Explanation Given: Young’s Modulus, E = 2 × 10 5 N/m 2 Area, A = 0.50 cm 2 Thickness, l = 3 mm Formula Used: Young's modulus is given by ratio of stress to strain. E = F / A δ l / l δ l = F L A E ............... ( 1 ) Where E is the Young’s modulus, F is applied force, A is area of cross section, l is the original length, and δ l is the change in length. Calculations: F = k δ l δ l = F k ............. ( 2 ) Potential energy is given by P E = 1 2 k δ l 2 From 1 and 2 k = A E L k = 5

7th Edition

ISBN: 2818440037979

Author: GIANCOLI

Publisher: PEARSON

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Chapter 9, Problem 49P

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