Explanation Given data: Angular velocity is 4.2 rad s . Mass of particle in rod A is 0.66 kg. Mass of rod B is 0.66 kg. Length of each rod is 0.75 m. Formula used: The expression of kinetic energy is given by, KE = 1 2 I ω 2 (1) Here, I is the moment of inertia and ω is the angular velocity. The expression for moment of inertia of a thin rod is given by, I = 1 3 M L 2 (2) Here, M is the mass of rod and L is the length of rod. Calculation: For rod A, Moment of inertia for rod A which has an attached particle is given as, I = M L 2 (3) Solving equation (1) and equation (3), KE A = 1 2 ( M L 2 ) ω 2 Substitute 0.66 kg for M , 0.75 m for L and 4.2 rad s for ω , KE A = 1 2 ( 0.66 kg × ( 0.75 m ) 2 ) ( 4.2 rad s ) 2 = 1 2 ( 0.66 kg × 0

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ISBN: 9781118486894

Author: David Young, Shane Stadler

Publisher: WILEY

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Chapter 9, Problem 50P

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The kinetic energy of rod A and of rod B.

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Chapter 9, Problem 49P

Chapter 9, Problem 51P

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Consider a rubber rod that has been rubbed with fur to give the rod a net negative charge, and a glass rod that has been rubbed with silk to give it a net positive charge. After being charged by contact by the fur and silk...? a. Both rods have less mass b. the rubber rod has more mass and the glass rod has less mass c. both rods have more mass d. the masses of both rods are unchanged e. the rubber rod has less mass and the glass rod has mroe mass

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