
Concept explainers
Pointer:
Pointer will allow the user to indirectly access and manipulate the variable data contents. A pointer variable will hold the address of the data contents. If an asterisk “*” operator is present before the variable then that variable is referred as pointer variable.
Consider the following statement:
//definition of pointer variable
int *ptrvar;
Here the variable “ptrvar” is defined to a pointer variable of integer data type. So, it can store the address of an integer variable.
Pointer to constant:
When an address of a constant item is passed to a pointer such that no modification can be made to that variables pointer to constants can be used.
Example:
//definition of pointer to constant variable
const int *ptr;
Explanation:
In the above definition, the variable “ptr” is declared as constant and any change made will not be accepted by the compiler.

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Chapter 9 Solutions
Starting Out with C++ from Control Structures to Objects Plus MyLab Programming with Pearson eText -- Access Card Package (9th Edition)
- Ensure you answer the question asked at the end of the document. Do not just paste things without the GNS3 console outputsarrow_forward"Do not use AI tools. Solve the problem by hand on paper only and upload a photo of your handwritten solution."arrow_forward"Do not use AI tools. Solve the problem by hand on paper only and upload a photo of your handwritten solution."arrow_forward
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- "Do not use AI tools. Solve the problem by hand on paper only and upload a photo of your handwritten solution."arrow_forward"Do not use AI tools. Solve the problem by hand on paper only and upload a photo of your handwritten solution."arrow_forwardSpecifications: Part-1Part-1: DescriptionIn this part of the lab you will build a single operation ALU. This ALU will implement a bitwise left rotation. Forthis lab assignment you are not allowed to use Digital's Arithmetic components.IF YOU ARE FOUND USING THEM, YOU WILL RECEIVE A ZERO FOR LAB2!The ALU you will be implementing consists of two 4-bit inputs (named inA and inB) and one 4-bit output (named out). Your ALU must rotate the bits in inA by the amount given by inB (i.e. 0-15).Part-1: User InterfaceYou are provided an interface file lab2_part1.dig; start Part-1 from this file.NOTE: You are not permitted to edit the content inside the dotted lines rectangle. Part-1: ExampleIn the figure above, the input values that we have selected to test are inA = {inA_3, inA_2, inA_1, inA_0} = {0, 1, 0,0} and inB = {inB_3, inB_2, inB_1, inB_0} = {0, 0, 1, 0}. Therefore, we must rotate the bus 0100 bitwise left by00102, or 2 in base 10, to get {0, 0, 0, 1}. Please note that a rotation left is…arrow_forward
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