Chapter 9, Problem 55A

To determine

(a)

What common fractional part of distance A is distance B.

Answer to Problem 55A

  $\frac{1}{4}$

Explanation of Solution

Given information:

A figure is given as below.

Calculation:

We have been given a figure as below.

From above figure we observe that,

Distance A $=10.00$ and distance B $=2.50$.

So, ratio of distance B to distance A $=\frac{2.50}{10.00}$

i.e. ratio of distance B to distance A $=\frac{\cancel{2.50}}{\cancel{2.50}\times 4}$

i.e. ratio of distance B to distance A $=\frac{1}{4}$

Hence, we can say that $\frac{1}{4}$ part of distance A is equal to distance B.

To determine

(b)

What common fractional part of distance A is distance C.

Answer to Problem 55A

  $\frac{9}{16}$

Explanation of Solution

Given information:

A figure is given as below.

Calculation:

We have been given a figure as below.

From above figure we observe that,

Distance A $=10.00$ and distance C $=5.625$.

So, ratio of distance C to distance A $=\frac{5.625}{10.00}$

i.e. ratio of distance C to distance A $=\frac{5.625}{10.00}\times \frac{1000}{1000}=\frac{5625}{10000}=\frac{9}{16}$

i.e. ratio of distance C to distance A $=\frac{9}{16}$

Hence, we can say that $\frac{9}{16}$ part of distance A is equal to distance C.

To determine

(c)

What common fractional part of distance A is distance D.

Answer to Problem 55A

  $\frac{1}{10}$

Explanation of Solution

Given information:

A figure is given as below.

Calculation:

We have been given a figure as below.

From above figure we observe that,

Distance A $=10.00$ and distance D $=1.00$.

So, ratio of distance D to distance A $=\frac{1.00}{10.00}$

i.e. ratio of distance D to distance A $=\frac{1.00}{10.00}\times \frac{100}{100}$

i.e. ratio of distance D to distance A $=\frac{1}{10}$

Hence, we can say that $\frac{1}{10}$ part of distance A is equal to distance D.

To determine

(d)

What common fractional part of distance A is distance E.

Answer to Problem 55A

  $\frac{3}{80}$

Explanation of Solution

Given information:

A figure is given as below.

Calculation:

We have been given a figure as below.

From above figure we observe that,

Distance A $=10.00$ and distance E $=0.375$.

So, ratio of distance E to distance A $=\frac{0.375}{10.00}$

i.e. ratio of distance E to distance A $=\frac{0.375}{10.00}\times \frac{1000}{1000}=\frac{375}{10000}$

i.e. ratio of distance E to distance A $=\frac{\cancel{125}\times 3}{\cancel{125}\times 80}=\frac{3}{80}$

Hence, we can say that $\frac{3}{80}$ part of distance A is equal to distance E.

To determine

(e)

What common fractional part of distance A is distance F.

Answer to Problem 55A

  $\frac{3}{8}$

Explanation of Solution

Given information:

A figure is given as below.

Calculation:

We have been given a figure as below.

From above figure we observe that,

Distance A $=10.00$ and distance F $=3.75$.

So, ratio of distance F to distance A $=\frac{3.75}{10.00}$

i.e. ratio of distance F to distance A $=\frac{3.75}{10.00}\times \frac{100}{100}=\frac{375}{1000}$

i.e. ratio of distance F to distance A $=\frac{\cancel{125}\times 3}{\cancel{125}\times 8}=\frac{3}{8}$

Hence, we can say that $\frac{3}{8}$ part of distance A is equal to distance F.