B to C or D is 1:1, that is for one mole of B one mole of both C and D are formed.

There are two possibilities for the limiting reagent in the given reaction.

Possibility 1

3A + B → C + DBefore 4 2 0 0Change −4 −1.34 +1.34 +1.34After 0 0.66 1.34 1.34

In this case, A is considered as limiting reagent.

Possibility 2

3A + B → C + DBefore 4 2 0 0Change −6 −2 +2 +2After −2 0 2 2

In this case, B is considered as limiting reagent.

Possibility 1 is correct as in possibility 2 there are negative numbers of moles of A which is not possible.

(e) The mole ratio for A to C or D is 3:1, that is for three moles of A one mole of both C and D are formed. The mole ratio for B to C or D is 1:1, that is for one mole of B one mole of both C and D are formed.

There are two possibilities for the limiting reagent in the given reaction.

Possibility 1

3A + B → C + DBefore 4 2 0 0Change −4 −1.34 +1.34 +1.34After 0 0.66 1.34 1.34

In this case, A is considered as limiting reagent.

Possibility 2

3A + B → C + DBefore 4 2 0 0Change −6 −2 +2 +2After −2 0 2 2

In this case, B is considered as limiting reagent.

Possibility 1 is correct as in possibility 2 there are negative numbers of moles of A which is not possible.

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Answer 4

Question

Chapter 9, Problem 8ALQ

Interpretation Introduction

Interpretation:

For the given equation, if 4 moles of A is reacted with 2 moles of B, then the correct statement is to be predicted. The reason behind the incorrect statements is to be stated.

Concept Introduction:

Limiting reagent is the reactant in the chemical reaction which is completely consumed. The amount of product and the excess reactant left in a reaction is determined on the basis of limiting reagent only.

Expert Solution & Answer

Answer to Problem 8ALQ

The true statement is “A is the limiting reactant because you need 6 moles of A and have 4 moles”.

Explanation of Solution

Reason for true statements: Possibility 1 is correct as in possibility 2 there are negative numbers of moles of A which is not possible.

The mole ratio for A to C or D is 3:1, that is for three moles of A one mole of both C and D are formed. The mole ratio for B to C or D is 1:1, that is for one mole of B one mole of both C and D are formed.

There are two possibilities for the limiting reagent in the given reaction.

Possibility 1

3A + B → C + DBefore 4 2 0 0Change −4 −1.34 +1.34 +1.34After 0 0.66 1.34 1.34

In this case, A is considered as limiting reagent.

Possibility 2

3A + B → C + DBefore 4 2 0 0Change −6 −2 +2 +2After −2 0 2 2

In this case, B is considered as limiting reagent.

Possibility 1 is correct as in possibility 2 there are negative numbers of moles of A which is not possible.

Conclusion

Reason for false statements:

(a) The given statement is not true as the molar mass is not required for determining the limiting reactant.

(c) The given statement is not true because possibility 1 is correct. In possibility 2, there are negative numbers of moles of A which is not possible.

(d) The given statement is not true because possibility 1 is correct. In possibility 2, there are negative numbers of moles of A which is not possible.

(e) The given statement is not true because A acts as limiting reagent.

Explanation:

(a) It is not necessarily true that the limiting reactant is the one with higher molar mass. The limiting reactant is calculated on the basis of stoichiometry of reactants in a chemical reaction.

(c) The mole ratio for A to C or D is 3:1, that is for three moles of A one mole of both C and D are formed. The mole ratio for B to C or D is 1:1, that is for one mole of B one mole of both C and D are formed.

There are two possibilities for the limiting reagent in the given reaction.

Possibility 1

3A + B → C + DBefore 4 2 0 0Change −4 −1.34 +1.34 +1.34After 0 0.66 1.34 1.34

In this case, A is considered as limiting reagent.

Possibility 2

3A + B → C + DBefore 4 2 0 0Change −6 −2 +2 +2After −2 0 2 2

In this case, B is considered as limiting reagent.

Possibility 1 is correct as in possibility 2 there are negative numbers of moles of A which is not possible.

(d) The mole ratio for A to C or D is 3:1, that is for three moles of A one mole of both C and D are formed. The mole ratio for B to C or D is 1:1, that is for one mole of B one mole of both C and D are formed.

There are two possibilities for the limiting reagent in the given reaction.

Possibility 1

3A + B → C + DBefore 4 2 0 0Change −4 −1.34 +1.34 +1.34After 0 0.66 1.34 1.34

In this case, A is considered as limiting reagent.

Possibility 2

3A + B → C + DBefore 4 2 0 0Change −6 −2 +2 +2After −2 0 2 2

In this case, B is considered as limiting reagent.

Possibility 1 is correct as in possibility 2 there are negative numbers of moles of A which is not possible.

(e) The mole ratio for A to C or D is 3:1, that is for three moles of A one mole of both C and D are formed. The mole ratio for B to C or D is 1:1, that is for one mole of B one mole of both C and D are formed.

There are two possibilities for the limiting reagent in the given reaction.

Possibility 1

3A + B → C + DBefore 4 2 0 0Change −4 −1.34 +1.34 +1.34After 0 0.66 1.34 1.34

In this case, A is considered as limiting reagent.

Possibility 2

3A + B → C + DBefore 4 2 0 0Change −6 −2 +2 +2After −2 0 2 2

In this case, B is considered as limiting reagent.

Possibility 1 is correct as in possibility 2 there are negative numbers of moles of A which is not possible.

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Answer 5

Chapter 9, Problem 8ALQ

Interpretation Introduction

Interpretation:

For the given equation, if 4 moles of A is reacted with 2 moles of B, then the correct statement is to be predicted. The reason behind the incorrect statements is to be stated.

Concept Introduction:

Limiting reagent is the reactant in the chemical reaction which is completely consumed. The amount of product and the excess reactant left in a reaction is determined on the basis of limiting reagent only.

Expert Solution & Answer

Answer to Problem 8ALQ

The true statement is “A is the limiting reactant because you need 6 moles of A and have 4 moles”.

Explanation of Solution

Reason for true statements: Possibility 1 is correct as in possibility 2 there are negative numbers of moles of A which is not possible.

The mole ratio for A to C or D is 3:1, that is for three moles of A one mole of both C and D are formed. The mole ratio for B to C or D is 1:1, that is for one mole of B one mole of both C and D are formed.

There are two possibilities for the limiting reagent in the given reaction.

Possibility 1

3A + B → C + DBefore 4 2 0 0Change −4 −1.34 +1.34 +1.34After 0 0.66 1.34 1.34

In this case, A is considered as limiting reagent.

Possibility 2

3A + B → C + DBefore 4 2 0 0Change −6 −2 +2 +2After −2 0 2 2

In this case, B is considered as limiting reagent.

Possibility 1 is correct as in possibility 2 there are negative numbers of moles of A which is not possible.

Conclusion

Reason for false statements:

(a) The given statement is not true as the molar mass is not required for determining the limiting reactant.

(c) The given statement is not true because possibility 1 is correct. In possibility 2, there are negative numbers of moles of A which is not possible.

(d) The given statement is not true because possibility 1 is correct. In possibility 2, there are negative numbers of moles of A which is not possible.

(e) The given statement is not true because A acts as limiting reagent.

Explanation:

(a) It is not necessarily true that the limiting reactant is the one with higher molar mass. The limiting reactant is calculated on the basis of stoichiometry of reactants in a chemical reaction.

(c) The mole ratio for A to C or D is 3:1, that is for three moles of A one mole of both C and D are formed. The mole ratio for B to C or D is 1:1, that is for one mole of B one mole of both C and D are formed.

There are two possibilities for the limiting reagent in the given reaction.

Possibility 1

3A + B → C + DBefore 4 2 0 0Change −4 −1.34 +1.34 +1.34After 0 0.66 1.34 1.34

In this case, A is considered as limiting reagent.

Possibility 2

3A + B → C + DBefore 4 2 0 0Change −6 −2 +2 +2After −2 0 2 2

In this case, B is considered as limiting reagent.

Possibility 1 is correct as in possibility 2 there are negative numbers of moles of A which is not possible.

(d) The mole ratio for A to C or D is 3:1, that is for three moles of A one mole of both C and D are formed. The mole ratio for B to C or D is 1:1, that is for one mole of B one mole of both C and D are formed.

There are two possibilities for the limiting reagent in the given reaction.

Possibility 1

3A + B → C + DBefore 4 2 0 0Change −4 −1.34 +1.34 +1.34After 0 0.66 1.34 1.34

In this case, A is considered as limiting reagent.

Possibility 2

3A + B → C + DBefore 4 2 0 0Change −6 −2 +2 +2After −2 0 2 2

In this case, B is considered as limiting reagent.

Possibility 1 is correct as in possibility 2 there are negative numbers of moles of A which is not possible.

(e) The mole ratio for A to C or D is 3:1, that is for three moles of A one mole of both C and D are formed. The mole ratio for B to C or D is 1:1, that is for one mole of B one mole of both C and D are formed.

There are two possibilities for the limiting reagent in the given reaction.

Possibility 1

3A + B → C + DBefore 4 2 0 0Change −4 −1.34 +1.34 +1.34After 0 0.66 1.34 1.34

In this case, A is considered as limiting reagent.

Possibility 2

3A + B → C + DBefore 4 2 0 0Change −6 −2 +2 +2After −2 0 2 2

In this case, B is considered as limiting reagent.

Possibility 1 is correct as in possibility 2 there are negative numbers of moles of A which is not possible.

Answer 6

Chapter 9, Problem 8ALQ

Interpretation Introduction

Interpretation:

For the given equation, if 4 moles of A is reacted with 2 moles of B, then the correct statement is to be predicted. The reason behind the incorrect statements is to be stated.

Concept Introduction:

Limiting reagent is the reactant in the chemical reaction which is completely consumed. The amount of product and the excess reactant left in a reaction is determined on the basis of limiting reagent only.

Expert Solution & Answer

Answer to Problem 8ALQ

The true statement is “A is the limiting reactant because you need 6 moles of A and have 4 moles”.

Explanation of Solution

Reason for true statements: Possibility 1 is correct as in possibility 2 there are negative numbers of moles of A which is not possible.

The mole ratio for A to C or D is 3:1, that is for three moles of A one mole of both C and D are formed. The mole ratio for B to C or D is 1:1, that is for one mole of B one mole of both C and D are formed.

There are two possibilities for the limiting reagent in the given reaction.

Possibility 1

3A + B → C + DBefore 4 2 0 0Change −4 −1.34 +1.34 +1.34After 0 0.66 1.34 1.34

In this case, A is considered as limiting reagent.

Possibility 2

3A + B → C + DBefore 4 2 0 0Change −6 −2 +2 +2After −2 0 2 2

In this case, B is considered as limiting reagent.

Possibility 1 is correct as in possibility 2 there are negative numbers of moles of A which is not possible.

Conclusion

Reason for false statements:

(a) The given statement is not true as the molar mass is not required for determining the limiting reactant.

(c) The given statement is not true because possibility 1 is correct. In possibility 2, there are negative numbers of moles of A which is not possible.

(d) The given statement is not true because possibility 1 is correct. In possibility 2, there are negative numbers of moles of A which is not possible.

(e) The given statement is not true because A acts as limiting reagent.

Explanation:

(a) It is not necessarily true that the limiting reactant is the one with higher molar mass. The limiting reactant is calculated on the basis of stoichiometry of reactants in a chemical reaction.

(c) The mole ratio for A to C or D is 3:1, that is for three moles of A one mole of both C and D are formed. The mole ratio for B to C or D is 1:1, that is for one mole of B one mole of both C and D are formed.

There are two possibilities for the limiting reagent in the given reaction.

Possibility 1

3A + B → C + DBefore 4 2 0 0Change −4 −1.34 +1.34 +1.34After 0 0.66 1.34 1.34

In this case, A is considered as limiting reagent.

Possibility 2

3A + B → C + DBefore 4 2 0 0Change −6 −2 +2 +2After −2 0 2 2

In this case, B is considered as limiting reagent.

Possibility 1 is correct as in possibility 2 there are negative numbers of moles of A which is not possible.

(d) The mole ratio for A to C or D is 3:1, that is for three moles of A one mole of both C and D are formed. The mole ratio for B to C or D is 1:1, that is for one mole of B one mole of both C and D are formed.

There are two possibilities for the limiting reagent in the given reaction.

Possibility 1

3A + B → C + DBefore 4 2 0 0Change −4 −1.34 +1.34 +1.34After 0 0.66 1.34 1.34

In this case, A is considered as limiting reagent.

Possibility 2

3A + B → C + DBefore 4 2 0 0Change −6 −2 +2 +2After −2 0 2 2

In this case, B is considered as limiting reagent.

Possibility 1 is correct as in possibility 2 there are negative numbers of moles of A which is not possible.

(e) The mole ratio for A to C or D is 3:1, that is for three moles of A one mole of both C and D are formed. The mole ratio for B to C or D is 1:1, that is for one mole of B one mole of both C and D are formed.

There are two possibilities for the limiting reagent in the given reaction.

Possibility 1

3A + B → C + DBefore 4 2 0 0Change −4 −1.34 +1.34 +1.34After 0 0.66 1.34 1.34

In this case, A is considered as limiting reagent.

Possibility 2

3A + B → C + DBefore 4 2 0 0Change −6 −2 +2 +2After −2 0 2 2

In this case, B is considered as limiting reagent.

Possibility 1 is correct as in possibility 2 there are negative numbers of moles of A which is not possible.

Answer 7

Chapter 9, Problem 8ALQ

Interpretation Introduction

Interpretation:

For the given equation, if 4 moles of A is reacted with 2 moles of B, then the correct statement is to be predicted. The reason behind the incorrect statements is to be stated.

Concept Introduction:

Limiting reagent is the reactant in the chemical reaction which is completely consumed. The amount of product and the excess reactant left in a reaction is determined on the basis of limiting reagent only.

Answer 8

Expert Solution & Answer

Answer to Problem 8ALQ

The true statement is “A is the limiting reactant because you need 6 moles of A and have 4 moles”.

Answer 9

Expert Solution & Answer

Answer 10

Expert Solution & Answer

Answer 11

Explanation of Solution

Reason for true statements: Possibility 1 is correct as in possibility 2 there are negative numbers of moles of A which is not possible.

The mole ratio for A to C or D is 3:1, that is for three moles of A one mole of both C and D are formed. The mole ratio for B to C or D is 1:1, that is for one mole of B one mole of both C and D are formed.

There are two possibilities for the limiting reagent in the given reaction.

Possibility 1

3A + B → C + DBefore 4 2 0 0Change −4 −1.34 +1.34 +1.34After 0 0.66 1.34 1.34

In this case, A is considered as limiting reagent.

Possibility 2

3A + B → C + DBefore 4 2 0 0Change −6 −2 +2 +2After −2 0 2 2

In this case, B is considered as limiting reagent.

Possibility 1 is correct as in possibility 2 there are negative numbers of moles of A which is not possible.

Answer 12

Conclusion

Reason for false statements:

(a) The given statement is not true as the molar mass is not required for determining the limiting reactant.

(c) The given statement is not true because possibility 1 is correct. In possibility 2, there are negative numbers of moles of A which is not possible.

(d) The given statement is not true because possibility 1 is correct. In possibility 2, there are negative numbers of moles of A which is not possible.

(e) The given statement is not true because A acts as limiting reagent.

Explanation:

(a) It is not necessarily true that the limiting reactant is the one with higher molar mass. The limiting reactant is calculated on the basis of stoichiometry of reactants in a chemical reaction.

(c) The mole ratio for A to C or D is 3:1, that is for three moles of A one mole of both C and D are formed. The mole ratio for B to C or D is 1:1, that is for one mole of B one mole of both C and D are formed.

There are two possibilities for the limiting reagent in the given reaction.

Possibility 1

3A + B → C + DBefore 4 2 0 0Change −4 −1.34 +1.34 +1.34After 0 0.66 1.34 1.34

In this case, A is considered as limiting reagent.

Possibility 2

3A + B → C + DBefore 4 2 0 0Change −6 −2 +2 +2After −2 0 2 2

In this case, B is considered as limiting reagent.

Possibility 1 is correct as in possibility 2 there are negative numbers of moles of A which is not possible.

(d) The mole ratio for A to C or D is 3:1, that is for three moles of A one mole of both C and D are formed. The mole ratio for B to C or D is 1:1, that is for one mole of B one mole of both C and D are formed.

There are two possibilities for the limiting reagent in the given reaction.

Possibility 1

3A + B → C + DBefore 4 2 0 0Change −4 −1.34 +1.34 +1.34After 0 0.66 1.34 1.34

In this case, A is considered as limiting reagent.

Possibility 2

3A + B → C + DBefore 4 2 0 0Change −6 −2 +2 +2After −2 0 2 2

In this case, B is considered as limiting reagent.

Possibility 1 is correct as in possibility 2 there are negative numbers of moles of A which is not possible.

(e) The mole ratio for A to C or D is 3:1, that is for three moles of A one mole of both C and D are formed. The mole ratio for B to C or D is 1:1, that is for one mole of B one mole of both C and D are formed.

There are two possibilities for the limiting reagent in the given reaction.

Possibility 1

3A + B → C + DBefore 4 2 0 0Change −4 −1.34 +1.34 +1.34After 0 0.66 1.34 1.34