Explanation Given: The following function is given: y = tan x With N = 5 and the interval [ 0 , π 4 ] Formula Used: s = ∫ a b 1 + [ f ' ( x ) ] 2 d x … ( 1 ) Where s is the arc length over [ a , b ] for graph f ( x ) . Calculation: Consider the given equation y = tan x Now, differentiating it with respect to x , we get y ' = sec 2 x Now, 1 + [ f ' ( x ) ] 2 = 1 + [ y ' ] 2 = 1 + sec 4 x Now, from the equation (1), the arc length over the interval [ 0 , π 4 ] is: s = ∫ 0 π 4 1 + sec 4 x d x To calculate trapezoidal approximation T 5 , the subintervals will be: [ ( i &...

3rd Edition

ISBN: 9781464125263

Author: Jon Rogawski, Colin Adams

Publisher: W.H. Freeman & Co

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Chapter 9, Problem 6CRE

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The trapezoidal approximation $T_{5}$ to the arc length s of $y = \tan x$ over $[0, \frac{π}{4}]$ .

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Chapter 9, Problem 5CRE

Chapter 9, Problem 7CRE

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The trapezoidal approximation T 5 to the arc length s of y = tan x over [ 0 , π 4 ] .

Solution Summary: The author calculates the trapezoidal approximation T 5 to the arc length s of y = tan x over [ 0, 4 ].

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To calculate:

The trapezoidal approximation $T_{5}$ to the arc length s of $y = \tan x$ over $[0, \frac{π}{4}]$ .

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Chapter 9 Solutions

The trapezoidal approximation T 5 to the arc length s of y = tan x over [ 0 , π 4 ] .

Solution Summary: The author calculates the trapezoidal approximation T 5 to the arc length s of y = tan x over [ 0, 4 ].

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To calculate: The trapezoidal approximation T5 to the arc length s of y=tanx over [0,π4].

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Chapter 9 Solutions

To calculate:

The trapezoidal approximation $T_{5}$ to the arc length s of $y = \tan x$ over $[0, \frac{π}{4}]$ .