EBK INQUIRY INTO PHYSICS
EBK INQUIRY INTO PHYSICS
8th Edition
ISBN: 8220103599450
Author: Ostdiek
Publisher: Cengage Learning US
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Chapter 9, Problem 4C
To determine

(a)

The refractive index of the refraction for water and for fused silica.

Expert Solution
Check Mark

Answer to Problem 4C

The refractive index of the refraction for water and for fused silica are 1.33 and 1.46 respectively.

Explanation of Solution

Given:

Velocity of light in air, v=3×108m/s

Refractive index of air, nair=1

From table 9.1, the critical angle of water, A2=48.6°

The critical angle of fused silica, A3=43.2°.

Formula used:

The Snell’s law is given as

n1sinA1=n2sinA2

Here,

n1,n2 are the refractive index.

A1,A2 are the critical angle.

Calculation:

The refractive index of water is calculated as

n1sinA1=n2sinA2

Plugging the values in the above equation.

1sin90°=nwatersin48.6°nwater=1.33

The refractive index of fussed silica is calculated as

n1sinA1=n3sinA3

Plugging the values in the above equation.

1sin90°=nglasssin43.2°nglass=1.46.

Conclusion:

The refractive index of the refraction for water and for fused silica are 1.33 and 1.46 respectively.

To determine

(b)

What is the angle of refraction?

Expert Solution
Check Mark

Answer to Problem 4C

  • The angle of refraction is 36.38°.
  • The angle of refraction in part (b) of the given figure is 14.7°.
  • The angle of refraction in part (c) of the given figure is 30°.
  • The angle of refraction in part (d) of the given figure is 46.9°.
  • The angle of refraction in part (e) of the given figure is 90°.

Explanation of Solution

Given:

Refractive index of air, nair=1

Angle of incidence, θi=60°

Refractive index of glass, n2=1.46

The figure of light ray.

EBK INQUIRY INTO PHYSICS, Chapter 9, Problem 4C

Figure 1.

Formula used:

The Snell’s law is given as

n1sinA1=n2sinA2

Here,

n1,n2 are the refractive index

A1,A2 are the critical angle.

Calculation:

The angle of refraction is calculated as

n1sinA1=n2sinA2

Plugging the values in the above equation.

1sin60°=1.46sinA2A2=36.38°

The angle of refraction in part (b) of the figure is calculated as

n3sinA3=n1sinA1

Plugging the values in the above equation.

1.46sin10°=1×sinA2A2=14.7°

The angle of refraction in part (c) of the figure is calculated as

n3sinA3=n1sinA1

Plugging the values in the above equation.

1.46sin20°=1×sinA2A2=30°

The angle of refraction in part (d) of the figure is calculated as

n3sinA3=n1sinA1

Plugging the values in the above equation

1.46sin30°=1×sinA2A2=46.9°

The angle of refraction in part (e) of the figure is calculated as

n3sinA3=n1sinA1

Plugging the values in the above equation.

1.46sin43°=1×sinA2A2=90°.

Conclusion:

  • The angle of refraction is 36.38°.
  • The angle of refraction in part (b) of the given figure is 14.7°.
  • The angle of refraction in part (c) of the given figure is 30°.
  • The angle of refraction in part (d) of the given figure is 46.9°.
  • The angle of refraction in part (e) of the given figure is 90°

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Chapter 9 Solutions

EBK INQUIRY INTO PHYSICS

Ch. 9 - Prob. 5QCh. 9 - Prob. 6QCh. 9 - Prob. 7QCh. 9 - Prob. 8QCh. 9 - Prob. 9QCh. 9 - Prob. 10QCh. 9 - Prob. 11QCh. 9 - (Indicates a review question, which means it...Ch. 9 - (Indicates a review question, which means it...Ch. 9 - (Indicates a review question, which means it...Ch. 9 - Prob. 15QCh. 9 - Prob. 16QCh. 9 - (Indicates a review question, which means it...Ch. 9 - (Indicates a review question, which means it...Ch. 9 - (Indicates a review question, which means it...Ch. 9 - Prob. 20QCh. 9 - Prob. 21QCh. 9 - Prob. 22QCh. 9 - Prob. 23QCh. 9 - Prob. 24QCh. 9 - Prob. 25QCh. 9 - Prob. 26QCh. 9 - Prob. 27QCh. 9 - (Indicates a review question, which means it...Ch. 9 - Prob. 29QCh. 9 - Prob. 30QCh. 9 - Prob. 31QCh. 9 - Prob. 32QCh. 9 - Prob. 33QCh. 9 - (Indicates a review question, which means it...Ch. 9 - Prob. 35QCh. 9 - Prob. 36QCh. 9 - Prob. 37QCh. 9 - (Indicates a review question, which means it...Ch. 9 - Prob. 39QCh. 9 - Prob. 40QCh. 9 - Prob. 41QCh. 9 - (Indicates a review question, which means it...Ch. 9 - Prob. 43QCh. 9 - Prob. 44QCh. 9 - Prob. 45QCh. 9 - Prob. 46QCh. 9 - Prob. 47QCh. 9 - Prob. 48QCh. 9 - Prob. 49QCh. 9 - Prob. 50QCh. 9 - Prob. 51QCh. 9 - Prob. 52QCh. 9 - Prob. 53QCh. 9 - Prob. 54QCh. 9 - Prob. 55QCh. 9 - Prob. 56QCh. 9 - Prob. 57QCh. 9 - Prob. 58QCh. 9 - Prob. 59QCh. 9 - Prob. 60QCh. 9 - Suppose a beam of red light from an He-Ne laser...Ch. 9 - In a double-slit interference experiment, a...Ch. 9 - A light ray traveling in air strikes the surface...Ch. 9 - A ray of yellow light crosses the boundary between...Ch. 9 - Prob. 5PCh. 9 - A fish looks up toward the surface of a pond and...Ch. 9 - A camera is equipped with a lens with a focal...Ch. 9 - A 2.0-cm-tall object stands in front of a...Ch. 9 - When viewed through a magnifying glass, a stamp...Ch. 9 - . A person looks at a statue that is 2 m tall. The...Ch. 9 - Prob. 11PCh. 9 - . A small object is placed to the left of a convex...Ch. 9 - . If the object in Problem 12 is moved toward the...Ch. 9 - . (a) In a camera equipped with a 50-mm...Ch. 9 - . The focal length of a diverging lens is...Ch. 9 - . The equation connecting s, p, and f for a simple...Ch. 9 - . If the mirror described in the previous problem...Ch. 9 - Prob. 18PCh. 9 - Prob. 19PCh. 9 - Prob. 1CCh. 9 - In Section 9.6, we described how the speed of...Ch. 9 - Would the critical angle for a glass—water...Ch. 9 - Prob. 4CCh. 9 - Prob. 5CCh. 9 - Prob. 6CCh. 9 - Prob. 7CCh. 9 - Prob. 8CCh. 9 - Prob. 9CCh. 9 - Prob. 10C
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