Explanation Formula used: The standard form of a circle with its radius a and center at ( x 1 , y 1 ) is given by, ( x − x 1 ) 2 + ( y − y 1 ) 2 = a 2 Calculation: Consider the equation x 2 + y 2 − 10 x + 12 y + 52 = 0 . Now, Group the x and the y terms on the left-hand side while keep the constants on the right-hand side, as follows, x 2 + y 2 − 10 x + 12 y + 52 = 0 ( x 2 − 10 x ) + ( y 2 + 12 y ) = − 52 Then, complete the square of the equation, to get the standard form, ( x 2 − 10 x ) + ( y 2 + 12 y ) = − 52 ( x 2 − 10 x + 25 ) − 25 + ( y 2 + 12 y + 36 ) − 36 = − 52 ( x − 5 ) 2

8th Edition

ISBN: 9780134178967

Author: John Tobey Jr., Jeffrey Slater, Jamie Blair, Jenny Crawford

Publisher: PEARSON

See similar textbooks

Question

Chapter 9, Problem 6RP

To determine

To calculate: The center and radius of each circle of the following equation and rewrite in its standard form, x2+y2−10x+12y+52=0

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Chapter 9, Problem 5RP

Chapter 9, Problem 7RP

Students have asked these similar questions

I need help with number 5.

3) Use the following system of linear inequalities graphed below to answer the questions. a) Use the graph to write the symbolic form of the system of linear inequalities. b) Is (-4,2) a solution to the system? Explain. 5 -7 -5 -3 -2 0 2 3 4 $ 6 -2 -6 -7

) Graph the feasible region subject to the following constraints. x + y ≤ 6 y ≤ 2x x ≥ 0, y ≥ 0 P + x

Chapter 9 Solutions

Intermediate Algebra (8th Edition)

Ch. 9.1 - Prob. 1E Ch. 9.1 - Prob. 2E Ch. 9.1 - Prob. 3E Ch. 9.1 - Prob. 4E Ch. 9.1 - Prob. 5E Ch. 9.1 - Prob. 6E Ch. 9.1 - Prob. 7E Ch. 9.1 - Prob. 8E Ch. 9.1 - Prob. 9E Ch. 9.1 - Find the distance between each pair of points....

Ch. 9.1 - Prob. 11E Ch. 9.1 - Prob. 12E Ch. 9.1 - Prob. 13E Ch. 9.1 - Prob. 14E Ch. 9.1 - Prob. 15E Ch. 9.1 - Find the distance between each pair of points....Ch. 9.1 - Prob. 17E Ch. 9.1 - Find the two values of the unknown coordinate so...Ch. 9.1 - Prob. 19E Ch. 9.1 - Prob. 20E Ch. 9.1 - Prob. 21E Ch. 9.1 - Prob. 22E Ch. 9.1 - Prob. 23E Ch. 9.1 - Prob. 24E Ch. 9.1 - Prob. 25E Ch. 9.1 - Prob. 26E Ch. 9.1 - Prob. 27E Ch. 9.1 - Prob. 28E Ch. 9.1 - Prob. 29E Ch. 9.1 - Prob. 30E Ch. 9.1 - Prob. 31E Ch. 9.1 - Prob. 32E Ch. 9.1 - Prob. 33E Ch. 9.1 - Prob. 34E Ch. 9.1 - Prob. 35E Ch. 9.1 - Prob. 36E Ch. 9.1 - Prob. 37E Ch. 9.1 - Prob. 38E Ch. 9.1 - Prob. 39E Ch. 9.1 - Prob. 40E Ch. 9.1 - Prob. 41E Ch. 9.1 - Prob. 42E Ch. 9.1 - Prob. 43E Ch. 9.1 - Prob. 44E Ch. 9.1 - Prob. 45E Ch. 9.1 - Prob. 46E Ch. 9.1 - Prob. 47E Ch. 9.1 - Prob. 48E Ch. 9.1 - Prob. 49E Ch. 9.1 - Prob. 50E Ch. 9.1 - Prob. 1QQ Ch. 9.1 - Prob. 2QQ Ch. 9.1 - Prob. 3QQ Ch. 9.1 - Prob. 4QQ Ch. 9.2 - Prob. 1E Ch. 9.2 - Prob. 2E Ch. 9.2 - Prob. 3E Ch. 9.2 - Prob. 4E Ch. 9.2 - Prob. 5E Ch. 9.2 - Prob. 6E Ch. 9.2 - Prob. 7E Ch. 9.2 - Prob. 8E Ch. 9.2 - Prob. 9E Ch. 9.2 - Prob. 10E Ch. 9.2 - Prob. 11E Ch. 9.2 - Prob. 12E Ch. 9.2 - Prob. 13E Ch. 9.2 - Prob. 14E Ch. 9.2 - Prob. 15E Ch. 9.2 - Prob. 16E Ch. 9.2 - Prob. 17E Ch. 9.2 - Prob. 18E Ch. 9.2 - Prob. 19E Ch. 9.2 - Prob. 20E Ch. 9.2 - Prob. 21E Ch. 9.2 - Prob. 22E Ch. 9.2 - Prob. 23E Ch. 9.2 - Prob. 24E Ch. 9.2 - Prob. 25E Ch. 9.2 - Prob. 26E Ch. 9.2 - Prob. 27E Ch. 9.2 - Prob. 28E Ch. 9.2 - Prob. 29E Ch. 9.2 - Prob. 30E Ch. 9.2 - Prob. 31E Ch. 9.2 - Prob. 32E Ch. 9.2 - Satellite Dishes Modern satellite dishes intended...Ch. 9.2 - Satellite Dishes Modern satellite dishes intended...Ch. 9.2 - Prob. 35E Ch. 9.2 - Prob. 36E Ch. 9.2 - Prob. 37E Ch. 9.2 - Prob. 38E Ch. 9.2 - Prob. 39E Ch. 9.2 - Prob. 40E Ch. 9.2 - Prob. 41E Ch. 9.2 - Prob. 42E Ch. 9.2 - Prob. 43E Ch. 9.2 - Prob. 44E Ch. 9.2 - Prob. 45E Ch. 9.2 - Prob. 46E Ch. 9.2 - Prob. 1QQ Ch. 9.2 - Prob. 2QQ Ch. 9.2 - Prob. 3QQ Ch. 9.2 - Prob. 4QQ Ch. 9.3 - Prob. 1E Ch. 9.3 - Prob. 2E Ch. 9.3 - Prob. 3E Ch. 9.3 - Prob. 4E Ch. 9.3 - Prob. 5E Ch. 9.3 - Prob. 6E Ch. 9.3 - Prob. 7E Ch. 9.3 - Prob. 8E Ch. 9.3 - Prob. 9E Ch. 9.3 - Prob. 10E Ch. 9.3 - Prob. 11E Ch. 9.3 - Prob. 12E Ch. 9.3 - Prob. 13E Ch. 9.3 - Prob. 14E Ch. 9.3 - Prob. 15E Ch. 9.3 - Prob. 16E Ch. 9.3 - Prob. 17E Ch. 9.3 - Prob. 18E Ch. 9.3 - Prob. 19E Ch. 9.3 - Prob. 20E Ch. 9.3 - Prob. 21E Ch. 9.3 - Prob. 22E Ch. 9.3 - Prob. 23E Ch. 9.3 - Prob. 24E Ch. 9.3 - Prob. 25E Ch. 9.3 - Prob. 26E Ch. 9.3 - Prob. 27E Ch. 9.3 - Prob. 28E Ch. 9.3 - Prob. 29E Ch. 9.3 - Prob. 30E Ch. 9.3 - Prob. 31E Ch. 9.3 - Prob. 32E Ch. 9.3 - Prob. 33E Ch. 9.3 - Prob. 34E Ch. 9.3 - Prob. 35E Ch. 9.3 - Prob. 36E Ch. 9.3 - Prob. 37E Ch. 9.3 - Prob. 1QQ Ch. 9.3 - Prob. 2QQ Ch. 9.3 - Prob. 3QQ Ch. 9.3 - Prob. 4QQ Ch. 9.4 - Prob. 1E Ch. 9.4 - Prob. 2E Ch. 9.4 - Prob. 3E Ch. 9.4 - Prob. 4E Ch. 9.4 - Prob. 5E Ch. 9.4 - Prob. 6E Ch. 9.4 - Prob. 7E Ch. 9.4 - Prob. 8E Ch. 9.4 - Prob. 9E Ch. 9.4 - Prob. 10E Ch. 9.4 - Prob. 11E Ch. 9.4 - Prob. 12E Ch. 9.4 - Prob. 13E Ch. 9.4 - Prob. 14E Ch. 9.4 - Prob. 15E Ch. 9.4 - Prob. 16E Ch. 9.4 - Prob. 17E Ch. 9.4 - Prob. 18E Ch. 9.4 - Prob. 19E Ch. 9.4 - Prob. 20E Ch. 9.4 - Prob. 21E Ch. 9.4 - Prob. 22E Ch. 9.4 - Prob. 23E Ch. 9.4 - Prob. 24E Ch. 9.4 - Prob. 25E Ch. 9.4 - Prob. 26E Ch. 9.4 - Prob. 27E Ch. 9.4 - Prob. 28E Ch. 9.4 - Prob. 29E Ch. 9.4 - Prob. 30E Ch. 9.4 - Prob. 31E Ch. 9.4 - Prob. 32E Ch. 9.4 - Prob. 33E Ch. 9.4 - Prob. 34E Ch. 9.4 - Prob. 1QQ Ch. 9.4 - Prob. 2QQ Ch. 9.4 - Prob. 3QQ Ch. 9.4 - Prob. 4QQ Ch. 9.5 - Prob. 1E Ch. 9.5 - Prob. 2E Ch. 9.5 - Prob. 3E Ch. 9.5 - Prob. 4E Ch. 9.5 - Prob. 5E Ch. 9.5 - Prob. 6E Ch. 9.5 - Prob. 7E Ch. 9.5 - Prob. 8E Ch. 9.5 - Prob. 9E Ch. 9.5 - Prob. 10E Ch. 9.5 - Prob. 11E Ch. 9.5 - Prob. 12E Ch. 9.5 - Prob. 13E Ch. 9.5 - Prob. 14E Ch. 9.5 - Prob. 15E Ch. 9.5 - Prob. 16E Ch. 9.5 - Prob. 17E Ch. 9.5 - Prob. 18E Ch. 9.5 - Prob. 19E Ch. 9.5 - Prob. 20E Ch. 9.5 - Prob. 21E Ch. 9.5 - Prob. 22E Ch. 9.5 - Prob. 23E Ch. 9.5 - Prob. 24E Ch. 9.5 - Prob. 25E Ch. 9.5 - Prob. 26E Ch. 9.5 - Prob. 27E Ch. 9.5 - Prob. 28E Ch. 9.5 - Prob. 29E Ch. 9.5 - Prob. 30E Ch. 9.5 - Prob. 1QQ Ch. 9.5 - Prob. 2QQ Ch. 9.5 - Prob. 3QQ Ch. 9.5 - Prob. 4QQ Ch. 9 - In exercises 1 and 2, find the distance between...Ch. 9 - Prob. 2RP Ch. 9 - Prob. 3RP Ch. 9 - Prob. 4RP Ch. 9 - Prob. 5RP Ch. 9 - Prob. 6RP Ch. 9 - Prob. 7RP Ch. 9 - Prob. 8RP Ch. 9 - Prob. 9RP Ch. 9 - Prob. 10RP Ch. 9 - Prob. 11RP Ch. 9 - Prob. 12RP Ch. 9 - Prob. 13RP Ch. 9 - Prob. 14RP Ch. 9 - Prob. 15RP Ch. 9 - Prob. 16RP Ch. 9 - Prob. 17RP Ch. 9 - Prob. 18RP Ch. 9 - Prob. 19RP Ch. 9 - Prob. 20RP Ch. 9 - Prob. 21RP Ch. 9 - Prob. 22RP Ch. 9 - Prob. 23RP Ch. 9 - Solve each nonlinear system. If there is no real...Ch. 9 - Prob. 25RP Ch. 9 - Prob. 26RP Ch. 9 - Prob. 27RP Ch. 9 - Prob. 1T Ch. 9 - Prob. 2T Ch. 9 - Rewrite the equation in standard form. Identify...Ch. 9 - Prob. 4T Ch. 9 - Prob. 5T Ch. 9 - Prob. 6T Ch. 9 - Prob. 7T Ch. 9 - Prob. 8T Ch. 9 - Prob. 9T Ch. 9 - Prob. 10T Ch. 9 - Prob. 11T Ch. 9 - Prob. 12T Ch. 9 - Prob. 13T Ch. 9 - Prob. 14T Ch. 9 - Prob. 15T Ch. 9 - Prob. 16T

Knowledge Booster

The center and radius of each circle of the following equation and rewrite in its standard form, x 2 + y 2 − 10 x + 12 y + 52 = 0

Solution Summary: The author explains how to calculate the center and radius of a circle using the following equation.

To calculate: The center and radius of each circle of the following equation and rewrite in its standard form, x2+y2−10x+12y+52=0

Want to see the full answer?

Chapter 9 Solutions