Explanation Given data: Angular velocity of motorcycle turning counterclockwise is 7 , 700 rev min . Angular velocity of motorcycle increases to 12 , 500 rev min . Angular velocity of motorcycle turning clockwise is 3.8 rev min . Formula used: The expression for angular momentum is given by, L = I ω (1) Here, I is the moment of inertia and ω is the angular velocity. Calculation: As from the law of conservation of angular momentum, initial angular momentum is always equal with final momentum. That is, L initial = L final (2) The total angular momentum of the motorcycle is the sum of the angular momentum of the engine and the angular momentum of the rest of the motorcycle. Solving equation (1) and equation (2), I E ω E0 + I M ω M0 = I E ω Ef + I M ω Mf (3) Here, I E is the initial moment of inertia of the engine, ω E0 is the initial angular velocity of the engine, I E is the final moment of inertia of the engine, ω Ef is the final angular velocity of the engine, I M is the moment of inertia of motorcycle, ω Mf is the final angular velocity of the motorcycle, and ω M0 is the initial angular velocity of the motorcycle. At the starting the engine is only rotating and the motorcycle is at rest so it initial angular velocity of the motorcycle is zero. The clockwise rotation is taken as negative whereas counterclockwise rotation is taken to be positive. Substitute 7 , 700 rev min for ω E0 , − 3

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ISBN: 9781118836880

Author: John D. Cutnell, Kenneth W. Johnson

Publisher: WILEY

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Chapter 9, Problem 62P

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